I've been stuck on this for a while. I'm using PHP, and MySQL. What I'm trying to do is create a query to insert a new value into a column called "counter" starting from the second row all the way for 20 columns. The table needs to be sorted by 'article_id' in order to ensure that all the proper rows are updated.
If you can help me to do it for the 2nd row, I can apply that code to the other ones. So I only need the query to update one column at a time.
Table Structure:
Any thoughts?
As far as I can understand it, you are trying to do something like this:
SET #id = SELECT `article_id` FROM `table` ORDER BY `article_id` ASC LIMIT 1, 1;
UPDATE `table` SET `counter` = 1 WHERE `article_id` > #id ORDER BY `article_id` LIMIT 20;
Where of course table is your table name.
Related
I wanted to update MySQL table with certain rules. I have let's say 3 column: ID, Name, Checked and I want to update Name to all rows equally where Checked = 0. In another table I have list 'Names` from where I pull my names.
Is this possible to do with one UPDATE query, or do i need to use some loop? Will there be a problem if let's say I have 11 rows to update but i have 10 names, how the query update those fields.
I find solution:
UPDATE `table` SET `ID` = (select `ID` from `name` ORDER BY rand() LIMIT 1) WHERE `Lock_ID` = 0
This query will randomly use name from other table and update it (it is 99% correct solution) it will redistribute name's almost the same for every row.
This is actually a form to update the team members who work for a specific client, When i deselect a member then it's status turns to 0.
I have a table with all unique records. table consists of four columns -
first column is `id` which is unique and auto_incremented.
second column is `client_id`.
third column is `member_id`. (these second and third columns together make the primary key.)
fourth column is `current` which shows the status (default is 1.).
Now i have a form which sends the values of client_id and member_id. But this forms also contains the values that are already in the table BUT NOT ALL.
I need a query which
(i) `INSERT` the values that are not already in the table,
(ii) `UPDATE` the `current` column to value `0` which are in the table but not in the form values.
here is a screenshot of my form.
If (select count(*) from yourtable where client_id = and member_id = ) > 0 THEN
update yourtable set current = 0;
ELSE
insert into yourtable (client_id,member_id,current) values (value1,value2,value3)
First of all check if the value exists in the table or not, by using a SELECT query.
Then check if the result haven't save value so it will be inserted, else show an error .
This would be a great time to create a database stored procedure that flows something like...
select user
if exists update row
else insert new row
stored procedures don't improve transaction times, but they are a great addition to any piece of software.
If this doesn't solve your problem then a database trigger might help out.
Doing a little research on this matter might open up some great ideas!
Add below logic in your SP
If (select count(*) from yourtable where client_id = <value> and member_id = <value>) > 0 THEN
update yourtable set current = 0;
ELSE
insert into yourtable (client_id,member_id,current) values (value1,value2,value3)
if you want simple solution then follow this:
*) use select with each entry in selected team.
if select returns a row
then use update sql
else
use insert sql.
In your case member_id & client_id together makes the primary key.
So , you can use sql ON DUPLICATE KEY UPDATE Syntax.
Example:
$sql="INSERT INTO table_name SET
client_id='".$clientId."',
member_id='".$member_id."',
current='".$current."'
ON DUPLICATE KEY
UPDATE
current = '".$current."'
";
In this case when member_id & client_id combination repeats , it will automatically executes update query for that particular row.
I need to Select a column with name song_number where id = 2 and then update the second row from the selected rows with 7 for example
what i think that the query i need is something like this but i can't get it work
UPDATE `song` SET `song_number`= 7 WHERE (SELECT `song_number` FROM `song` WHERE `id` = 2 LIMIT 1,1)
any help will be appreciated
edit: i think the problem is mainly in the database structure i made however i found a solution to what i need by making stored procedure http://dev.mysql.com/doc/refman/5.0/en/create-procedure.html
so that i can save the selected items in a procedure and then update it
You have to identify which row you want to update. Identification means using a UNIQUE key or the PRIMARY key of the table.
The limitation of MySQL on UPDATE can be lifted by moving the condition from the WHERE to a JOIN:
UPDATE
song AS s
JOIN
( SELECT PK --- the Primary Key of the tba;e
FROM song
WHERE id = 2
ORDER BY ---whatever
LIMIT 1 OFFSET 1
) AS u
ON u.PK = s.PK
SET s.song_number= 7
If the PRIMARY KEY is id, then the above is useless of course. You are doing something wrong.
I doubt it is possible with one query and yet I see no reason in doing it in one query.
Why can't you just select and then update?
