I have some problems using stripslashes() on array.
Here is my array :
$tabRegion = array(
1=>"Alsace",
2=>"Aquitaine",
3=>"Auvergne",
4=>"Basse-Normandie",
5=>"Bourgogne",
6=>"Bretagne",
7=>"Centre",
8=>"Champagne-Ardenne",
9=>"Corse",
10=>"Franche-Comté",
(...)
21=>"Provence-Alpes-Côte d'Azur",
22=>"Rhône-Alpes",);
In order to stripslash, I have adapted this PHP code :
foreach ($tabRegion as $key=>$region) {
$tabRegion[$key] = stripslashes($region);
}
After in the file, I generate URL with it for example :
if (file_exists('../region/$tabRegion[$region]/$fonction/messages/$lecturefichier (...)
But the fact is that the last value of the array is always selected ("Rhône-Alpes") by the code... I don't know why.
Do you have an idea? :)
Thank you !
You are using foreach loop then you have to generate url in that loop.
In that loop you will get each region value
$tabRegion = array(
1=>"Alsace",
2=>"Aquitaine",
3=>"Auvergne",
4=>"Basse-Normandie",
5=>"Bourgogne",
6=>"Bretagne",
7=>"Centre",
8=>"Champagne-Ardenne",
9=>"Corse");
foreach ($tabRegion as $key=>$region)
{
$tabRegion[$key] = stripslashes($region);
print "<br>".$region;
}
Output will be :
Alsace
Aquitaine
Auvergne
Basse-Normandie
Bourgogne
Bretagne
Centre
Champagne-Ardenne
Corse
So that,you have to insert following line in that for loop :
if (file_exists('../region/$tabRegion[$region]/$fonction/messages/$lecturefichier (...)
You are using $region variable in foreach loop and you should know that it is treated like any other variable in your script. So for example:
$fruit = 'Banana';
foreach(array('Tomato', 'Orange') as $fruit) {
echo $fruit;
}
echo $fruit; // it will output 'Orange';
Related
I need to get values of array through a loop with dynamic vars.
I can't understand why the "echo" doesn’t display any result for "$TAB['b']".
Do you know why ?
The test with error message : https://3v4l.org/Fp3GT
$TAB_a = "aaaaa";
$TAB['b'] = "bbbbb";
$TAB['b']['c'] = "ccccc";
$TAB_paths = ["_a", "['b']", "['b']['c']"];
foreach ($TAB_paths as $key => $value) {
echo "\n\n\${'TAB'.$value} : "; print_r(${'TAB'.$value});
}
You are treating the array access characters as if they are part of the variable name. They are not.
So if you have an array $TAB = array('b' => 'something');, the variable name is $TAB. When you do ${'TAB'.$value}, you're looking for a variable that's actually named $TAB['b'], which you don't have.
Since you say that you just want to be able to access array indexes dynamically based on the values in another array, you just put the indexes alone (without the array access characters) in the other array.
$TAB['b'] = 'bbbbbb';
$TAB['c'] = 'cccccc';
$TAB_paths = array('b', 'c');
foreach ($TAB_paths as $key => $value) {
echo "\n\n".'$TAB['."'$value'".'] : ' . $TAB[$value];
}
Output:
$TAB['b'] : bbbbbb
$TAB['c'] : cccccc
DEMO
It's unclear what you're trying to do, although you need to include $TAB_all in $TAB_paths:
$TAB_paths = [$TAB_all['a'], $TAB_all['aside']['nav']];
Result:
${TAB_all.aaaaa} : ${TAB_all.bbbbb} :
Not certain what you're needing. My guess you need to merge two arrays into one. Easiest solution is to use the array_merge function.
$TAB_paths = array_merge($TAB_a1, $TAB_a2);
You can define the variable first
foreach ($TAB_all as $key => $value) {
${"TAB_all" . $key} = $value;
}
Now Explore the result:
foreach ($TAB_all as $key => $value) {
print_r(${"TAB_all" . $key});
}
I have an array composed of files of a folder.
