Connection Error in PHP - php

Question

Ohk, I just started to learn PHP and MySQL. Everything was going fine untill this thing boiled up my mind.
Here is the problem.
I have two php files in the same directory.
mysql.php--->
<?php
require("connect.php")or die(mysql_error());
?>
connect.php--->
<?php
error_reporting(0);
$connect=mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("phpacademy")or die(mysql_error());
echo"Connected!";
?>
The problem is that whenever I am running the connect.php script directly, its working fine.
But when I run mysql.php to connect to the other script it gives the following error:
Warning: require(1): failed to open stream: No such file or directory in C:\xampp\htdocs\stckovrflw1\mysql.php on line 3
Fatal error: require(): Failed opening required '1' (include_path='.;C:\xampp\php\PEAR') in C:\xampp\htdocs\stckovrflw1\mysql.php on line 3
Its not getting the file even though it exists and the spelling is obviously not incorrect.
And the most amazing part is that, as soon as I remove the or die() everything works like a charm.
As I am a beginner I have no idea whats going on. I supposed that or die() is just for developer's or user's help to see the exact error, but in this case it is causing the error itself.
Do help!!!
Thanks in advance...:)
P.S.: I am running on localhost as mentioned in code also.

Answer 1

or has a higher precedence than require/require_once. Therefore php evaluates
('connect.php') or die("blah blah")
before passing the result to require. Or takes two boolean operands. ('connect.php') evaluates to true therefore the whole expression is true and
require true;
is invoked.
require takes string as parameter, so true casts to 1 by php.
so it became require 1 in your case
that generate failed to open error
A bug reported on bugs.php.net https://bugs.php.net/bug.php?id=15438 says:
"Because include() is a special language costruct, parentheses are not
needed around its argument. Take care when comparing return value.
<?php
// won't work, evaluated as include(('vars.php') == 'OK'), i.e. include('')
if (include('vars.php') == 'OK') {
echo 'OK';
}
// works
if ((include 'vars.php') == 'OK') {
echo 'OK';
}

Answer 2

It is mysql_select_db and not mysql_selectdb
and by the way if you have begun learning php and mysql, better get yourself trained using mysqli and not mysql
You don't have to use die() in the require line, if the file is not present PHP will automatically throw error
FYI:
die() method comes in handy for debugging yes!! thts true when you want to stop the execution of some loop or code flow when you want to analyse what are the variables that you get as output and the ones that you dont

Answer 3

<?php
require("connect.php")or die(mysql_error());
?>
Does not work. PHP at first evaluates the expression
("connect.php") or die(mysql_error())
And this expression is always true. The result ist:
require true
This doesn't work. You even don't need to check the connection because you checked this in your connect.php. But double checking is not wrong and it's better for future compatibility (for example you can change your implementation and remove the check in connect.php). So you can use this instead:
<?php
require("connect.php");
if(!$connect)
die(mysql_error());
?>

Answer 4

error_reporting(0);
$connect=mysql_connect("localhost","root","") or die(mysql_error());
mysql_selectdb("phpacademy",$connect)or die(mysql_error());
echo"Connected!";

Answer 5

You need to set you PHP.INI
It is clear that your include path is set to default, which is (include_path='.;C:\xampp\php\PEAR')
You PHP-config is looking for file in 'C:\xampp\php\PEAR', which is not there.
Try set_include_path() (reference: www.php.net/set_include_path)
<?php
set_include_path('C:\xampp\htdocs\stckovrflw1\');
require("connect.php")or die(mysql_error());
?>

Answer 6

mysql_selectdb("phpacademy",$connect)or die(mysql_error());