I have a server running on Linux that execute commands to 12 nodes (12 computers with Linux running in them). I recently downloaded PHP on the server to create web pages that can execute commands by opening a specific PHP file.
I used exec(), passthru(), shell_​exec(), and system(). system() is the only one that returns a part of my code. I would like PHP to act like open termainal command in linux and I cannot figure out how to do it!
Here is an example of what is happening now (Linux directly vs PHP):
When using linux open terminal command directly:
user#wizard:/home/hyperwall/Desktop> /usr/local/bin/chbg -mt
I get an output:
The following settings will be used:
option = mtsu COLOR = IMAGE = imagehereyouknow!
NODES = LOCAL
and additional code to send it to 12 nodes.
Now with PHP:
switch($_REQUEST['do'])
{ case 'test':
echo system('/usr/local/bin/chbg -mt');
break;
}
Output:
The following settings will be used:
option = mtsu COLOR = IMAGE = imagehereyouknow!
NODES = LOCAL
And stops! Anyone has an explanation of what is happening? And how to fix it? Only system displays part of the code the other functions display nothing!
My First thought is it can be something about std and output error. Some softwares dump some informations on std out and some in std error. When you are not redirecting std error to std out, most of the system calls only returns the stdout part. It sounds thats why you see the whole output in terminal and can't in the system calls.
So try with
/usr/local/bin/chbg -mt 2>&1
Edit:
Also for a temporary work through, you can try some other things. For example redirect the output to file next to the script and read its contents after executing the command, This way you can use the exec:
exec("usr/local/bin/chbg -mt 2>&1 > chbg_out");
//Then start reading chbg_out and see is it work
Edit2
Also it does not make sense why others not working for you.
For example this piece of code written in c, dumps a string in stderr and there is other in stdout.
#include <stdio.h>
#include<stdlib.h>
int main()
{
fputs("\nerr\nrro\nrrr\n",stderr);
fputs("\nou\nuu\nuttt\n",stdout);
return 0;
}
and this php script, tries to run that via exec:
<?php
exec("/tmp/ctest",&$result);
foreach ( $result as $v )
{
echo $v;
}
#output ouuuuttt
?>
See it still dumps out the stdout. But it did not receive the stderr.
Now consider this:
<?php
exec("/tmp/ctest 2>&1",&$result);
foreach ( $result as $v )
{
echo $v;
}
//output: errrrorrrouuuuttt
?>
See, this time we got the whole outputs.
This time the system:
<?php
echo system("/tmp/ctest 2>&1");
//output: err rro rrr ou uu uttt uttt
?>
and so on ...
Maybe your chbg -mt writes additional code to stderr instead of stdout? Try to execute your script inside php like this:
/usr/local/bin/chbg -mt 2>&1
The other responses are good for generic advice. But in this specific case, it appears you are trying to change your background on your desktop. This requires many special considerations because of 'user context':
First, your web server is probably running as a different user, and therefore would not have permissions to change your desktop.
Second, the program probably requires some environmental variables from your user context. For example, X programs need a DISPLAY variable, ssh-agent needs SSH_AGENT_PID and SSH_AUTH_SOCK, etc. I don't know much about changing backgrounds, but I'm guessing it involves D-Bus, which probably requires things like DBUS_SESSION_BUS_ADDRESS, KONSOLE_DBUS_SERVICE, KONSOLE_DBUS_SESSION, and KONSOLE_DBUS_WINDOW. There may be many others. Note that some of these vars change every time you log in, so you can't hard-code them on the PHP side.
For testing, it might be simpler to start your own webserver right from your user session. (i.e. Don't use the system one, it has to run as you. You will need to run it on an alternate port, like 8080). The web server you start manually will have all the 'context' it needs. I'll mention websocketd because it just came out and looks neat.
For "production", you may need to run a daemon in your user context all the time, and have the web server talk to that daemon to 'get stuff done' inside your user context.
PHP's system only returns the last line of execution:
Return Value: Returns the last line of the command output on success, and FALSE on failure.
You will most likely want to use either exec or passthru. exec has an optional parameter to put the output into an array. You could implode the output and use that to echo it.
switch($_REQUEST['do'])
{ case 'test':
exec('/usr/local/bin/chbg -mt', $output);
echo implode('\n', $output); // Could use <br /> if HTML output is desired
break;
}
I think that the result of execution, can changes between users.
First, try to run your PHP script directly into your terminal php yourScript.php
If it runs as expected, go to your Apache service and update it to run with your own credentials
You are trying to change the backgrounds for currently logged in users... While they are using the desktop. Like while I'm typing this message. I minimize my browser and 'ooh my desktop background is different'. Hopefully this is for something important like it turns red when the reactor or overheating.
Anyway to my answer:
Instead of trying to remotely connect and run items as the individual users. Setup each user to run a bash script (in their own account, in their own shell) on a repeating timer. Say every 10 minutes. Have it select the SAME file.. from a network location
/somenetworkshare/backgrounds/images/current.png
Then you can update ALL nodes (1 to a million) just by changing the image itself in /somenetworkshare/backgrounds/images/current.png
I wrote something a while ago that does just this -- you can run a command interpreter (/bin/sh), send it commands, read back responses, send more commands, etc. It uses proc_open() to open a child process and talk to it.
