I'm not very familiar with PHP and have been trying my hardest to figure out how to create this URL. So far, this is working:
<?php echo site_url($p->post_title) ?>
Where post title is defined by the Mapify.it Wordpress plugin. The result is:
http://siteurl.com/post_title
What I'd like to do is add a string before it, ideally ?s= or /search/, but when I try to add this before $p->post_title I'm still generating the above URL. Variations such as:
<?php echo site_url('?s=', $p->post_title) ?>
<?php echo site_url('/search/', $p->post_title) ?>
produce http://siteurl.com/?s= and ignore the variable. Nothing seems to do what I want.
What am I doing wrong?
Hope you need the following url format,
http://siteurl.com/?s=Here come the post title
So,
<?php echo site_url("?s=".$p->post_title) ?>
OR
<?php echo site_url("/search/".$p->post_title) ?>
should work.
Found it!
<?php echo site_url('?s='), $p->post_title ?>
Instead of adding custom URL Parameters directly, I'd suggest you to use WordPress built-in function add_query_arg(), it's more cleaner.
Here is an usage example:
$url = get_site_url();
$params = array(
's' => $p->post_title
);
echo add_query_arg($params, $url);
You can specify multiple parameters this way.
For ref: Check add_query_arg()
Related
This is my "code":
function whoop_function(){
return "whoop whoop!";
}
add_shortcode('whoop', 'whoop_function' );
Now when I want to use it in a post, all I get is:
[whoop]
As you can see I am very new and unused to it so maybe the answer is really simple, maybe I've just miss a thing in advance.
I both checked defining the function in functions.php and also in content.php
For shortcode function echo is required.
Please check with below code
function whoop_function(){
$responseData = "whoop whoop!";
echo $responseData;
return true;
}
add_shortcode('whoop', 'whoop_function' );
put your code in themes/function.php files and remove from content.php as function is duplicated so function already defined PHP error occurred.
function whoop_function(){
return "whoop whoop!";
}
add_shortcode('whoop', 'whoop_function' );
and add your shortcode [whoop] in any page content section.
if u use do_shortcode('[whoop]'); then echo it like below.
<?php echo do_shortcode('[whoop]'); ?>
Your approach is correct. I think you are using it in a template. Just need to use it as mentioned below :
In files:
<?php echo do_shortcode('[whoop]'); ?>
In admin pages or posts:
[whoop]
Fetch the content like this:
$post_content = get_post(get_id_by_slug('short')); // assuming that you have already defined get_id_by_slug function as you are using it in your code and "short" is a slug for post you are fetching content
$content = $post_content->post_content;
echo do_shortcode( $content );
You are fetching content without considering the short code. Update your code as above.
Hope it will work for you.
I have a shortcode in a theme that displays only when a user is logged out. Usually, I would use the following shortcode to achieve this
[logged_out]Content[/logged_out]
How would I achieve this in PHP?
<?php echo do_shortcode("[logged_out]"); ?>
Can you just try the code like below,
<?php
$string = 'Hello world';
echo do_shortcode('[logged_out]'.$string.'[/logged_out]');
?>
you can assign any value to the variable $string ;
Or you can directly use like this,
<?php
echo do_shortcode('[logged_out]Hello world[/logged_out]');
?>
For more information please refer,
https://developer.wordpress.org/reference/functions/do_shortcode/
you can use following way in your php file.
echo do_shortcode('[logged_out] your content [/logged_out]');
I'm a little lost here, hoping that someone can help. I'm using the Meta Box plugin for WordPress, and I'm trying to create a process for the user to select an option from a predefined list, and then assign a URL to that option as a link. Im trying to define the URL in a variable, and then call it in a function, but I'm still a little green on PHP syntax. this is my code now:
<?php
$article_url= rwmb_meta('orion_2016_article_url', 'type=URL');
if (rwmb_meta('orion_2016_article_source') != '') {
echo '<a href= ("$article_url") target=blank>';
echo rwmb_meta('orion_2016_article_source');
echo '</a>';} ?> on <?php the_date(); ?>
Since the options are already predefined, it seems like assigning a random URL to one of the options should be pretty simple. Hopefully this makes sense!
You need to to place variables you wish to echo inside double quotes or simply concatenate strings using . as in my example. Note that I didn't check the plugin's specific syntax, only general PHP syntax.
<?php
$article_url= rwmb_meta( 'orion_2016_article_url', 'type=URL' );
if (rwmb_meta('orion_2016_article_source') != '') {
echo '' . rwmb_meta( 'orion_2016_article_source' ); . '';
} ?> on <?php the_date(); ?>
In WordPress i'm currently using this function from a plugin <?php the_field('event_boat'); ?> to output the post ID for the selected field, which happens to be 5755 in this example.
As the plugin only allows me to output the post ID is it possible to incorporate the value from that function inside <?php echo get_permalink(); ?> to get the permalink based on the post ID?
You can pass the ID as a parameter in the get_permalink function, either by storing the ID value in a new variable, or just passing in the ACF-function directly as a parameter.
$post_id = get_field('event_boat');
echo get_permalink($post_id) // echoes out link for ID 5755
I'm using get_field() instead of the_field() because the_field() will echo out the value, We just want to pass it along.
We might aswell just do:
echo get_permalink(get_field('event_boat'));
This should work fine. :)
<?php $a = get_permalink(get_field('event_boat')); echo $a; ?>
<?php $a =get_permalink(get_field('event_boat')); echo $a; ?>
This should work fine. :)
<?php echo get_permalink(get_field('event_boat')); ?>
I'm trying to substring the title which it is called via the method the_title() .
Here are 2 things I did to do it but they both failed.
first try: <?php echo substr(the_title(),1,15) ?>
second try: <?php $new_title = the_title() ; echo substr($new_title, 1,15) ?>
They both didn't work. when I used the second try I still get the full title.
Note: I'm trying to implement this on a Wordpress script, also it's for my php practice.
Thanks in Advance.
The function the_title() does not return the title as string but outputs it by default.
Use the_title('','', 1) which makes it return the title or the alternative function get_the_title() instead.