I think should be like this:
UPDATE `song` SET `song_number`= 7 WHERE `song_number` = (SELECT `song_number` FROM `song` WHERE `id` = 2 LIMIT 1,1);
I am trying to update fields in my DB, but got stuck with such a simple problem: I want to update just one row in the table with the biggest id number. I would do something like that:
UPDATE table SET name='test_name' WHERE id = max(id)
Unfortunatelly it doesnt work. Any ideas?
Table Structure
id | name
---|------
1 | ghost
2 | fox
3 | ghost
I want to update only last row because ID number is the greatest one.
The use of MAX() is not possible at this position. But you can do this:
UPDATE table SET name='test_name' ORDER BY id DESC LIMIT 1;
For multiple table, as #Euthyphro question, use table.column.
The error indicates that column id is ambiguous.
Example :
UPDATE table1 as t1
LEFT JOIN table2 as t2
ON t2.id = t1.colref_t2
SET t1.name = nameref_t2
ORDER BY t1.id DESC
LIMIT 1
UPDATE table SET name='test_name' WHERE id = (SELECT max(id) FROM table)
This query will return an error as you can not do a SELECT subquery from the same table you're updating.
Try using this:
UPDATE table SET name='test_name' WHERE id = (
SELECT uid FROM (
SELECT MAX(id) FROM table AS t
) AS tmp
)
This creates a temporary table, which allows using same table for UPDATE and SELECT, but at the cost of performance.
I think iblue's method is probably your best bet; but another solution might be to set the result as a variable, then use that variable in your UPDATE statement.
SET #max = (SELECT max(`id`) FROM `table`);
UPDATE `table` SET `name` = "FOO" WHERE `id` = #max;
This could come in handy if you're expecting to be running multiple queries with the same ID, but its not really ideal to run two queries if you're only performing one update operation.
UPDATE table_NAME
SET COLUMN_NAME='COLUMN_VALUE'
ORDER BY ID
DESC LIMIT 1;
Because you can't use SELECT IN DELETE OR UPDATE CLAUSE.ORDER BY ID DESC LIMIT 1. This gives you ID's which have maximum value MAX(ID) like you tried to do. But MAX(ID) will not work.
Old Question, but for anyone coming across this you might also be able to do this:
UPDATE
`table_name` a
JOIN (SELECT MAX(`id`) AS `maxid` FROM `table_name`) b ON (b.`maxid` = a.`id`)
SET a.`name` = 'test_name';
We can update the record using max() function and maybe it will help for you.
UPDATE MainTable
SET [Date] = GETDATE()
where [ID] = (SELECT MAX([ID]) FROM MainTable)
It will work the perfect for me.
I have to update a table with consecutive numbers.
This is how i do.
UPDATE pos_facturaciondian fdu
SET fdu.idfacturacompra = '".$resultado["afectados"]."',
fdu.fechacreacion = '".$fechacreacion."'
WHERE idfacturaciondian =
(
SELECT min(idfacturaciondian) FROM
(
SELECT *
FROM pos_facturaciondian fds
WHERE fds.idfacturacompra = ''
ORDER BY fds.idfacturaciondian
) as idfacturaciondian
)
Using PHP I tend to do run a mysqli_num_rows then put the result into a variable, then do an UPDATE statement saying where ID = the newly created variable. Some people have posted there is no need to use LIMIT 1 on the end however I like to do this as it doesn't cause any trivial delay but could prevent any unforeseen actions from being taken.
If you have only just inserted the row you can use PHP's mysqli_insert_id function to return this id automatically to you without needing to run the mysqli_num_rows query.
Select the max id first, then update.
UPDATE table SET name='test_name' WHERE id = (SELECT max(id) FROM table)
mysql fetch previous or next record order by anyother field name and not by using order by id
select * from table where id > $id order by name asc limit 1
select * from table where id < $id order by name desc limit 1
I am able to get next and previous records but in this case how can i
upgrade next and previous records.
ID Links orderID
14 Google.com 1
15 Yahoo.com 2
20 gmail.com 3
25 facebook.com 4
What about if i use + and - button in front each link to upgrade and downgrade them and then rearrange the menus order by orderID ?
Well, if you really want to do it in a single query, you can use a subquery to find out the ID you need to update. The problem lies in the fact that MySQL cannot update the same table that you're trying to subquery, for obvious data integrity reasons. So you'll need to use some workarounds for that, such as creating a temporary table in a subquery.
UPDATE table AS t
SET [...]
WHERE t.`id` = (select * FROM (select `id` from table where `id` > $id order by `id` asc limit 1) AS sq)
There is absolutely no need to do the two selects.
You can do the following:
UPDATE table SET field='some value' WHERE id=$id+1
UPDATE table SET field='some value' WHERE id=$id-1
There you go :)