I wrote this function to generate pagelinks for a high count of pages and a effective navigation.
I want to optimize this code to get better round values depending on the distance to current page.
I played with $r and $c to adjust the result. $c is the adjusted centerpoint to get round values.
for exsample with current_page=1 or 1000 i get a perfect result:
[1] 2 3 .. 10 .. 20 .. 50 .. 100 .. 500 .. 1000 .. 1789 next
previous 1 .. 500 .. 900 .. 950 .. 980 .. 990 .. 998 999 [1000] 1001 1002 .. 1010 .. 1020 .. 1050 .. 1100 .. 1500 .. 1789 next
but with current_page=1350 its not perfect:
previous 1 .. 400 .. 900 .. 1300 .. 1330 .. 1340 .. 1348 1349 [1350] 1351 1352 .. 1360 .. 1370 .. 1400 .. 1450 .. 1500 .. 1789 next
the first 3 step values from current page in both directions are ok, but the values 900 and 400 are strange. 500 and 1000 would be better.
i have to adjust the range $r and the dynamic centerpoint $c better, but i can´t find a elegant solution.
please help.
<?
function pagination_test(){
$page_var = "current_page";
$cur_page = isset($_GET[$page_var]) ? $_GET[$page_var] : 1;
$page_count = 1789; // count of pages for test
$steps = Array(10,20,50,100,500,1000,2000,5000,10000); // steps around current page for effective navigation in many results
$link_count = 3; // link count direct around current page
$stepspace = ".. ";
$pagelinks = ""; $space = $stepspace; // set output & spacer
if($page_count > 1 && $cur_page > 1)
$pagelinks .= "<a href='?{$page_var}=".($cur_page-1)."'>previous</a> "; // previous page
for($f=1; $f<=$page_count; $f++){
// here is my problem
$r = pow(10,strlen((string)abs($f-$cur_page)+1)-1); // get range - distance to cur-page? (10,100,1000,10000)
$c = round($cur_page/$r)*$r; // get center point for dynamic step - snap to range
if($cur_page==$f) $pagelinks .= "<a class=current>[{$f}]</a> "; // current page
else if( $f == 1 || $f == $page_count || $link_count > abs($f-$cur_page) || in_array(abs($f-$c), $steps)){
$pagelinks .= "<a href='?{$page_var}={$f}'>{$f}</a> "; // stepped & selected
$space = $stepspace." "; //set spacer for next step
}else{
$pagelinks .= $space;
$space = ""; // only one spacer behind steps
}
}
if($page_count > 1 && $cur_page < $page_count)
$pagelinks .= "<a href='?{$page_var}=".($cur_page+1)."'>next</a>"; // next page
return trim($pagelinks);
}
echo pagination_test();
?>
Related
What is the logic behind google's pagination behaviour?
My paginator goes something like this:
[1] 2 3 ... 184 >
< 1 [2] 3 4 ... 184 >
< 1 2 [3] 4 5 ... 184 >
< 1 2 3 [4] 5 6 ... 184 >
< 1 ... 3 4 [5] 6 7 ... 184 >
< 1 ... 4 5 [6] 7 8 ... 184 >
< 1 ... 5 6 [7] 8 9 ... 184 >
< 1 ... 6 7 [8] 9 10 ... 184 >
Here is a live version of the above example: http://www.dev.thomaskile.me/?page=test-zone&module=Paginator.
I know why this is happening; I've set the amount of page numbers to be shown on each side of current page to two (2).
I would rather have the range of numbers to be equal like this:
[1] 2 3 4 5 6 7 8 ... 184 >
< 1 [2] 3 4 5 6 7 ... 184 >
< 1 2 [3] 4 5 6 7 ... 184 >
< 1 2 3 [4] 5 6 7 ... 184 >
< 1 ... 3 4 [5] 6 7 ... 184 >
< 1 ... 4 5 [6] 7 8 ... 184 >
< 1 ... 5 6 [7] 8 9 ... 184 >
< 1 ... 6 7 [8] 9 10 ... 184 >
It's at the beginning and the end I need to make some changes, but can't figure out how to make it an easy operation...
I would like to make it flexible as well. Meaning I would like to be able to change the number of wanted pages on each side, and have the script expand and calculate it all...
