PHP use function as return;? - php

Question

I'm using include(); to load certain parts of my page, but sometimes if I'm working on a specific area I want the include(); function to terminate somewhere within that included file, so I use return; and everything following that line will not be included when include(); is called on that file. I can't use die(); because sometimes I have other files needed to be included as well.
Now, I want to be able to control that return; function in terms of what other users see, for instance - I'd like to limit what types of users can see beyond that return; line within the included file. I want admin level users to be able to see beyond that point but not regular users. So I use some kind of if() { } statement to check the user type. Sometimes I want only myself to be able to view the content after the return; line, and I then add if($ip != $my_ip) return;.
The problem is that I have to manually write this stuff, but since I use it often I'd like to write a function that I can pass to what users I want to let bypass the return; part. So I setup a terminate(); function, something like this:
function terminate($param) {
// if statement
{
return;
}
}
But the return; line in that function only returns within that function, it doesn't have any effect on the file that called that function. So in other words, the return; line in my terminate(); function won't actually do the return; I need to stop the include(); function going beyond it.
So how do I stop the include(); command on my file going beyond a certain point with a function and have it not interrupt the remaining code after stopping an include();?
Edit: as a temp fix, I'm using this:
if(terminate($param)) return;
So after passing my parameters to the function if it returns true (stop the include();), it will return; on the file I'm including. So it works that way, I'm just wondering if it's possible to just have a terminate($param); command that will fire the return; command on the file that called that function without having to wrap it around in an if() statement?..

Answer 1

In general, most of the modern projects, which are trying to use clean templates with only HTML, that are obeying the MVC architecture, etc, are using conditions in their templates. There's nothing wrong in it. If you are template looks clean.
<div class="content">
<span class="subcontent"> some content </span>
<?php if ($app->UserController->hasPermissions($_SESSION['id'])): ?>
<span class="admincontent"> Admin Content </span>
<?php endif; ?>
</div>
This kind of code is considered OK. Your view DO have conditions and loops. You cannot avoid them. Also it does not look that clean if you have
<div class="content">
<span class="subcontent"> some content </span>
someFunction();
<span class="admincontent"> Admin Content </span>
</div>
Which will also hide all the content till the end of the file. And it's hard to manage it. It's not impossible still. You can use output buffer for that:
Let's say you have:
functions.php
<?php session_start(); $_SESSION['user_id'] = 1; //fictive session code ?>
<?php
function hasPermissions() {
if ($_SESSION['user_id'] != 1) {
ob_end_clean();
}
}
?>
<?php ob_start(); ?>
end.php
<?php $ob = ob_get_contents();?>
<?php ob_end_clean(); ?>
<?= $ob; ?>
Template.php
<?php include("functions.php"); ?>
<p>included content</p>
<?php hasPermissions(); ?>
<p> included content 2 </p>
<?php include("end.php"); ?>
so, if you are with session id = 1, and running Template.php file, the output will be:
included content
included content 2
Else it will output
included content