I have here a ajax. What I need to know if it possible to send back the post value and store it in php variable in the mainpage depending in onchange event? $_POST["mainlist_id"] store in php var?
getajax.php
<?php
if (isset($_POST["mainlist_id"])) {
$mysqli = new mysqli("localhost", "root", "", "2015");
$main = $mysqli->real_escape_string($_POST["mainlist_id"]);
$result1 = $mysqli->query("SELECT * FROM code WHERE cat_code='$main' GROUP BY item_code ORDER BY item");
$option1 = '';
while($row = $result1->fetch_assoc())
{
$option1 .= '<option value = "'.$row['item'].'">'.$row['item'].'</option>';
}
echo $option1;
}
?>
Mainpage
<script type="text/javascript">
$('#main').change(function () {
$.ajax({
url: 'getajax.php',
data: {
mainlist_id: $(this).val()
},
dataType: 'html',
type: 'POST',
success: function (data) {
$('#languages').html(data);
}
});
});
</script>
getajax.php
<?php
session_start();
if (isset($_POST["mainlist_id"])) {
$mysqli = new mysqli("localhost", "root", "", "2015");
$main = $mysqli->real_escape_string($_POST["mainlist_id"]);
$_SESSION['mainlist_id']=$main;
$result1 = $mysqli->query("SELECT * FROM code WHERE cat_code='$main' GROUP BY item_code ORDER BY item");
$option1 = '';
while($row = $result1->fetch_assoc())
{
$option1 .= '<option value = "'.$row['item'].'">'.$row['item'].'</option>';
}
echo $option1;
}
?>
Mainpage
<?php session_start();
$main_id=$_SESSION['mainlist_id'];
?>
<script type="text/javascript">
$('#main').change(function () {
$.ajax({
url: 'getajax.php',
data: {
mainlist_id: $(this).val()
},
dataType: 'html',
type: 'POST',
success: function (data) {
$('#languages').html(data);
}
});
});
</script>
Related
I want to compare my field value to mysql field with ajax.
this is my ajax cod:
$("#checkCodeButton").click(function() {
var enteredCodeField = $("#order-discount").val();
$.ajax({
type: 'post',
url: 'check.php',
data: {
enteredCode: enteredCodeField
},
dataType: "text",
success: function(data) {
alert(data);
}
})
});
and this is my code in check.php
<?php
$link = mysqli_connect("localhost", "root", "", "animating-wp");
date_default_timezone_set('Asia/Tehran');
$days = 0;
$hours = 0;
$discountPercent = 0;
if (isset($_POST['enteredCode']) && !empty($_POST['enteredCode'])) {
$SelectDiscountQuery = "SELECT * FROM discounts WHERE discount_code = ' " . $_POST['enteredCode'] . " ' ";
$discountResult = mysqli_query($link, $SelectDiscountQuery);
if(mysqli_num_rows($discountResult) > 0){
echo "blah blah";
} else {
echo "blah";
}
}
but I dont know why when I'm clicking on the button it doesn't work?
( also I run this in wordpress them and linked jquery in script>
thanks
I have the following code:
<?php
session_start();
?>
<html>
<head>
<title>Dashboard</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
</head>
<body>
<button id="openjob">View open job requests</button>
<button id="jobtoday">View all job requests today</button>
<div id="responsecontainer"></div>
<script type="text/javascript">
$('#openjob').click(function() {
<?php
$_SESSION["flag"] = 0;
?>
$.ajax({
type: "GET",
url: "cssdashsubmit.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
$('#jobtoday').click(function() {
<?php
$_SESSION['flag'] = 1;
?>
$.ajax({
type: "GET",
url: "cssdashsubmit.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
</script>
</body>
</html>
cssdashsubmit.php includes
session_start();
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
echo $_SESSION['flag'];
if (isset($_SESSION['flag']) && $_SESSION["flag"] === 0) {
$sql = "SELECT * FROM Ticket WHERE ticket_close_open = 'open'";
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
unset($_SESSION['flag']);
}
if (isset($_SESSION['flag']) && $_SESSION["flag"] === 1) {
$sql = "SELECT * FROM Ticket WHERE DATE(ticket_open_datetime) = date('Ymd')";
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
unset($_SESSION['flag']);
}
?>
Now when I click on the buttons, it always echoes 3, irrespective of which button I click. I've tried changing the session variable name, but it still persists. Can anybody point where I am erroring?