Here is my code so far:
/**
* page controller buttons
* #param str $this->querySting href="URL string"
* #param str $this->pageIdentifier $_GET['this-name']
* #param int $this->numPages Total amount of pages
* #param int $this->midRange Number of pages to show on each side of current page
*/
public function prevPage()
{
if ($this->currentPage > 1){
$prevPage = ($this->currentPage - 1);
return 'prev';
}
}
public function nextPage()
{
if ($this->currentPage < $this->numPages) {
$nextPage = $this->currentPage + 1;
return 'next';
}
}
public function firstPage()
{
if ($this->currentPage > ($this->midRange + 1)) { // if number of pages between "currentPage" and "firstPage" exceeds $midRange with 1...
$firstPage .= '1'; // ...show "first page"-link
if ($this->currentPage > ($this->midRange + 2)) { // if number of pages between $currentPage and "first page" exceeds $midRange with more than 1
$firstPage .= '…'; // add "..." between "1st page"-link and first page in $range
}
}
return $firstPage;
}
public function lastPage()
{
if ($this->currentPage < ($this->numPages - $this->midRange)) { // if number of pages between "currentPage" and "last page" is equal to $midRange
if (($this->currentPage < ($this->numPages - $this->midRange) - 1)) { // if number of pages between $currentPage and "last page" exceeds $range with more than two
$lastPage .= '…'; // add "..." between "last page"-link and last page in $range
}
$lastPage .= ''.$this->numPages.''; // show "last page"-link
}
return $lastPage;
}
# Range of pages between (prev first ...) and (... last next)
public function listPages()
{
for ($i = ($this->currentPage - $this->midRange); $i < (($this->currentPage + $this->midRange) + 1); $i++){
if (($i > 0) && ($i <= $this->numPages)) // if page number are within page range
{
if ($i == $this->currentPage) { $listPages .= '<a class="current">'.$i.'</a>'; } // if we're on current page
else { $listPages .= ''.$i.''; } // if not current page
}
}
return $listPages;
}
This is what I do for my Pagination.
$startPage = $currentPage - 4;
$endPage = $currentPage + 4;
if ($startPage <= 0) {
$endPage -= ($startPage - 1);
$startPage = 1;
}
if ($endPage > $totalPage)
$endPage = $totalPage;
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
I believe my code is self-explained, but I will try to explain it in plain English. First of all, you need to know two things before you can generate Pagination: $totalPage and $currentPage.
Step 1: Assuming that the current page is in mid-range. $startPage and $endPage store range of page that pagination try to generate.
Step 2: If $startPage is negative, then you need to make-up for $endPage.
Step 3: If $endPage excess $totalPage, then $endPage is the last page.
Step 4: Generating Pagination into HTML. (it is up to you how you want your pagination to look. I will simply use plain text to represent my pagination)
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
Fixed flaw to my previous logic
$startPage = ($curPage < 5)? 1 : $curPage - 4;
$endPage = 8 + $startPage;
$endPage = ($totalPage < $endPage) ? $totalPage : $endPage;
$diff = $startPage - $endPage + 8;
$startPage -= ($startPage - $diff > 0) ? $diff : 0;
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
This conversation was a great start for me! But I wanted a paginator closer to the intentions of the original question, that:
1) Could be contained in a function with variables to alter the total pages, current page, and number of pages on each side of the current to show.
2) Maintains a constant width, similar to the original post:
< [1] 2 3 4 5 6 7 ... 99 >
< 1 [2] 3 4 5 6 7 ... 99 >
< 1 2 [3] 4 5 6 7 ... 99 >
< 1 2 3 [4] 5 6 7 ... 99 >
< 1 2 3 4 [5] 6 7 ... 99 >
< 1 ... 4 5 [6] 7 8 ... 99 >
< 1 ... 5 6 [7] 8 9 ... 99 >
< 1 ... 92 93 [94] 95 96 ... 99 >
< 1 ... 93 94 [95] 96 97 98 99 >
< 1 ... 93 94 95 [96] 97 98 99 >
< 1 ... 93 94 95 96 [97] 98 99 >
< 1 ... 93 94 95 96 97 [98] 99 >
< 1 ... 93 94 95 96 97 98 [99] >
3) Continues to display the number "2" rather than "..." in cases where you would have 1 ... 3
4) Same thing for the end.
