I suck at formatting, maybe I had a bad foundation. I have a json like this
'first_name'=>'steve', 'msg'=>'something here','profile_id'=>1
and I want to push a new item into it, I wrote
$i = array('first_name'=>'steve', 'msg'=>'something here','profile_id'=>1);
$loginId = array($_GET['login_id']);
array_push($i,$loginId);
echo json_encode($i);
The result I got is strange:
$i = array('first_name'=>'steve', 'msg'=>'something here','profile_id'=>1);
$loginId = $_GET['login_id'];
$i['login_id']=$loginId;
echo json_encode($i);
The reason array_push didn't work is because you are treating $i as an array (collection) of objects (arrays), while it is just a key-value list (map).
If the array is like K1=>V1, K2=>V2, use $arr[K3]=V3 to add another pair.
If the array is like [(k1,v1), (k2,v2)], then array_push($arr,(k3,v3));
You are basically taking a value $_GET['login_id'], placing it in an array and trying to push it into an associate array, so you you get a new numeric index 0 holding a nested array, which in turn holds your value.
If you want the entire thing to be treated uniformly as an associative array (or an object once converted to JSON) then you should do something like:
$i = array('first_name'=>'steve', 'msg'=>'something here','profile_id'=>1);
$i['login_id'] = $_GET['login_id'];
echo json_encode($i);
Related
I have a script that loops through and retrieves some specified values and adds them to a php array. I then have it return the value to this script:
//Returns the php array to loop through
$test_list= $db->DatabaseRequest($testing);
//Loops through the $test_list array and retrieves a row for each value
foreach ($test_list as $id => $test) {
$getList = $db->getTest($test['id']);
$id_export[] = $getList ;
}
print(json_encode($id_export));
This returns a JSON value of:
[[{"id":1,"amount":2,"type":"0"}], [{"id":2,"amount":25,"type":"0"}]]
This is causing problems when I try to parse the data onto my android App. The result needs to be something like this:
[{"id":1,"amount":2,"type":"0"}, {"id":2,"amount":25,"type":"0"}]
I realize that the loop is adding the array into another array. My question is how can I loop through a php array and put or keep all of those values into an array and output them in the JSON format above?
of course I think $getList contains an array you database's columns,
use
$id_export[] = $getList[0]
Maybe can do some checks to verify if your $getList array is effectively 1 size
$db->getTest() seems to be returning an array of a single object, maybe more, which you are then adding to a new array. Try one of the following:
If there will only ever be one row, just get the 0 index (the simplest):
$id_export[] = $db->getTest($test['id'])[0];
Or get the current array item:
$getList = $db->getTest($test['id']);
$id_export[] = current($getList); //optionally reset()
If there may be more than one row, merge them (probably a better and safer idea regardless):
$getList = $db->getTest($test['id']);
$id_export = array_merge((array)$id_export, $getList);
I am trying to unset a value from test_bots.json and save it back, but somehow the data format is being changed in the process.
test_bots.json contains this JSON array:
["John","Vladimir","Toni","Joshua","Jessica"]
My code looks like this:
$good = 'Toni';
$good_arr = file_get_contents('test_bots.json');
$good_arr = json_decode($good_arr);
if(in_array($good, $good_arr)){
$key = array_search($good, $good_arr);
unset($good_arr[$key]);
$good_arr2 = json_encode($good_arr);
file_put_contents('test_bots.json',$good_arr2);
}
The output that's saved is:
{"0":"John","1":"Vladimir","3":"Joshua","4":"Jessica"}
but I want the output to look like:
["John","Vladimir","Joshua","Jessica"]
I tried to unserialize the array before saving it, but it's not working.
Why is this happening?
In order for json_encode to convert a PHP array with numeric keys to a JSON array rather than a JSON object, the keys must be sequential. (See example #4 in the PHP manual for json_encode.)
You can accomplish this in your code by using array_values, which will reindex the array after you have removed one of the items.
$good_arr2 = json_encode(array_values($good_arr));
Confusing title, the basics are that I'm saving a fully sorted and ordered multidimensional array from a script and into MySQL. I then, on another page, pull it from the database and unserialize it, and then proceed to print it out with this,
$s = "SELECT * FROM gator_historical_data WHERE channelid = '{$chanid}'";
$r = $link->query($s);
$comboarray = array();
while ($row = mysqli_fetch_assoc($r)) {
$comboarray[] = unserialize($row['dataarray']);
}
foreach ($comboarray as $item) {
$desc = $item['content']['description'];
$title = $item['content']['title'];
$datetime = $item['datetime'];
// ... ^^^ problems getting array data
}
The problem is that it doesn't take the full array from MySQL, only the first entry and thus only prints the first 'array'. So where the returned value from dataarray looks like this (var_dump): http://pastebin.com/raw.php?i=Z0jy55sM the data stored into the unserialized $comboarray only looks like this (var_dump): http://pastebin.com/raw.php?i=Ycwwa924
TL;DR: Pulling a serialized multidimensional array from a database, unserializing and it loses all arrays after the first one.
Any ideas what to do?
The string you've got is a serialized string plus something more at the end that is also a serialized string again and again:
a:3:{s:6:"source";s:25:"World news | The Guardian";s:8:"datetime ...
... story01.htm";}}a:3:{s:6:"source";s:16:"BBC News - World";
^^^
This format is not supported by PHP unserialize, it will only unserialize the first chunk and drop everything at the end.
Instead create one array, serialize it and store that result into the database.
Alternatively you can try to recover for the moment by un-chunking the string, however in case the paste was done right, there are more issues. But on the other hand the paste obvious isn't the done fully correct.
