I have this part of code working fine:
$array_stats_raw = $db->query($query);
$array_statistics[$name] = $array_stats_raw->fetchArray(SQLITE3_ASSOC);
However I have many different queries that I have to pass in the same code so I am trying to put it in a function and call the function instead of repeating this code many times.
I tried the following:
function sqlite_query123($dbhandle,$query1,$name)
{
$result = $dbhandle->query($query1);
$result1[$name] = $result->fetchArray(SQLITE3_ASSOC);
return $result1;
}
$array_statistics[$name] = sqlite_query123($db, $query, $name);
What am I doing wrong? Sorry for asking a novice question but I feel like I am missing something simple and can't figure it out what?
Incase it is not a typo in the question, you misspelt $result as $results :
function sqlite_query123($dbhandle,$query1,$name)
{
$result = $dbhandle->query($query1);
$result1[$name] = $result->fetchArray(SQLITE3_ASSOC);
return $result1;
}
UPDATE :
Try this
function sqlite_query123($dbhandle,$query1,$name)
{
$result = $dbhandle->query($query1);
return $result->fetchArray(SQLITE3_ASSOC);
}
The following also worked:
function sqlite_query123($dbhandle,$query1,$name)
{
$result = $dbhandle->query($query1);
$result1[$name] = $result->fetchArray(SQLITE3_ASSOC);
return $result1[name];
}
Related
public function subchapt()
{
$result = $this->recursive_subchapter_id($level_title);
}
public function recursive_subchapter_id($level_title)
{
$level_data = $this->db->query("SELECT * FROM presto_project_level WHERE level_title ='". $level_title."'")->result_array();
if(count($level_data)>0){
$parentid1 = '';
$leveltitle1 = '';
$parentid1 = trim($level_data[0]['parent_id']);
$leveltitle1 = trim($level_data[0]['level_title']);
if($parentid1 == '0') {
return $leveltitle1;die;
}
else
{
$res = $this->recursive_subchapter_id($parentid1);
return $res;die;
}
}
else{
return $level_title;die;
}
}
every time getting result array is null. i tried directly in url so it was give result array and its count. but while call from other function it was give count of zero.
instead of checking the parentid in the recursive_subchapter_id(), check in subchapt() and then call again recursive_subchapter_id() if it not satisfy the condition.
I want to get query result from my model and use it in view. I don't know why but my result is empty. Can you look at this and tell me what I'm doing wrong?
Controller:
$peugeot = $this->input->post('peugeot');
$citroen = $this->input->post('Citroen C-Elysee');
$nissan= $this->input->post('Nissan Evalia');
$renault = $this->input->post('Renault Trafic 9-os');
$this->load->model('Edit_model');
$this->Edit_model->peugeot($peugeot);
if($peugeot)
{
$result = $this->Edit_model->peugeot($peugeot);
$data['result'] = $result;
}
Model:
public function peugeot($peugeot)
{
$this->db->like('model', $peugeot, 'after');
$query = $this->db->get('cars');
$result = $query->result();
return $result;
}
View:
if($peugeot)
{
print_r($result);
}
Kinda strange, but It works
I've changed my controller into this
$data['peugeot'] = $this->input->post('peugeot');
$data['citroen'] = $this->input->post('citroen');
$data['nissan'] = $this->input->post('nissan');
$data['renault'] = $this->input->post('renault');
$this->load->model('Edit_model');
if($data['peugeot'])
{
$this->Edit_model->peugeot($data['peugeot']);
$result = $this->Edit_model->peugeot($data['peugeot']);
$data['result'] = $result;
$this->load->view('content/editprocess',$data);
}
I am trying to display records using PDO LIKE query, but I am getting this error message can I know how to solve this.
This is my code:
$rs = new JSONRecordSet();
$searchbooksSQL = "SELECT Title FROM l_stock WHERE Title LIKE ?";
$params = array("%$term%");
echo $rs->getRecordSet($searchbooksSQL, $params);
This is the getRecordSet code:
class R_RecordSet {
function getRecordSet($sql, $params = null) {
if (is_array($params)) {
$this->stmt = $this->db->prepare($sql);
// execute the statement passing in the named placeholder and the value it'll have
$this->stmt->execute($params);
} else {
$this->stmt = $this->db->query($sql);
}
return $this->stmt;
}
}
class JSONRecordSet extends R_RecordSet {
function getRecordSet($sql, $elementName = "ResultSet", $params = null) {
$stmt = parent::getRecordSet($sql, $params);
$recordSet = $stmt->fetchAll(PDO::FETCH_ASSOC);
$nRecords = count($recordSet);
if ($nRecords == 0) {
$status = 'error';
$message = json_encode(array("text" => "No records found"));
$result = '[]';
} else {
$status = 'ok';
$message = json_encode(array("text" => ""));
$result = json_encode($recordSet);
}
return "{\"status\": \"$status\", \"message\":$message, \"$elementName\" :{\"RowCount\": $nRecords ,\"Result\": $result}}";
}
}
The error message i am getting is "Notice: Array to string conversion"
getRecordSet() is defined as:
function getRecordSet($sql, $elementName = "ResultSet", $params = null) {
however, you are calling it as:
echo $rs->getRecordSet($searchbooksSQL, $params);
You will need to modify your code to pass in an appropriate $elementName parameter. (The default is probably reasonable.)
echo $rs->getRecordSet($searchbooksSQL, 'ResultSet', $params);
Additionally, you should probably use json_encode() to generate the final result from JSONRecordSet::getRecordSet(), rather than building it up with string concatenation. It will make the code easier to read and understand.