So here's what I did. I am coding in a different language (coffeescript), but it should function as good sudo-code anyway:
get_pages_array = (total_page, each_side, curr_page) ->
if total_page <= (2*each_side)+5
# in this case, too few pages, so display them all
start_page = 1
end_page = total_page
else if curr_page<=each_side+3
# in this case, curr_page is too close to the beginning
start_page = 1
end_page = (2*each_side)+3
else if curr_page >= total_page - (each_side+2)
# in this case, curr_page is too close to the end
start_page = total_page - (2*each_side) - 2
end_page = total_page
else
# regular case
start_page = curr_page - each_side
end_page = curr_page + each_side
return_me = []
if start_page> 1
return_me.push "1"
if start_page>2
return_me.push "..."
for x in [start_page..end_page]
return_me.push x
if end_page<total_page-1
return_me.push "..."
if end_page<total_page
return_me.push total_page
return return_me
I am using this code for each_side = 2, so that's where I'm sure it works.
EDIT: fixed logic as per #Vextil
Here's a Python program that shows how to do this correctly:
def main():
num_pages = 13
page = 12
window = 5
start = page - window
end = page + window - 1
if start <= 0:
end = end - start + 1
start = 1
if end > num_pages:
end = num_pages
start = max(end - (window * 2) + 1, 1)
for no in range(start, end + 1):
print "{}*".format(no) if page == no else no
if __name__ == '__main__':
main()
This is pure awesome! I think I got this paginator to work the way I described.
Please, have a look and try it out here http://dev.thomaskile.me/?page=test-zone&module=Paginator and let me know...
After a lot of logical math studying I finally came to this conclusion:
In order to make this act so differently on different levels, there have to be some if, elsef-s to handle the logic on each level seperatly. I'll try to explain, but find it hard to do in a good way...
These are the levels I'm talking about:
If currentPage == firstPage :
Calculate how many pages to show after currentPage starting from 2nd page.
This calculation needed to be done based on how many page boxes there would be at the most. (midRange value is a key factor here)
[1] 2 3 4 5 6 7 8 ... 184 >
elseif currentPage is in between firstPage and midRange value maxed out.
Reduce pages in range by one to prevent moving the whole paginator to the right once prevPage is added.
Calculate pages to show before and after currentPage to keep the amount of pages equal trough the whole thing.
< 1 [2] 3 4 5 6 7 ... 184 >
< 1 2 [3] 4 5 6 7 ... 184 >
< 1 2 3 [4] 5 6 7 ... 184 >
elseif midRange value is maxed out on each side. Meaning we're in the middle somewhere.
midRange pages + the current page + midRange pages. Quite straight forward i guess...
< 1 ... 3 4 [5] 6 7 ... 184 >
...
...
...
< 1 ... 178 179 [180] 181 182 ... 184 >
elseif currentPage is in between midRange value and lastPage
Almost the same as in the beginning. Difference was to calculate a static pagenumber to start pages from, then calculate pages to show before/after current page...
(this, by the way, has been my headache this weekend)
< 1 ... 178 179 180 [181] 182 183 184 >
< 1 ... 178 179 180 181 [182] 183 184 >
< 1 ... 178 179 180 181 182 [183] 184 >
elseif currentPage == numPages (number of tatal pages).
Pretty much same as firstPage operation... calculating how many pages needed to fill the whole thing up and calculate where to start from...
What I need to do now is to make the code itself better...
< 1 ... 178 179 180 181 182 183 [184] >
The "problem" in my case was that the whole paginator should calculate everything based on the midRange value and nothing else.
For me to execute this paginator in any of my future project, all I have to do is:
$paginator = new paginator((int)); // e.g. number of total results from a db request
I might in most cases need to add a personal querystring to make sure the a href is working:
$paginator->set_queryString('my querystring');
And that's pretty much all. I've set up a couple of optional functions like this:
$paginator->set_resultsPerPage((int));
$paginator->set_midRange((int));
$paginator->set_pageIdentifier('querystring-pageNumber-identifier-name-for-get'); // whatever I needed
Finally i display the paginator page controller like this:
$paginator->pageController('full'); // full, med, min for different styles.