I"m creating a PHP script that handles JSON input (via a $_POST variable). It"s extracts data from the JSON and uploads it to an SQL database. I want the JSON in a particular format:
$object = json_decode('{
"key_a":[{"value_a":10,"value_b":7},{"value_a":10,"value_b":7},{"value_a":10,"value_b":7}],
"key_b":[{"value_a":10,"value_b":7}],
"key_c":[{"value_a":10,"value_b":7},{"value_a":10,"value_b":7}]
}',true);
Basically, an object with keys in, each of which should hold an array (no matter what size it is). I use json_decode(json,true) to convert it to an associative array (as opposed to object). I"ve had to add lots of checks in for each of the keys, checking if they"re objects or arrays (as the ASP.net page that the extract comes from converts arrays with single objects in, to objects - removing the array that holds them). The checks then convert them back to arrays, if there"s an object where I"d like an array holding an object:
if(is_object($object["key_b"]))
{
$a = array();
$a[] = $object["key"];
$object["key"] = $a;
}
I then iterate through the array, adding the values to rows in an SQL database. This all works fine, but when converting back to JSON with json_encode, any keys that hold arrays with only one object in, remove the array, and leave just the object under that key:
echo(json_encode($object));
// RETURNED JSON
'{
"key_a":[{"value_a":10,"value_b":7},{"value_a":10,"value_b":7},{"value_a":10,"value_b":7}],
"key_b":{"value_a":10,"value_b":7},
"key_c":[{"value_a":10,"value_b":7},{"value_a":10,"value_b":7}]
}'
You see, key_b no longer holds an array, but an object! This is really annoying, as I plan to create a JavaScript script that iterates through the arrays, adding one DOM element (div) for each of the objects.
Why does this happen? Is there any way to keep them as arrays, even if there"s only one object in the array?
I"ve tried:
if(is_object($object["key_b"]))
{
$a = array();
$a[] = array_values($object["key"]);
$object["key"] = $a;
}
and
if(is_object($object["key_b"]))
{
$a = array();
$a[0] = array_values($object["key"]);
$object["key"] = $a;
}
But it seems like nothing prevents json_encode from affecting the JSON in this way.
It"s not hard to get around this - but it means adding one check per key (checking whether it"s an array or value), which is particularly time consuming as the data extract that comes through is really big.
Any advice would be greatly appreciated.
EDIT: changed ' to " in JSON - though, this is only an example I just wrote to show the structure.
EDIT: I'm using references to cut my coding time down, if this changes anything?:
$t =& $object["key_b"];
if(is_object($t))
{
$a = array();
$a[] = $t;
$t = $a;
}
It appears using is_object() on a key of an associative array will not return true. I just knocked up this example, to prove this:
$json = json_decode('{"job_details":{"a":[{"x":5},{"y":23},{"z":18}],"b":{"x":19},"c":[{"x":64},{"y":132}]}}',true);
echo(json_encode($json)."<br><br>");
$t =& $json["job_details"]["b"];
if(is_object($t))
{
$a = array();
$a[] = $t;
$t = $a;
echo("IS OBJECT<br><br>");
}
echo(json_encode($json));
I will find another means of checking what value is held within an associative arrays key.
I was actually trying to find whether the value in the key is an associative array or not (not an object) - I just didn't realise they were different in PHP.
I must just use this custom function:
function is_assoc($array)
{
return (bool)count(array_filter(array_keys($array), 'is_string'));
}
From: How to check if PHP array is associative or sequential?
Which returns true if the value is an associative array.
Problem: returns array, but not in json.
Result: must return array with in array. outer array has key with numbers and value is array with keys "ID" and "NAME" and there values are assigned from database.
$i = 0;
$json_values = array();
while($sctg = mysql_fetch_assoc($get_sctg)){
$json_values[$i] = array("ID" => $sctg['ID'], "NAME" => $sctg['NAME']);
$i++;
}
echo json_encode($json_values);
Your code is perfectly fine - you just misunderstood the different between arrays and objects in JavaScript.
[{"ID":"4","NAME":"asdasd"},
{"ID":"3","NAME":"LOKS"},
{"ID":"1","NAME":"LOL"}]
This is JSON containing an array with three elements. Each element is an object with the properties ID and NAME.
Let's assume that array is stored in data. You can iterate over the objects in that array with a simple for loop:
for(var i = 0; i < data.length; i++) {
var row = data[i];
// Here you can use row.ID and row.NAME
}
I guess you expected your JSON to look like this:
{
0: {"ID":"4","NAME":"asdasd"},
1: {"ID":"3","NAME":"LOKS"},
2: {"ID":"1","NAME":"LOL"}
}
This would actually be bad since objects in JavaScript are not ordered (even though they actually are in most browsers, but that's not guaranteed!). So when iterating over the rows in such an element (using for(var key in data)), you would not necessarily get the row with ID=4 first just because its key is zero.
However, if you really want an object instead of an array for some reason (you don't!), you could always cast the array to object:
echo json_encode((object)$json_values);
As a side-note, usually it's a good idea to have an object as the top-level element in JSON for security reasons (you can redefine the array constructor and then include something with a top-level array with a script tag and thus access data usually protected by the same origin policy if it was accessed by an XHR request), so I'd change the PHP code like this:
echo json_encode(array('rows' => $json_values));
No need to use $i++; directly use
while($sctg = mysql_fetch_assoc($get_sctg)){
$json_values[] = array("ID" => $sctg['ID'], "NAME" => $sctg['NAME']);
}
and it will return you the JSON