<?php
$source = 'http://www.xxx.com/1.jpg';
$fileBody = date('YmdHis') . rand(1000, 9999);
$extension = pathinfo($source, PATHINFO_EXTENSION);
$fileName = $fileBody . '.' . $extension;
$ch = curl_init($source);
$fp = fopen($path . $fileName, 'wb');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);
clearstatcache();
return $fileName;
This is how I grab image from internet, the image saved successfully and I will return file name for ajax to make immediately thumbnail, but sometimes php return the $fileName when it still processing download, therefore JavaScript reveal empty image on the page, how response after the file indeed been download.
curl_exec returns true on success and false on failure. Use that information.
Also, You can check curl_getinfo to make sure the transfer completed successfully and was not empty. (You get http_code there for example, as well as content_type and size_download).
$downComplete = false;
while(!$downComplete)
{
if(!file_exist($filePath))
{
sleep(1);
}
else
{
$downComplete = true;
break;
}
}
Hi,Above is an idea for check if file is completely downloaded,i think it's useful,
main idea is check saved file all the time until its finished download,then you can
display the img to front end..you can add it after your curl code,i didn't run it
myself,so just an idea..
Related
I try to have a php script output a generated image as .jpg file:
$url = 'http://www.photopost.com/photopost/showfull.php?photo=7541';
file_put_contents('image.jpg',file_get_contents($url));
$page = file_get_contents($url);
echo $page;
The echo displays a correct image in the browser.
but image.jpg is not saved.
How can I make this work ?
You need to output a Content-Type header with a proper MIME type for the browser to be able to understand what kind of file the server is sending.
header('Content-Type: image/jpeg');
Refer to http://php.net/manual/en/function.header.php and https://www.sitepoint.com/web-foundations/mime-types-complete-list/ for a list of valid MIME types.
Getting image from url using curl :-
$profile_Image = 'http://www.photopost.com/photopost/showfull.php?photo=7541'; //image url
$userImage = 'myimg.jpg'; // renaming image
$path = ''; // your saving path
$ch = curl_init($profile_Image);
$fp = fopen($path . $userImage, 'wb');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
$result = curl_exec($ch);
curl_close($ch);
fclose($fp);
Getting image from url using file_get_contents :-
$profile_Image = 'http://www.photopost.com/photopost/showfull.php?photo=7541'; //image url
$userImage = 'myimg.jpg'; // renaming image
$path = ''; // your saving path
$thumb_image = file_get_contents($profile_Image);
if ($http_response_header != NULL) {
$thumb_file = $path . $userImage;
file_put_contents($thumb_file, $thumb_image);
}
Change your url from
http://www.photopost.com/photopost/showfull.php?photo=7541 //html document
to
http://www.photopost.com/photopost/watermark.php?file=7541 //downloadable url
Then use code from other answers or use imagecreatefromjpeg
http://php.net/manual/en/function.imagecreatefromjpeg.php
I am downloading a public image and writing it to file. But the filesize(file) returns the entire encoded string of the image
My code is as follows
<?php header('Access-Control-Allow-Origin: *'); ?>
<?php
function download_and_write($src,$filename)
{
$ch = curl_init($src);
$fp = fopen($_SERVER["DOCUMENT_ROOT"]."/dashboard/uploads/".$filename, 'wb');
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
$httpcode = curl_getinfo($curl, CURLINFO_HTTP_CODE);
curl_close($ch);
fclose($fp);
$filepath = $_SERVER["DOCUMENT_ROOT"]."/dashboard/uploads/".$filename;
return filesize($filepath);
}
$src_url = $_POST['source'];
$dest_url = $_POST['destination'];
$filename = $_POST['filename'];
try{
$download = download_and_write($src_url,$filename);
echo $download;
}
catch(Exception $e) {
$mess=$e->getMessage();
echo "exception";
echo $mess;
}
?>
And echo of the download variable is like this
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Why would this occur ? The file didn't download.
EDIT:
I'm not checking the size of a remote file. I'm checking the size of the file on my own server. So this can't be related to the possible duplicate you mentioned.
I think fopen is getting an error, so you're not redirecting the curl output to the file. Add error checking.
error_reporting(E_ALL);
$fp = fopen($_SERVER["DOCUMENT_ROOT"]."/dashboard/uploads/".$filename, 'wb');
if (!$fp) {
throw new Exception("Unable to open download file");
}
I have a file, where I read URLs line by line. The URL are links to images. All the image-links work in the browser. Now I want to download them to my current directory. For the record I need to use a PHP-script.