If non of these are good enough, i could just call each button like this:
$paginator->prevPage();
$paginator->firstPage();
$paginator->listPages();
$paginator->lastPage();
$paginator->nextPage();
$paginator->pageJumper();
$paginator->perPageSelector();
I assume your pagination have this structure:
number_of_active_page + separate(...) + page(184) + next_page(>)
You can set number_of_active_page become 8
( include prev_page(<) + pages ( ... and page number )
[1] 2 3 4 5 6 7 8 ... 184 >
[number_of_active_page(set to 8)] + separate + page + next_page
< 1 ... 3 4 [5] 6 7 ... 184 >
import math
size = 3
len = 13
for page in range(1,10):
if(( size*(page-1) ) >len):
startPoint = (size*(page-1)) - (size*(page- math.ceil(len/size)))
else:
startPoint = ( size*(page-1) )
if((startPoint +size)>len):
endPoint = len
else:
endPoint = (startPoint +size -1)
print("Page = "+str(page))
print("start = " +str(startPoint))
print("end = " +str(endPoint))
print()
Hear is a simple example of pagination display:
$paginationDisplay = ""; // Initialize the pagination output variable
// This code runs only if the last page variable is not equal to 1,
// if it is only 1 page we require no paginated links to display
if ($lastPage != "1"){
// This shows the user what page they are on, and the total number of pages
$paginationDisplay .= 'Page <strong>' . $pn .
'</strong> of ' . $lastPage. 'last';
// If we are not on page 1 we can place the Back button
if ($pn != 1) {
$previous = $pn - 1;
$paginationDisplay .= ' <a href="' .
$_SERVER['PHP_SELF'] . '?pn=' . $previous . '"> Back</a> ';
}
// Lay in the clickable numbers display here between the Back and Next links
$paginationDisplay .= '<span>' . $centerPages . '</span>';
// If we are not on the very last page we can place the Next button
if ($pn != $lastPage) {
$nextPage = $pn + 1;
$paginationDisplay .= ' <a href="' .
$_SERVER['PHP_SELF'] . '?pn=' . $nextPage . '"> Next</a> ';
}
}
This is the pagination logic I have
$pLinks = 5; // Links per page
$pMids = 3;
$pTot = 10; // Total page
$pSel = 1 // Selected page
if (($pSel <= $pMids) || ($pTot <= $pLinks)) {
$sPage = 1;
$ePage = ($pTot <= $pLinks) ? $pTot : $pLinks;
} else {
$etPage = $pSel + ($pMids - 1);
$ePage = ($etPage <= $pTot) ? $etPage : $pTot;
$sPage = $ePage - ($pLinks - 1);
}
if ($pSel > $sPage) {
$sL = 'First';
$sN = '«';
} else {
$sL = 'First';
$sN = '«';
}
if ($pSel < $ePage) {
$eL = 'End';
$eN = '»';
} else {
$eL = 'End';
$eN = '»';
}
$pOptions = '';
$pOptions .= '<span class="iPage">'.$pSel.'/'.$pTot.'</span>';
$pOptions .= '<span class="renderFL">'.$sL.'</span>';
$pOptions .= '<span class="renderPN">'.$sN.'</span>';
for ($i = $sPage; $i <= $ePage; $i++) {
if($i != $pSel) {
$pOptions .= '<span>'.$i.'</span>';
} else {
$pOptions .= '<span class="selected">'.$i.'</span>';
}
}
$pOptions .= '<span class="renderPN">'.$eN.'</span>';
$pOptions .= '<span class="renderFL">'.$eL.'</span>';
The result would be look like this:
1 -> [1] 2 3 4 5
2 -> 1 [2] 3 4 5
3 -> 1 2 [3] 4 5
..
5 -> 3 4 [5] 6 7
6 -> 4 5 [6] 7 8
..
8 -> 6 7 [8] 9 10
9 -> 6 7 8 [9] 10
10 -> 6 7 8 9 [10]
.
//Prev
.
for($number = 1; $number <= $num_pages; $number++)
{
if($page == $number)
{
$navigator .= "<b>[$number]</b> ";
}
else
{
$navigator .= "<a href='?c=".$_SESSION['cID']".&rows=".$per_page."&page=$number'>$number</a> ";
}
}
.
//Next
.
This is the snippet that prints number of pages.
Sample output:
Previous 1 2 3 4 [5] 6 7 8 9 10 Next
5 is the current page.
Problem: page numbers are shown in sequence with no restrictions. If i have 100 pages, all numbers show up.
Question: I need my paging numbers appear as the following...
Assume we only have 7 ($num_pages) pages:
Previous 1 2 [3] 4 5 6 7 Next
Assume we have 90 pages:
[1] 2 3 4 5 6 7 ... 90 Next
Assume user clicked the 7th page:
Previous 1 ... 5 6 [7] 8 9 10 11 ... 90 Next
Assume user clicked 11th page:
Previous 1 ... 9 10 [11] 12 13 14 15 ... 90 Next
Assume user clicked 15th page:
Previous 1 ... 13 14 [15] 16 17 18 19 ... 90 Next
Assume user clicked 90th page:
Previous 1 ... 84 85 86 87 88 89 [90]
Any help will be appreciated.
