Show cell value where row and column intersects - php

Question

I am trying to get cell value which is at the intersection of row and column number entered by user, as like in matrices, like if user enters row 5 and column 4 then my result should show the value present in the cell [5.4].
I am getting row and column number as:
<td>Please enter the temperature:</td>
<td><input type="text" name="temp" /></td>
<td>Please enter the column:</td>
<td><input type="text" name="col" /></td>
<td><input type="submit" name="go" /></td>
i am redirecting these values to find.php page, where i am doing this:
$entry1 = $_POST['temp'];
$entry2 = $_POST['col'];
$result = mysql_query("SELECT * FROM tables WHERE Temperature LIKE '".$entry1."'
AND COLUMN_NAME = '".$entry2."' ");
and showing my result as
<td ><?php echo (don't know what to write here) ; ?></td>
i know i am making lot of mistakes but do not know how to fix them. Please show me way.

Answer 1

If you want to get values at [Temperature ,COLUMN_NAME] then change query to
$result = mysql_query("SELECT * FROM tables WHERE Temperature = '".$entry1."'
AND COLUMN_NAME = '".$entry2."' ");
Because LIKE will look all string containing $entry1.
For example if $entry = 10 the it will select column with values like 10, 110, 100,...
after executing the query fetch data like this
if the no of rows returned is more than one the loop it with while like this
while ($row = mysql_fetch_array($result))
{
echo $row[$entry2];
}
or if it return only one value or you need only first value when it returns more than one value try this
$row = mysql_fetch_array($result);
echo $row[$entry2];
Also try to avoid using mysql_* functions and start using mysqli_* function or PDO