How to showing report that group by archieve with PHP & MySQL? - php

I want to recapitulate report that grouped by month. But the results of sum is incorrect. It's just sum data in one month and show in all rows.
<?php
$query = mysql_query("SELECT * FROM barang GROUP BY arsip");
$i = 1;
while ($data = mysql_fetch_assoc($query)) {
?>
<tr class="<?php if ($i % 2 == 0) { echo "odd"; } else { echo "even"; } ?>">
<td><?php echo $i; ?></td>
<td><?php echo $data['arsip']; ?></td>
<td><?php
$Masuk= mysql_query("SELECT SUM(barang_in) AS masuk FROM barang GROUP BY arsip");
if($Masuk){
$data = mysql_fetch_assoc($Masuk);
echo $data['masuk'];
}
?></td>
<td><?php
$keluar= mysql_query("SELECT SUM(bijih_out+htm_out+pth_out) AS keluar FROM barang GROUP BY arsip");
if($keluar){
$data = mysql_fetch_assoc($keluar);
echo $data['keluar'];
}?></td>
<td><?php
$efisiensi= mysql_query("SELECT SUM((bijih_out+htm_out+pth_out)-barang_in) AS efisiensi FROM barang GROUP BY arsip");
if($efisiensi){
$data = mysql_fetch_assoc($efisiensi);
echo $data['efisiensi'];
}
?></td>
<td><?php
$persen= mysql_query("SELECT SUM(barang_in/(bijih_out+htm_out+pth_out))*1 AS persen FROM barang GROUP BY arsip");
$simbol = "%";
if($persen){
$data = mysql_fetch_assoc($persen);
echo number_format($data['persen'],2); echo $simbol;
}
?></td>
<?php
$i++;
}
?>
so that's my code. what's wrong with that? There are some columns for displaying income items, outcome items, efficiency ( difference of outcome and income items ) and percent of efficiency.

finally I found out the right code. Thankyou for #RandomSeed who helps me. This is my final code and it works!
<?php
$query = mysql_query("SELECT arsip, SUM(barang_in) AS income, SUM(bijih_out+htm_out+pth_out) AS outcome, SUM((bijih_out+htm_out+pth_out
)-barang_in) AS efficiency, SUM((barang_in / ( bijih_out + htm_out + pth_out))*100) AS percent FROM barang GROUP BY arsip");
$i = 1;
while ($data = mysql_fetch_assoc($query)) {
?>
<tr class="<?php if ($i % 2 == 0) { echo "odd"; } else { echo "even"; } ?>">
<td><?php echo $i; ?></td>
<td><?php echo $data['arsip']; ?></td>
<td><?php echo $data['income']; ?></td>
<td><?php echo $data['outcome']; ?></td>
<td><?php echo $data['efficiency']; ?></td>
<td><?php $simbol = "%"; echo number_format($data['percent'],0); echo $simbol; ?></td>
<?php
$i++;
}
?>

Related

Calculate total amount of rows for specific date

I have this working.
$queryPR = "SELECT * FROM `raport` WHERE DATE(`timestamp`) = CURDATE() AND (lokacioni = 'PR')";
I need the total amount of rows calculated for specific date.
I need also to the SUM('pagesat') somehow but I have no idea how.
Find the whole code below.
I am trying to build something simple to show the income and outcome for 3 locations that we have.
<table class="responsive-table">
<thead>
<tr>
<th>Vetura</th>
<th>Targa</th>
<th>Dite</th>
<th>Pagesa</th>
<th>Cmimi Ditore</th>
<th>Vazhdim</th>
<th>Te Tjera</th>
<th>Shpenzime</th>
<th>Komente</th>
</tr>
</thead>
<tbody>
<?php
$query = "SELECT * FROM `raport` WHERE DATE(`timestamp`) = CURDATE() AND (lokacioni = 'FR')";
$stmt = $DBcon->prepare( $query );
$stmt->execute();
while($row=$stmt->fetch(PDO::FETCH_ASSOC)){
?>
<tr>
<td><?php echo $row['vetura']; ?></td>
<td><?php echo $row['targa']; ?></td>
<td><?php echo $row['dite']; ?></td>
<td><?php echo $row['pagesa']; ?>€</td>
<td><?php echo $row['cmimiditore']; ?>€</td>
<td><?php echo $row['vazhdim']; ?>€</td>
<td><?php echo $row['tetjera']; ?>€</td>
<td><?php echo $row['shpenzime']; ?>€</td>
<td><?php echo $row['koment']; ?></td>
</tr>
<?php
$pagesa = $row['pagesa'];
$tetjera = $row['tetjera'];
$vazhdime = $row['vazhdim'];
$shpenzime = $row['shpenzime'];
}?>
</tbody>
</table>
<?php
$totali = ($pagesa + $vazhdime + $tetjera);
$gtotal = ($totali - $shpenzime);
?>
<div class="card grey">
<hgroup class="totalDitorRaport">
<h2>Total</h2>
<h1><?php echo $gtotal; ?>€</h1>
</hgroup>
</div>
try this
get the sum of the row pagesa in the loop
$queryPR = "SELECT * FROM `raport` WHERE DATE(`timestamp`) = CURDATE() AND (lokacioni = 'PR')";
$stmt = $DBcon->prepare( $query );
$stmt->execute();
$sum = 0;
while($row=$stmt->fetch(PDO::FETCH_ASSOC)){
$sum += $row['pagesa'];
}
echo $sum;