Also, your two implementations of getRecordSet() are incompatible with each other, according to the Liskov Substitution Principle due to the change in the semantics of the input parameters, and is likely what led you to the parameter mismatch at your call site in the first place. You probably want to re-order JSONRecordSet::getRecordSet() parameters to:
function getRecordSet($sql, $params = null, $elementName = 'ResultSet') {
I am having trouble getting two tables and passing them to controller:
IN A MODEL:
function get_all_entries() {
$query = $this->db->get('entry');
return $query->result();
$this->db->select('entry_id , count(comment_id) as total_comment');
$this->db->group_by('entry_id');
$comment = $this->db->get('comment');
return $comment->result();
}
IN A CONTROLLER:
$data['query'] = $this->blog_model->get_all_entries();
$this->load->view('blog/index',$data);
How do I return $query and $comment variables to controller? I think I am doing it wrong.
Use this because you are not allowed to return twice in the same method
function get_all_entries()
{
$query = $this->db->get('entry');
$data[] = $query->result();
$this->db->select('entry_id , count(comment_id) as total_comment');
$this->db->group_by('entry_id');
$comment = $this->db->get('comment');
$data[] = $comment->result();
return $data;
}
EDITS:
In controller
function index(){
$this->load->model('mymodel');
$result = $this->mymodel->get_all_entries();
$entries = $result[0] ;
$comments = $result[1] ;
$data['entries'] = $entries;
$data['comments '] = $comments;
}
Your issue is that you're returning $query->result() in first place, return function halts the current function, so the next steps are not being processed.
Best way would be to create two methods for either $query get and $comment get.
An alternative to your issue would be
function get_all_entries() {
$query = $this->db->get('entry');
$this->db->select('entry_id , count(comment_id) as total_comment');
$this->db->group_by('entry_id');
$comment = $this->db->get('comment');
return array($query->result(),$comment->result());
}
Then in your controller
list($data['query'],$data['comment']) = $this->blog_model->get_all_entries();
$this->load->view('blog/index',$data);
Im trying to get an max value with codeigniter from an table but it isnt working. This is the error i get:
Severity: 4096
Message: Object of class CI_DB_mysql_result could not be converted to
string
Filename: database/DB_active_rec.php
Line Number: 427
This is my function:
public function getPeriodeNummer($bedrijf_id) {
$this->db->select_max('id');
$this->db->where('bedrijf_id', $bedrijf_id);
$result = $this->db->get('rapporten');
$this->db->select('periode_nummer');
$this->db->where('rapporten_id', $result);
$query = $this->db->get('statistieken_onderhoud');
$data = $query + 1;
return $data;
}
What im trying to do is as followed:
Select the highest id where bedrijf_id = $bedrijf_id from rapporten.
Select the periode_nummer from statistieken_onderhoud where rapporten_id = the highest id i got from step 1.
Add 1 to the periode_nummer i got from step 2 and return that number.
Thanks in forward for your help!
Try
public function getPeriodeNummer($bedrijf_id) {
$this->db->select_max('id');
$this->db->where('bedrijf_id', $bedrijf_id);
$res1 = $this->db->get('rapporten');
if ($res1->num_rows() > 0)
{
$res2 = $res1->result_array();
$result = $res2[0]['id'];
$this->db->select('periode_nummer');
$this->db->where('rapporten_id', $result);
$query = $this->db->get('statistieken_onderhoud');
if ($query->num_rows() > 0)
{
$row = $query->result_array();
$data['query'] = 1 + $row[0]['periode_nummer'];
}
return $data['query'];
}
return NULL;
}
Try this:
$this->db->select_max('display_sequence');
$this->db->from('acl_menu');
$query = $this->db->get();
$r=$query->result();
Display Sequence is your column name & acl_menu is your table name.
You can't use an object as a string. Use this:
public function getPeriodeNummer($bedrijf_id) {
$this->db->select_max('id');
$this->db->where('bedrijf_id', $bedrijf_id);
$result = $this->db->get('rapporten');
$this->db->select('periode_nummer');
$this->db->where('rapporten_id', $result);
$query = $this->db->get('statistieken_onderhoud');
// fetch first row in object
$result = $query->row();
$data = $result + 1;
return $data;
}
$this->db->select_max('id', 'max_id');
$query = $this->db->get('video_processing');
return $query->row();
try the above:
I think the $query variable is holding a mysql result resource and it cannot be used as a String or in this case an Integer.
You could try this way:
$data = mysql_result($query,0) + 1;
Shortest:
$this->db->select_max('id', 'max_id')->get('video_processing')->row();