$radius = 3;
for($i = 1; $i <= $total; $i++){
if(($i >= 1 && $i <= $radius) || ($i > $current - $radius && $i < $current + $radius) || ($i <= $total && $i > $total - $radius)){
if($i == $current) echo "<b>".$i."</b>";
}
elseif($i == $current - $radius || $i == $current + $radius) {
echo "... ";
}
}
This should be more than enough to get you started at least
$count = 7; // number to show
// start at half threshold down from the current location.
$number = $current - round($count/2);
if( $number > 1 ) echo '...';
else $ // increase to have number start at 1.
for( $number; $number < $number + $count; $number++)
{
// your for loop as normal
}
if( $number < $total ) echo '...';
An elegant solution for this kind of thing is to use "logarithmic page navigation". See my answer to this question (PHP code included):
How to do page navigation for many, many pages? Logarithmic page navigation
i'm a newbie in php especially on making pagination.
my question is, how to make paging like stackoverflow's pagination?
i mean paging like this :
1 ... 5 6 7 8 9 ... 25
(the first number and the last number is always appear, but in the middle only 5 numbers with the selected page absolutely in the middle)
in php i have tried making paging,
<?php
//Show page links
for($i=1; $i<=$pages; $i++)
{
echo '<li id="'.$i.'">'.$i.'</li>';
}
?>
but it will be shown all of pages like
1 2 3 4 5 6 7 8 9 10 etc
any body have simple logic example to solve this problem?
many thanks :)
This will generate the numbers as per above with current = 7, pages = 25. Replace the numbers with links to get an actual pagination index.
$current = 7;
$pages = 25;
$links = array();
if ($pages > 3) {
// this specifies the range of pages we want to show in the middle
$min = max($current - 2, 2);
$max = min($current + 2, $pages-1);
// we always show the first page
$links[] = "1";
// we're more than one space away from the beginning, so we need a separator
if ($min > 2) {
$links[] = "...";
}
// generate the middle numbers
for ($i=$min; $i<$max+1; $i++) {
$links[] = "$i";
}
// we're more than one space away from the end, so we need a separator
if ($max < $pages-1) {
$links[] = "...";
}
// we always show the last page
$links[] = "$pages";
} else {
// we must special-case three or less, because the above logic won't work
$links = array("1", "2", "3");
}
echo implode(" ", $links);
Output:
1 ... 5 6 7 8 9 ... 25
Below is a snippet from a general pagination class1 I wrote a few years ago. I have edited it to show the relevant parts only.
// cntAround is the number of pages to show before and after the current
function renderNavigation($cntAround = 1) {
$out = '';
$isGap = false; // A "gap" is the pages to skip
$current = // Current page
$cntPages = // Total number of pages
for ($i = 0; $i < $pages; $i++) { // Run through pages
$isGap = false;
// Are we at a gap?
if ($cntAround >= 0 && $i > 0 && $i < $cntPages - 1 && abs($i - $current) > $cntAround) { // If beyond "cntAround" and not first or last.
$isGap = true;
// Skip to next linked item (or last if we've already run past the current page)
$i = ($i < $current ? $current - $cntAround : $cntPages - 1) - 1;
}
$lnk = ($isGap ? '...' : ($i + 1)); // If gap, write ellipsis, else page number
if ($i != $current && !$isGap) { // Do not link gaps and current
$lnk = '' . $lnk . '';
}
$out .= "\t<li>" . $lnk . "</li>\n"; // Wrap in list items
}
return "<ul>\n" . $out . '</ul>'; // Wrap in list
}
Example 1
cntAround = 1, current = 5, cntPages = 9:
[1] ... [4] 5 [6] ... [9]
Example 2
cntAround = 3, current = 5, cntPages = 11:
[1] [2] [3] [4] 5 [6] [7] [8] ... [11]
1) Article is in Danish. Google Translate'd version is here.