Instead of session - use simple url parameter:
$('#openjob').click(function() {
$.ajax({
type: "GET",
url: "cssdashsubmit.php?type=jobs",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
$('#jobtoday').click(function() {
$.ajax({
type: "GET",
url: "cssdashsubmit.php?type=requests",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
}
});
});
On server side code can be:
session_start();
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
switch ($_GET['type']) {
case "jobs":
$sql = "SELECT * FROM Ticket WHERE ticket_close_open = 'open'";
break;
case "requests":
$sql = "SELECT * FROM Ticket WHERE DATE(ticket_open_datetime) = date('Ymd')";
break;
}
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
echo $row['ticket_id'];
echo $row['ticket_equipment'];
}
}
I have drop down Select box as follows
<?php
$sql = "SELECT scheduleName FROM schedule";
$result = mysqli_query($link,$sql);
echo "<select name='schedule' id='schedule'>";
echo "<option value=''>-- Select Schedule --</option>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['scheduleName'] . "'>" . $row['scheduleName'] . "</option>";
}
echo "</select>";
?>
And I have a file called processClg.php as follows
<?php
include "config.php";
if ($_POST['type']=='POST')
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE 'Row id of drop down selection'";
$res = mysqli_query($link,$qry);
}
?>
How can I call processClg.php file on $("#schedule").change(function ());by assigning Row id of drop down selection as where condition.
Update
Am getting Response from processClg.Php as follows
[{"id":"2","scheduleName":"shanth","subject":"Patho","university":"Dali","facultyName":"Dr","scheduleStartDate":"2015-06-05","scheduleEndDate":"2015-06-09"}]
How to assign response values from ajax call to the following Php variables
<?php
$scheduleStartDate = '';
$scheduleEndDate = '';
?>
Any help my greatly appreciated.
$("#schedule").change(function() {
var value = $('#schedule option:selected').text();
var ajaxCheck = $.ajax({
url: 'processClg.php',
type: 'POST', // had mention post bcoz u mention in processClg.php
dataType: 'json', // processClg.php will return string means change to text
data: { id: value },
success: function(data){
console.log('success');
itrToRead(data);
}
});
});
function itrToRead(data) {
$(data).each(function(key, value){
console.log('key is: '+key+' and value is: '+value);
});
}
processClg.php
<?php
include "config.php";
if ($_POST['type']=='POST') {
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_POST['id']."'";
$res = mysqli_query($link,$qry);
echo $res;
}
?>
You can call ajax as follows:
var RowId;
$.ajax({
type: "POST",
async: false,
url: url,
data: postdata,
//dataType: "json",
success: function (data) {
RowId = data;
}
});
The fact is that to assign response to variable is pass the parameter async: false,
Then its work.
I guess you have your dropdown in your rendered page and you want to send the selected value to the php page:
$("#schedule").change(function(){
var val2pass = $(this).find(':selected').val(); // get the value
$.ajax({
url: 'processClg.php',
type:'post', // <-----you need to use post as you are using $_POST[]
data: { rowid : val2pass }, //<---pass the value
success: function(data){
itrToRead(data);
}
});
});
So now on the php side you need to do this:
<?php
include "config.php";
if ($_POST['type']=='POST')
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_POST['rowid']."'";
$res = mysqli_query($link,$qry);
}
?>
Your procellClg.php will be
<?php
include "config.php";
if (isset($_REQUEST['qid']))
{
$qry = "SELECT * FROM schedule WHERE scheduleName LIKE '".$_REQUEST['qid']."'";
$result = mysqli_query($link,$qry);
echo "<select name='schedule' id='schedule'>";
echo "<option value=''>-- Select Schedule --</option>";
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['scheduleName'] . "'>" . $row['scheduleName'] . "</option>";
}
echo "</select>";
}
?>
and then make Ajax function call
$("#schedule").change(function() {
val = $(this).val();
$.ajax({
type: "POST",
async: false,
url: 'processClg.php',
data: {qid:val},
success: function(data){
$(this).html(data);
}
});
});
Hello im doing some try and error. This is the code where select-option populate from database but this gives me null value
echo "<option value=\"\">"."Select"."</option>";
$qry = "select * from try where name = '".$_POST['name']."'";
$result = mysqli_query($con,$qry);
while ($row = mysqli_fetch_array($result)){
echo "<option value='".$row['trynum']."'>".$row['tryname']."</option>";
}
$.ajax({
type: "POST",
url: "json_php_sub.php",
data: {instructor:$(this).val()},
datatype: 'json',
success: function(result){
alert(result);
document.getElementById("sub").innerHTML = result;
}
});
<select id="sub" name="subb"></select>
my problem is whether i select from dropdown the content is there but no value. pls help..
