Json get value from table - php

Question

I have a small code make this result :
{"nomdupharmacie":[{"pid":"71","name":"dft","longi":"9.010505676269531","lati":"34.1575970207261","matricule":"M65203124"},{"pid":"72","name":"erezrzer","longi":"7.529407627880573","lati":"34.63767601827405","matricule":"123"},{"pid":"73","name":"qsd","longi":"8.83832462131977","lati":"35.172592315800905","matricule":"333"}],"success":1}
with this php code :
// get all products from products table
$result = mysql_query("SELECT *FROM nomdupharmacie") or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node
$response["nomdupharmacie"] = array();
$v = "12";
while ($row = mysql_fetch_array($result)) {
// temp user array
$product = array();
$product["pid"] = $row["pid"];
$product["name"] = $row["name"];
$product["longi"] = $row["longitude"];
$product["lati"] = $row["latitude"];
$product["matricule"] = $row["personnel_number"];
// push single product into final response array
array_push($response["nomdupharmacie"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";
// echo no users JSON
echo json_encode($response);
}
i have to test for example :
$value = "555"
if $value exists in column of matricule so get alert
so the questionis how to make test if the value exists in the Matricule column or not ??

Answer 1

You should look into using PDO or ADOdb instead of mysql_query which is deprecated.
The only option is to compare manually like this:
1) create a function that receives an array x and value v to check
function isMatriculeInArray($x, $v)
{
foreach($x as $z)
{
if($z["matricule"] == $v)
{
return true;
}
}
return false;
}
2) check if matricule is in there
if(!isMatriculeInArray($response["nomdupharmacie"], $v)
{
array_push($response["nomdupharmacie"], $product);
}