php code to select sum and count of column

there are multiple column in my table ..
col1 col2 col3 price
500 700 100 10
501 700 100 20
502 700 100 30
503 700 100 10
4 70
I need to get count of col1 and display its sum.
and also display sum of price column...
But the main thing is i need to display this in last row....after all data...how can select this and echo in last row...
plz help me...
I need to echo exactly as i put the data in above table...
I need sql query and also need help to echo only sum of this two column in last row only......
SELECT *,IFNULL(col1,'SUM'), count(*) as count FROM coupon_entry WHERE Group By col1 WITH ROLLUP
<?php if (is_array($data)) { foreach($data as $row){ ?>
<tr>
<td><?php echo htmlspecialchars($row['col1']); ?></td>
<td><?php echo htmlspecialchars($row['col2']); ?></td>
<td><?php echo htmlspecialchars($row['col3']); ?></td>
<td><?php echo htmlspecialchars($row['price']); ?></td>
</tr>
<?php } }?>
One solution is to calculate the sum in PHP with variables :
<?php if (is_array($data)) {
$totalCol1 = 0;
$totalPrice = 0;
foreach($data as $row){
$totalCol1 += $row['col1'];
$totalPrice += $row['price'];
?>
<tr>
<td><?php echo htmlspecialchars($row['col1']); ?></td>
<td><?php echo htmlspecialchars($row['col2']); ?></td>
<td><?php echo htmlspecialchars($row['col3']); ?></td>
<td><?php echo htmlspecialchars($row['price']); ?></td>
</tr>
<?php }
<tr>
<td><?php echo $totalCol1;?></td>
<td></td>
<td></td>
<td><?php echo $totalPrice;?></td>
</tr>
}?>
Either you have to do 2 separate queries or else you have to do your calculations in PHP - either one is fairly simple although the PHP solution will probably be slightly (negligibly?) faster.
double-query:
$r = query('SELECT *
FROM yada-yada');
while ($row = fetch($r)) {
echo "<td>$row[col1]</td>\n";
echo "<td>$row[col2]</td>\n";
echo "<td>$row[col3]</td>\n";
echo "<td>$row[price]</td>\n";
}
$r2 = query('SELECT COUNT(*) as cnt, sum(col1) as sum_col1,
sum(price) as sum_price
FROM yada-yada...');
if ($row = fetch($r2)) {
echo "<td>$row['cnt']</td><td>$row['sum_col1']</td>...$row['sum_price']...\n";
}
calculate in PHP:
$cnt = $sum_col1 = $sum_price = 0;
$r = query('SELECT *
FROM yada-yada');
while ($row = fetch($r)) {
echo "<td>$row[col1]</td>\n";
echo "<td>$row[col2]</td>\n";
echo "<td>$row[col3]</td>\n";
echo "<td>$row[price]</td>\n";
$cnt++;
$sum_col1 += $row['col1'];
$sum_price += $row['price'];
}
echo "<td>$cnt</td><td>$sum_col1</td>...$sum_price...\n";
Below is my sql query to get count and sum of column.
SELECT COUNT(coupon) As Total,SUM(Price) AS TotalPrice FROM coupon_entry
And put this in seprate row below table...
<?php
foreach($tot as $tota)
?>
<tr style="background-color:#33CCFF;">
<td colspan="2" style="text-align:right; font-weight:bold;">Total Coupon</td>
<td><?php echo $tota['Total'];?></td>
<td style="text-align:right; font-weight:bold;">Total Amount in Rs</td>
<td><?php echo $tota['TotalPrice'];?></td>
</tr>
<?php }?>

Cannot echo the column SUM(column_name) as Total

This is my query:
$rs = pg_query("select sj.*, SUM(p.paid_amount) as Total, sj.subject_fee - SUM(p.paid_amount) as Balance
from tbl_subject as sj, tbl_payment_details as p, tbl_student as s, tbl_student_block as sb
where p.student_block_id = sb.student_block_id and s.student_id = sb.student_id and sj.subject_id = sb.subject_id and
sb.student_id = ".$_POST['student']." group by sj.subject_id order by sj.subject_id;");
displayRecordset($rs);
The problem is when I echo $r['Total'], it doesn't show column Total in my query.
This is my function:
$counter = 1;
while ($r = pg_fetch_array($rs, NULL, PGSQL_ASSOC))
{
$total = $r['Total'];
?>
<tr>
<td><?php echo $counter; ?></td>
<td><?php echo $r['subject_id']; ?></td>
<td><?php echo $r['subject_fee']; ?></td>
<td><?php echo $total; ?></td>
<td><?php echo $r['Balance']."Balance"; ?></td>
<td>
Edit
</td>
</tr>
<?php
$counter++;
}