Somewhat like this(pseudo-code):
pg = CurrentPageNo
low = 1
high = MAX_PAGES
if (pg-low <=5)
output 1 to pg-1 [with links]
else
output 1..3 [with links]
output "..."
output (pg-3) to (pg-1) [with links]
output pg
if (high - pg <=5)
output pg+1 to high [with links]
else
output (pg+1) to high-3 [with links]
output "..."
output (high-2) to high [with links]
You could use Zend_Paginator to do just that, and learn to use the Zend Framework while you're at it.
Below is php classes link from where you can download php class for pagination.
http://www.phpclasses.org/search.html?words=paging&x=0&y=0&go_search=1
If you (might potentially) have a large number of pages, consider using "logarithmic" page navigation, as described here (sample code included):
How to do page navigation for many, many pages? Logarithmic page navigation
(Note that it'll work just fine for small numbers of pages, too, of course!)
I need some help. I want to create one tournament. Let's say I have 6 players. 1 2 3 4 5 6
I want to create some.. lets' say stages... Every player will play 5 matches(number of players - 1), in 5 different stages. In one stage, all the players must appear only once.
For example, with 6 players I want to generate these results:
Squad 1:
1-2
3-4
5-6
Squad 2:
1-3
2-5
4-6
Squad 3:
1-4
2-6
3-5
Squad 4:
1-5
2-4
3-6
Squad 5:
1-6
2-3
4-5
So, in every stage, the matches must be unique, and every player must play with every player.
I want one algorithm that will work even if I want 8 players, or 12, or 16, or 28.
Thanks
<?php
$numplayers = 6;
if ($numplayers % 2 != 0) $numplayers++; // Dummy
for ($round = 0;$round < $numplayers - 1;$round++) {
echo 'Squad ' . ($round+1) . ":\n\n1-";
for ($i = 0;$i < $numplayers-1;$i++) {
if ($i % 2 == 0) {
$player = ($numplayers-2) - ($i/2) - $round;
} else {
$player = ((($i-1)/2) - $round);
}
if ($player < 0) $player += $numplayers - 1;
echo ($player+2);
echo ($i % 2 == 0) ? "\n" : '-';
}
echo "\n\n";
}
I have the following method that creates and returns markup for my pagination links in PHP.
public function getPaginationLinks($options) {
if($options['total_pages'] > 1) {
$markup = '<div class="pagination">';
if($options['page'] > 1) {
$markup .= '< prev';
}
for($i = 1; $i <= $options['total_pages']; $i++) {
if($options['page'] != $i) {
$markup .= '' . $i . '';
}
else {
$markup .= '<span class="current">' . $i . '</span>';
}
}
if($options['page'] < $options['total_pages']) {
$markup .= 'next >';
}
$markup .= '</div>';
return $markup;
}
else {
return false;
}
}
I just recently discovered (to my surprise) that i had reached 70+ pages which means that there are now 70+ links showing up at the bottom..
I'm wondering if someone can help me break this up.. I'm not sure how most pagination works as far as showing the numbers if im on say.. page 30, ideas?
You just display the current page plus the previous and the following x (say 4) pages.
If you're on Page 1:
1 2 3 4 5
Page 35:
31 32 33 34 35 36 37 38 39
Page 70:
66 67 68 69 70
You could also add a quick link to the first and last page using « and » for instance.
Example:
$x = 4;
for ($i = $currentPage - $x; $i < $currentPage; $i++)
{
if ($i >= 1) { /* show link */}
else { /* show ellipsis and fix counter */ $i = 1; }
}
/* show current page number without link */
for ($i = $currentPage + 1; $i < $currentPage + $x; $i++)
{
if ($i <= $totalPages) { /* show link */}
else { /* show ellipsis and break */ break; }
}
You can also implement Infinite History / Pagination, which is uber cool. =)
UPDATE: A more elegant version of this # Codepad.
You could do (on page 15)
[View Previous] 12 13 14 [15] 15 17 18 [View More]
Where the [View More] link fetches the rest (or just a few more) page links. This keeps things uncluttered while allowing the user to navigate all the pages.
Example (after clicking View Previous)
1 2 3 4 5 6 7 8 9 10 11 12 13 14 [15] 15 17 18 [View More]
or (just show a few more)
[View More] 7 8 9 10 11 12 13 14 [15] 15 17 18 [View More]
When I say "fetch" I mean use javascript to create links to the other pages w/o reloading the page
Consider "logarithmic pagination", as described here (PHP code included):
How to do page navigation for many, many pages? Logarithmic page navigation
You may also look at Zend_Paginator, which handles lots of these types of things for you.