Counting multiple values from a query - php

Question

I'm getting an array of this type from the database: (I can't change the type of data received, as it comes from an outside source)
Array
(
[0] => Es\Result Object
(
[_hit:protected] => Array
(
[_index] => website
[_type] => structure
[_id] => 8
[_score] => 0.625
[_source] => Array
(
[name] => Test1
[locality] => Array
(
[locality] => Bologna
[sign] => BO
[province] => Array
(
[province] => Bologna
[region] => Array
(
[region] => Emilia Romagna
)
)
)
)
)
)
[1] => Elastica\Result Object
(
[_hit:protected] => Array
(
[_index] => website
[_type] => structure
[_id] => 6
[_score] => 0.625
[_source] => Array
(
[name] => Test2
[locality] => Array
(
[locality] => Bologna
[sign] => BO
[province] => Array
(
[province] => Bologna
[region] => Array
(
[region] => Emilia Romagna
)
)
)
)
)
)
......
I enter into a json object value of "locality" and count how many "locality" are equal, for example:
foreach ($results as $result) {
$source = $result->getSource();
$locality = $source['locality']['locality'];
$dataLocality[] = array(
'type' => 'locality',
'label' => $locality,
'count' => 1, //How to increase the count here?
);
}
I tried to put everything in a loop but I can't count the values ​​correctly.
Is there a way to do this?
EDIT
This should be the result that I get:
let's say I get the array has 3 "locality":
2 "foo"
1 "bar"
$dataLocality =
Array
(
[0] => Array
(
[type] => 'locality'
[locality] => 'foo'
[count] => 2
)
[1] => Array
(
[type] => 'locality'
[locality] => 'bar'
[count] => 1
)
)

Answer 1

Does the value of $locality exist in the array? If no, then store it with a count of 1. If yes, then add 1 to the count.
foreach ($results as $result) {
$source = $result->getSource();
$locality = $source['locality']['locality'];
// Manually specify the array key. This makes life much easier down the road,
// especially when you need to find items in the array.
if ( !isset($dataLocality[$locality]) ) {
$dataLocality[$locality] = array('type' => 'locality',
'label' => $locality,
'count' => 1);
} else {
$dataLocality[$locality]['count'] += 1;
}
}

Answer 2

Declare an array (say $dataLocality) outside your foreach loop. In each loop you search for an existant locality in $datalocality (if $result is in $dataLocality). If there is one, you increment the counter by $dataLocality[$indexOfFounding]['count']++.
This off course requires the adding of your array of 'type', 'label' and 'count' if you don't find any locality in $dataLocality.
After the foreach loop you can go through your array and output or do anything with your results.

Answer 3

If you are needing the count of locality array then make use of count Try:
foreach ($results as $result) {
$source = $result->getSource();
$locality = $source['locality']['locality'];
$dataLocality[] = array(
'type' => 'locality',
'label' => $locality,
'count' => count($source['locality']), //get locality array count
);
}

Answer 4

Thanks to #Dave's reply I solved the problem, but since I could not have named keys, I added outside the loop:
$dataLocality = array_values($dataLocality);
so the complete code to solve the problem, but on occasions someone had a problem similar to mine is:
foreach ($results as $result) {
$source = $result->getSource();
if(!isset($dataLocality[$locality = $source['locality']['locality']])) {
$dataLocality[$locality] = array(
'type' => 'locality',
'label' => $locality,
'count' => 1,
);
} else {
$dataLocality[$locality]['count']++;
}
}
$dataLocality = array_values($dataLocality);