How to get correct timezone value using php - php

Question

i am changing server time into another time zone using belowcode
$datetime = new DateTime(2014-02-27 03:03:00);
$la_time = new DateTimeZone('America/New_York');
$datetime->setTimezone($la_time);
$dateformat="Y-m-d h:i A";
return $datetime->format($dateformat);
its working fine except AM/PM...
correct result is: 02-26-14 10:03 AM but i am getting result as 02-26-14 10:03 PM.
can you please tell me where the problem

Answer 1

The result will always be based on the original timezone setting. If you want to convert to a different timezone, you must initialize the DateTime object after setting the timezone.
Here's a function to make the job easier:
function convertTimezone($date,$from_tz,$to_tz,$format='Y-m-d h:i A') {
$date = new DateTime($date, new DateTimeZone($from_tz));
$date->setTimezone(new DateTimeZone($to_tz));
return $date->format($format);
}
The function could be improved by checking if the supplied timezones are valid.
Example Usage:
echo convertTimezone('2014-02-27 03:03:00','Pacific/Nauru','Pacific/Chatham');
Output:
2014-02-27 04:48 AM
Demo

Answer 2

Set the timezone when you initialize the DateTime:
$datetime = new DateTime("2014-02-27 03:03:00", new DateTimeZone('America/New_York'));
$dateformat="Y-m-d h:i A";
return $datetime->format($dateformat);
When you set a DateTime, it uses the timezone then in effect. If you change the timezone later, it will change the representation of the time, but the time will be based on the original timezone setting.
EDIT: I didn't read the question carefully enough; you should set the time zone when you initialize the DateTime object, as in the manual.