This is how I get my Images:
for ($j; $j< $count;$j++)
{
// Get Image-URL as String and then do getImage
$image = $arr[$j];
$newname = $j;
getImage($image, $newname);
}
function getImage($image, $newname)
{
$ch = curl_init($image);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_BINARYTRANSFER,1);
$rawdata=curl_exec ($ch);
curl_close ($ch);
$fp = fopen("$newname.jpg",'w');
fwrite($fp, $rawdata);
fclose($fp);
}
But the problem is, I get all the images, only the last one is viewable. The others I can't open and they only have 1KB.
So what did I do wrong?
Plus I need to also download png-Files later on, so can I then just change the $newname.jpg into $newname.png?
Thanks in advance, I really need an answer fast, been sitting here for hours, trying to figure it out.
Why not use stream_copy_to_stream?
function getImage($image, $newname, $fileType = "jpg")
{
$in = fopen($image, "r");
$out = fopen("$newname.$fileType",'w');
stream_copy_to_stream($in, $out);
fclose($in); fclose($out);
}
You can also play with stream_set_read_buffer
stream_set_read_buffer($in, 4096);
Just tested this with our avatar pics.
$data = [
"https://www.gravatar.com/avatar/42eec337b6404f97aedfb4f39d4991f2?s=32&d=identicon&r=PG&f=1",
"https://www.gravatar.com/avatar/2700a034dcbecff07c55d4fef09d110b?s=32&d=identicon&r=PG&f=1",
];
foreach ($data as $i => $image) getImage($image, $i, "png");
Works perfectly.
Debug: Read the remote headers for more info?
$httpresponseheader
var_dump($http_response_header);
or stream_get_meta_data
var_dump(stream_get_meta_data($in), stream_get_meta_data($out));
I wrote a PHP script which simply gets URL for images and tries to download/save them on server.
My problem here is that sometimes the image is not fully loaded and the codes blow only save images partially. I did some research but couldn't figure out if I can add something to it, so it can check whether it is saving the full image or not.
Images sizes and other properties of images are random so I can't check it with those factors unless there is a way that I can get those info before loading them image.
Thank you all.
if ( $leng >= "5" ) {
define('UPLOAD_DIR', dirname(__FILE__) . '/files/');
$length = 512000;
$handle = fopen($url, 'rb');
$filename = UPLOAD_DIR . substr(strrchr($url, '/'), 1);
$write = fopen($filename, 'w');
while (!feof($handle))
{
$buffer = fread($handle, $length);
fwrite($write, $buffer);
}
fclose($handle);
fclose($write);
}else {Echo "failed";}
I think that using cURL is a better solution than using fopen for url. Check this out:
$file = fopen($filename, 'wb'); //Write it as a binary file - like image
$c = curl_init($url);
curl_setopt($c, CURLOPT_FILE, $file);
curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); //Allow cURL to follow redirects (but take note that this does not work with safemode enabled)
curl_exec($c);
$httpCode = curl_getinfo($c, CURLINFO_HTTP_CODE); //200 means OK, you may check it later, just for sure
curl_close($c);
fclose($file);
Partially based on Downloading a large file using curl
I am trying to create an upload plugin that allows for a user to upload any file from their computer or from a url they type into the provided text field.
This is the script I have to upload files from a local disk:
session_start();
//Loop through each file
for($i=0; $i<count($_FILES['file']); $i++) {
//Get the temp file path
if (isset($_FILES['file']['tmp_name'][$i]))
{
$tmpFilePath = $_FILES['file']['tmp_name'][$i];
}
//Make sure we have a filepath
if ($tmpFilePath != ""){
//Setup our new file path
if (isset($_FILES['file']['name'][$i]))
$newFilePath = "./uploaded_files/" . $_FILES['file']['name'][$i];
}
//Upload the file into the temp dir
if(move_uploaded_file($tmpFilePath, $newFilePath)) {
echo "Uploaded Successfully!<br />";
}
All I need now is for the curl part to take the file from the url submitted in the text field and save it to the same location.
Here is the cURL I have so far:
function GetImageFromUrl($link) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_POST, 0);
curl_setopt($ch,CURLOPT_URL,$link);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$result=curl_exec($ch);
curl_close($ch);
return $result;
}
$sourcecode=GetImageFromUrl("http://domain.com/path/image.jpg");
$savefile = fopen('/home/path/image.jpg', 'w');
fwrite($savefile, $sourcecode);
fclose($savefile);
Is there a specific reason you want to use curl? Here's how you can simply do that without it:
$url = $_POST['url'];
$file_content = file_get_contents($url);
$file_name = array_pop(explode('/', parse_url($url, PHP_URL_PATH)));
file_put_contents('/home/path/' . $file_name, $file_content);
You should also consider looking into $url and checking if it's valid before working with it.