It's at http://github.com/andrasq/quicklib, Quick/Proc/Process.php
Using it would look something like (easier if you have a flexible autoloader; I wrote one of those too in Quicklib):
include 'lib/Quick/Proc/Exception.php';
include 'lib/Quick/Proc/Exists.php';
include 'lib/Quick/Proc/Process.php';
$proc = new Quick_Proc_Process("/bin/sh");
$proc->putInput("pwd\n");
$lines = $proc->getOutputLines($nlines = 10, $timeoutSec = 0.2);
echo $lines[0];
$proc->putInput("date\n");
$lines = $proc->getOutputLines(1, 0.2);
echo $lines[0];
Outputs
/home/andras/quicklib
Sat Feb 21 01:50:39 EST 2015
The unit of communication between php and the process is newline terminated lines. All commands must be newline terminated, and all responses are retrieved in units of lines. Don't forget the newlines, they're hard to identify afterward.
I am working on a project that uses Terminal A on machine A to output to Terminal B on Machine B, both using linux for now. I didnt see it mentioned, but perhaps you can use redirection, something like this in your webserver:
switch($_REQUEST['do'])
{ case 'test':
#process ID on the target (12345, 12346 etc)
echo system('/usr/local/bin/chbg -mt > /proc/<processID>/fd/1');
#OR
#device file on the target (pts/0,tty0, etc)
echo system('/usr/local/bin/chbg -mt > /dev/<TTY-TYPE>/<TTYNUM>');
break;
}
Definitely the permissions need to be set correctly for this to work. The command "mesg y" in a terminal may also assist...Hope that helps.
I use PHP for edit code LUA, change and save file. I can execute the file, but I can not use show if I have error, as console.
example:
my code lua:
print "hello"
and code php:
<?php
$output = passthru("sudo /usr/local/bin/lua /var/www/test.lua");
//show output
echo "<pre>$output</pre>";
?>
this work, but I can show errors (console), if code has.
i think use the code io.stdin or io.stdout in lua
thanks
See this comment: http://php.net/manual/en/function.passthru.php#101148
When Lua fails and responds with an error, passthrough can't capture the result, even though I get the STDERR text without any problems, you may, as suggested in the comment, try piping the Lua result to tee program.
$output = passthru("sudo /usr/local/bin/lua /var/www/test.lua | tee");
Here's the issue:
I am using R to run some statistical analysis. The results of which will eventually be sent to a an embedded swf on the user's client machine.
To do this, I have PHP execute a shell script to run the R program, and I want to retrieve the results of that program so I can parse them in PHP and respond with the appropriate data.
So, it's simply:
$output = shell_exec("R CMD BATCH /home/bitnami/r_script.R");
echo $output;
But, I receive nothing of course, because R CMD BATCH writes to a file. I've tried redirecting the output in a manner similar to this question which changes my script to
$output = shell_exec('R CMD BATCH /home/bitnami/raschPL.R /dev/tty');
echo $output;
But what I get on the console is a huge spillout of the source code, and nothing is echoed.
I've also tried this question's solution in my R script.
tl;dr; I need to retrieve the results of an R script in PHP.
Cheers!
If it writes to file perhaps you could use file_get_contents to read it?
http://php.net/manual/en/function.file-get-contents.php
Found it, the answer is through Rscript. Rscript should be included in the latest install of R.
Using my code as an example, I would enter this at the very top of r_script.R
#!/usr/bin/Rscript --options-you-need
This should be the path to your Rscript executable. This can be found easily by typing
which Rscript
in the terminal. Where I have --options-you-need, place the options you would normally have when doing the CMD BATCH, such as --slave to remove extraneous output.
You should now be able to run your script like so:
./r_script.R arg1 arg2
Important! If you get the error
Error in `contrasts<-`(`*tmp*`, value = "contr.treatment") :
could not find function "is"
You need to include the "methods" package, like so:
require("methods");
Perhaps,a much simpler workaround, would be:
$output = shell_exec('R CMD BATCH /home/bitnami/raschPL.R > /dev/tty 2>&1');
echo $output;
Redirects both STDOUT and STDERR, since R outputs to STDERR, by default.
I have a C program which has been compiled to an executable. I can run this program from my console. I am trying to get the output from this program through my web browser so I am using the exec command in PHP. My PHP script works fine when I execute it from the command line, but when I call it over a browser I get no input. Here is my PHP program
<?php
echo exec('/var/www/html/./readcard');
?>
The readcard program has 777 permissions. I am guess the issue is something to do with permissions?
You aren't capturing the output. The second argument to exec consists of an array to which the output lines will be placed.
<?php
$output=array();
$rv=0;
exec('/var/www/html/./readcard',$output,$rv);
if($rv!=0)
{
die("readcard failed, got a return value of $rv\n");
}
foreach($output as $line)
{
echo("<p>$line</p>\n");
}
?>
You probably just echo the return code of the script, which is zero. You can either redirect the output to a file and then serve that from php, or pipe the output stream directly back to php code.
Try
<?php
$output = array();
exec('/var/www/html/./readcard', &$output);
?>
I am using red hat enterprise edition n try making a simple php page..
When I try with ...
// html code
<?php
echo exec(<cmd>);
?>
// rest html code
Its working fine
but when tried with ...
// html code
<?php
exec(<cmd>);
?>
// rest html code
Its not working
even a simple command like cat,ls,etc not working and also I tried 2 > &1 then no error is printed .
What could be the possible error ???
Docs:
http://php.net/manual/en/function.exec.php
return a response from the command, you would need to print the response out as well
Example:
<?php
$response = array();
exec('whoami', $response);
print_r($response,true);
?>
okkkkkkk ......... I solved the problem. Actually there were two issues ...
The apache user searches its command in /usr/bin folder by default and the command I was trying to use was located in /usr/local/bin. So I need to create a soft link of that command in the /usr/bin directory.
Secondly , apache is a less privilaged user than root so need to on the sticky bit of command so that apache could successfully run the command.
I hope this will help someone else also who will face the same problem in future.