PHP:
$ajaxAnswer = "<option value=\"\">"."Select"."</option>";
$instructor = mysqli_real_escape_string($conn,$_POST['instructor']);
$qry = "select * from try where name = '".$instructor."'";
$result = mysqli_query($con,$qry);
while ($row = mysqli_fetch_array($result)){
$ajaxAnswer .= "<option value='".$row['trynum']."'>".$row['tryname']."</option>";
}
echo $ajaxAnswer;
Jquery:
$.ajax({
type: "POST",
url: "json_php_sub.php",
data: {instructor:$(this).val()},
success: function(result){
$("#sub").html(result);
}
});
data: {instructor:$('#SELECT_ELEMTN_ID').val()},
Depending on scope and stuff, you may not wanna use "this".
Jquery
$(document).ready(function () {
$.ajax({
type: "GET",
url: "phpfile.php",
dataType: "json",
success: function (data) {
$.each(data, function (idx, obj) {
$('#selectdata').append('<option value="'+obj.user_id+'">'+obj.user_name+'</option>' )
});
}
});
});
</script>
</head>
<body>
<select id="selectdata">
</select>
</body>
phpfile.php
<?php
$host = "localhost";
$user = "root";
$password ="";
$database= "databasename";
$con = mysqli_connect($host , $user , $password);
$database_connect = mysqli_select_db($con, $database);
$result = mysqli_query($con, "select Id as user_id,Name as user_name from users");
$data = mysqli_fetch_all($result, MYSQLI_ASSOC);
echo json_encode($data);
?>
I want to get the latest post_id in the table without refreshing it, but the problem is whenever a user inserts a value to the database, It echoes infinitely the last post_id. I want it to echo only once. But I still want to get the latest post_id from the table.
Here is my main php:
<div id = "this_div">
<?php
include 'connect.php';
session_start();
$query = "SELECT post_id FROM tbl_posts ORDER BY post_id ASC LIMIT 20";
$execute_query = mysqli_query($con,$query);
while($row = mysqli_fetch_assoc($execute_query))
{
$get_this_id = $row['post_id'];
echo $get_this_id."<br>";
}
$_SESSION['get_this_id'] = $get_this_id;
?>
</div>
here is my jQuery ajax:
<script>
var refreshId = setInterval(function(){
compare_session = "<?php echo $_SESSION['get_this_id']; ?>";
$.ajax({
url: 'another_file.php',
data: {},
success: function(data)
{
if(compare_session != data)
{
$('#this_div').text($('#this_div').text()+data);
}
}
});
},400);
</script>
here is the php code of another_file.php
<?php
include 'connect.php';
session_start();
$query = "SELECT post_id FROM tbl_posts ORDER BY post_id DESC LIMIT 1";
$execute_query = mysqli_query($con,$query);
if($row = mysqli_fetch_assoc($execute_query))
{
echo $get_this_id = $row['post_id'];
}
?>
You are not updating the compare_session variable , it holds always the initial value . So update it inside success callback function
compare_session = "<?php echo $_SESSION['get_this_id']; ?>";
var refreshId = setInterval(function () {
$.ajax({
url: 'another_file.php',
data: {},
success: function (data) {
if (compare_session != data) {
$('#this_div').text($('#this_div').text() + data);
}
compare_session = data;
}
});
}, 400);