Set proper conditional statement in WHILE LOOP

After submitting a mysqli_query to select open/unfulfilled orders from a cart database the results is output to the screen with a standard WHILE LOOP.
while($row = mysqli_fetch_array($oresult)) { include('orders-open.php');}
orders-open.php is simply the internal part of a TABLE:
<tr style="color:#FFF;">
<td><?php echo $row['Buyer']; ?></td>
<td><?php echo $row['Cart_Date']; ?></td>
<td><?php echo $row['Item_Number']; ?></td>
<td><?php echo $row['Item_Title']; ?></td>
<td><?php echo $row['Item_FPrice']; ?></td>
<td><?php echo $row['Item_Qty']; ?></td>
</tr>
So here is my question, I want to apply a simple HTML "<HR>" tag between the records at the point where the value in $row['Buyer'] changes, so by example:
John Doe 9/11/13 123456 Item 1 $5.99 5
John Doe 9/11/13 123654 Item 2 $8.99 3
John Doe 9/9/13 321456 Item 3 $4.99 2
(HR - Horizontal Rule Tag here)
Mike Doe 9/7/13 123555 Item 1 $9.99 2
Mike Doe 9/7/13 123777 Item 2 $2.99 6
What would be the best way to write the conditional statement inside the WHILE LOOP to compare the $row[Buyer'] result to the previous $row['Buyer'] result?
$first_run = TRUE;
$previous_buyer = NULL;
while($row = mysqli_fetch_array($oresult)) {
if($first_run) {
$first_run = FALSE;
$previous_buyer = $row['Buyer'];
}
include('orders-open.php');
}
And then in your include file:
<?php if($previous_buyer != $row['Buyer']) {
echo '<HR width="100%">';
$previous_buyer = $row['Buyer'];
} ?>
<tr style="color:#FFF;">
<td><?php echo $row['Buyer']; ?></td>
<td><?php echo $row['Cart_Date']; ?></td>
<td><?php echo $row['Item_Number']; ?></td>
<td><?php echo $row['Item_Title']; ?></td>
<td><?php echo $row['Item_FPrice']; ?></td>
<td><?php echo $row['Item_Qty']; ?></td>
</tr>
$prev_buyer = '';
while($row = mysqli_fetch_array($oresult))
{
if($prev_buyer !== $row['Buyer'])
{
//Do Something
}
include('orders-open.php');
$prev_buyer = $row['Buyer']
}
Just as Elon said above - change this:
while($row = mysqli_fetch_array($oresult)) { include('orders-open.php');}
to
$old_buyer = null;
while($row = mysqli_fetch_array($oresult)) {
if ($row['Buyer'] != $old_buyer) {
echo '<hr>';
}
$old_buyer = $row['Buyer'];
include('orders-open.php');
}
You could do it like this:
$buyer = null ; //Cache buyer in a variable, because $row is reset in the loop.
while($row = mysqli_fetch_array($oresult)) {
include('orders-open.php');
if ($buyer !== $row["Buyer"]){
echo ($buyer !== null) ? "<hr/>" : "" ;
$buyer = $row["Buyer"] ;
}
}

sum all value in foreach loop php

<?php foreach((array)$query as $row):?>
<td><?php echo $row->date ?></td>
<td><?php echo $row->cost ?></td>
<?php endforeach ;?>
I want to sum all values in $row->cost when $row->date=02-01-2016, like this in a table
Thanks.
echo array_sum(array_filter(array_map(function($row){
if($row->date == '02-01-2016')
return $row->cost;
}, $array)));
You can use
array_map: to compare and skip the values for which cost is not needed to add in sum.
array_filter: and then to remove the blank indexes
array_sum: and finally to sum cost
Note: if you are getting results from database, you can simply do sum there (see below):
$db->query("SELECT SUM(costs) FROM table_name WHERE `date`='2016-01-02'");
echo $db->fetchColumn();
Try below code:
<?php
$total = 0;
foreach((array)$query as $row):
$date = $row->date;
$cost = $row->cost;
if(date("M-d-Y", strtotime($date))==date("M-d-Y")) {
$total = $total+$cost;
}
?>
<td><?php echo $date ?></td>
<td><?php echo $cost ?></td>
<?php endforeach; ?>
<td colspan="2"><?php echo $total; ?></td>
<?php
$tot = 0;
foreach( (array)$query as $row ) {
if( $row->date=='02-01-2016' ) $tot = $tot+$row->cost;
?>
<tr>
<td><?php echo $row->date ?></td>
<td><?php echo $row->cost ?></td>
</tr>
<?php } ?>
<tr><td colspan="2"><?php echo $tot; ?></td></tr>
obviously, the comparison works if $row->date is formatted as dd-mm-yyyy
<table border=1>
<?php
$tot = 0;
foreach($query as $row ) {
if( $row->date=='2016-01-02' ) $tot += $row->cost;
?>
<tr>
<td><?php echo $row->date ?></td>
<td><?php echo $row->cost ?></td>
</tr>
<?php } ?>
<tr><td></td><td><?php echo $total; ?></td></tr>
</table>
It will work for you exctly what u want.

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