php script was working, now second $_POST suddenly not working - php

Question

I am fairly new to php and have been searching for three days to find my problem. The script below worked for two years, and now suddenly the second POST command never populates (it is the last lines of code, and when I echo $_POST['input']; nothing is ever there.) I have looked at var_dump$[_$POST] and it gets $formType, but never $input.
Why would this suddenly stop working? It goes to the next form, but nothing works because it all counts on $input being passed on.
I am running on a unix server, Network Solutions.
Any help is greatly appreciated!!
here is the code (sanitized names of directories and databases, obviously):
<?php
session_start();
if ($_SESSION['auth'] != "yes") {
header("Location: login.php");
exit();
}
if (isset($_REQUEST['Enter'])) {
header("Location: http://www.mysite.com/subdirectory/nextform.php");
} else if (isset($_REQUEST['Delete'])) {
header("Location: http://www.mysite.com/subdirectory/deleterow.php");
}
########################################
####checks what kind of service request######
#########################################
?>
<form name="form" method="post" action="<?php
echo htmlentities($_SERVER['PHP_SELF']);
?>">
<p><legend>Form Type</legend></p>
<p> <basefont size = "4"></p>
<p><label for="formType" required>*Select Type of Form:</label></p>
<p><select name="formType"></p>
<p><option value="">select</option></p>
<p><option value="Garda">Security Officer</option></p>
<p><option value="Surveil">Surveil</option></p>
<p><option value="EmployApp">Employment Application</option></p>
<p></select></p>
<p><input type="submit" name="Submit" value="Submit" /></p>
</form>
<?php
$formType = $_POST['formType'];
SESSION_register("formType");
if ($formType == Garda) {
// Connects to your Database
include("introGardaform.php");
$database = "Gardaform"; // provide your database name
$db_table = "GardaINQ"; // leave this as is
$db = mysql_connect($hostname, $db_user, $db_password);
mysql_select_db($database, $db);
$data = mysql_query("SELECT * FROM GardaINQ") or die(mysql_error());
// puts the "GardaINQ"database table info into the $info array
//$info = mysql_fetch_array( $data );
Print "<table border cellpadding=15>";
while ($info = mysql_fetch_array($data)) {
Print "<tr>";
Print "<th>Inquiry Number:</th> <td>" . $info['Inquiry_num'] . "</td> ";
Print "<th>Contact Name:</th> <td>" . $info['contactName'] . " </td>";
Print "<th>Contact Number:</th> <td>" . $info['contactNum'] . " </td></tr>";
}
Print "</table>";
}
if ($formType == Surveil) {
// Connects to your Database
include("investfm.php");
$database = "investigateform"; // provide your database name
$db_table = "surveil"; // leave this as is
$db = mysql_connect($hostname, $db_user, $db_password);
mysql_select_db($database, $db);
$data = mysql_query("SELECT * FROM surveil") or die(mysql_error());
// puts the "surveil"database table info into the $info array
//$info = mysql_fetch_array( $data );
Print "<table border cellpadding=15>";
while ($info = mysql_fetch_array($data)) {
Print "<tr>";
Print "<th>Inquiry Number:</th> <td>" . $info['Inquiry_num'] . "</td> ";
Print "<th>Contact Name:</th> <td>" . $info['contactName'] . " </td>";
Print "<th>Contact Number:</th> <td>" . $info['contactNum'] . " </td></tr>";
}
Print "</table>";
}
if ($formType == EmployApp) {
// Connects to your Database
include("introhires.php");
$database = "hires"; // provide your database name
$db_table = "hiresentry"; // leave this as is
$db = mysql_connect($hostname, $db_user, $db_password);
mysql_select_db($database, $db);
$data = mysql_query("SELECT * FROM hiresentry") or die(mysql_error());
// puts the "hiresentry"database table info into the $info array
//$info = mysql_fetch_array( $data );
Print "<table border cellpadding=15>";
while ($info = mysql_fetch_array($data)) {
Print "<tr>";
Print "<th>First Name:</th> <td>" . $info['firstName'] . " </td>";
Print "<th>Last Name:</th> <td>" . $info['lastName'] . " </td>";
Print "<th>Date:</th> <td>" . $info['date'] . " </td></tr>";
}
Print "</table>";
}
?>
<form name="finddata" method="POST" action="<?php
echo htmlentities($_SERVER['PHP_SELF']);
?>">
<p> <basefont size = "4"></p>
<p><label for="finddata" required>Enter Inquiry Number for Garda or Surveil, Last name for Employment
Application:</label></p>
<p><input type = "text" size="20" maxlength="40" required onKeyPress="return noenter()"
name="input"></p>
<p><input type="hidden" value="<?php
echo $formType;
?>" name="formType"></p>
<p><input type="submit" name="Enter" value="Enter" ></p><br/>
<p><input type="submit" style="font-face: 'Comic Sans MS'; font-size: larger; color: red; background-color: #FFFFC0; border: 3pt ridge lightgrey" name = "Delete" value="Delete"></p>
</form>
<?php
$input = $_POST['input'];
SESSION_register("input");
echo $_POST['input'];
?>

Answer 1

You have used SESSION_register("formType"); undefined function and This function has been DEPRECATED as of PHP 5.3.0 and REMOVED as of PHP 5.4.0.
So you can use $_SESSION["formType"]=$formType;, also
Need to wrap " or ' to check the string. Try this,
if($formType=="Garda"){
and if($formType=="EmployApp"){
instead of
if($formType==Garda){
if($formType==EmployApp){

Answer 2

You have a lot of issues on your code.
You are comparing your $formtype variable to a constant instead. It has to be like this. if($formType=="Garda"){ and if($formType=="Surveil"){ and if($formType=="EmployApp"){ add the double quotes to all those if statements as shown.
You are using a deprecated version i.e. session_register

Answer 3

can you try the following:
Remove the action attribute completely from both the forms as by default it is POST to self.
replace the font-face css property to font-family property in the last element of the second form. however that should not be the cause of the issue you are facing.
As there are 2 forms in the page and there are 2 code blocks depending on the form post, I assume that your second form post creates the issue in the first part of the code as the data for the first from will not be posted from the submit button in the second form. so before executing the piece of code you should identify if that piece of code should be executed or not. A simple multi form setup should look something like this:
<form name="form1" method="post">
<input type="text"/>
<input type="submit" name="form1-submit" value="Submit Name" />
</form>
<!-- form1 specific code -->
<?php
if(isset($_POST["form1-submit"]))
{
// do your stuff here
}
?>
<form name="form2" method="post">
<input type="text"/>
<input type="submit" name="form2-submit" value="Submit Name" />
</form>
<!-- form2 specific code -->
<?php
if(isset($_POST["form2-submit"]))
{
// do your stuff here
}
?>
<!-- independent code -->
<?php
// do your common code here.
?>
If you can write the code in above manner you will be able to resolve your problem yourself. please let us know in case above helped.