When I use the following snippet :
foreach($myarray as $key => $value)
{
echo $value. "<br>";
}
I have the following output :
vendor/templates/File1.docx
vendor/templates/File2.docx
vendor/templates/File3.docx
My question is : how to make it to put each value of my array in a new variable ? How to make it automatically if I have e.g 100 files in my folder ?
Actually I'd like to have (if my array is only composed of 3 items) :
$a = 'vendor/templates/File1.docx'
$b = 'vendor/templates/File2.docx'
$c = 'vendor/templates/File3.docx'
I guess I should use a loop but after many tests, I'm still getting stuck..
Have you any ideas ?
Thanks !!
Here is the solution:
<?php
$myarray = ['vendor/templates/File1.docx', 'vendor/templates/File2.docx', 'vendor/templates/File3.docx'];
foreach($myarray as $key => $value)
{
$varname = "var".$key;
$$varname = $value;
}
echo $var0."\n";
echo $var1."\n";
echo $var2."\n";
->
vendor/templates/File1.docx
vendor/templates/File2.docx
vendor/templates/File3.docx
May be following function will work for your problem.
extract($array);
http://php.net/extract
In PHP I am getting an array from foreach. I am JSON encoding and showing all the results at once. This works fine. But what if I need to display array items one by one as foreach still continues?
<?php
$array = //somearray;
$data_arr = array();
foreach($array as $arr){
//do something
$data_arr[] = $arr;
}
echo json_encode(array('success'=>true,'data'=>$data_arr));
//here i can display the data in my jquery using each function
//i can display the whole data at once after the foreach is completed
//what i need is i want to display first element of data_arr after its loop is completed and then the second element and so on
?>
Did you try http://www.php.net/array_shift ? its php function you need to call this function after foreach
<?php
foreach($array as $arr){
//do something
$data_arr[] = $arr;
}
print_r array_shift($data_arr);
//Print First array value from this $data_arr list.
?>
Thanks.
What you looking for is Streaming Response.
Checkout following link to learn how to do that.
https://www.sitepoint.com/php-streaming-output-buffering-explained/
I have the below code
$student_IT_vitipare = mysql_query("SELECT * from notat where dega='teknologji informacioni' AND viti_lendes='viti pare' ");
$vekt_stud_IT_vitipare = array();
while ($kolo1 = mysql_fetch_array($student_IT_vitipare)) {
$vekt_stud_IT_vitipare[] = $kolo1;
}
$gjatesia_vektorit = count($vekt_stud_IT_vitipare);
EXAMPLE: Array take from database name,last name and it has {john,trevis}{george,trolus} {dionis,karrblus} etc...
I know that if i want to echo out only name the code is :
for($i=0;i<$gjatesia_vektorit;i++){
echo $vekt_stud_IT_vitipare[$i]['name'];
}
i've tryed $vekt_stud_IT_vitipare[$i]['name']['last name']; but it does not work
you should stop using mysql_* because it's removed on php 7.0 instead use mysqli_* or PDO
your code won't work but instead if you do something like
for($i=0;i<$gjatesia_vektorit;i++){
echo $vekt_stud_IT_vitipare[$i][$i];
}
it would but you will only one value
instead you need a nested foreach loop
foreach($vekt_stud_IT_vitipare as $key => $value) {
foreach ($value as $val) {
echo $val;
}
}
Share the exact sample array which you want to compare. I will try to solve the problem. The one you shared is not sufficient.
The below array sample i need:
$vekt_stud_IT_vitipare
I have the following JSON structure
{"Id":"1","Persons":[{"Name":"Carl","Time":"00:00:03","info":"","Timeext":"","Timeout":"","Timein":""}, {"Name":"Carl","Time":"00:00:03","info":"","Timeext":"","Timeout":"","Timein":""}{"Name":"Luis","Time":"00:00:08","info":"","Timeext":"","Timeout":"","Timein":""}]}
How I can have acces or read the item inside the nest? For example if I just want the value of time for Carl or all information about Carl. Till now I just can get without a problem the single item in the collection 'Id'. The rst nested items not.
I tryed with json_decode like this:
if( $_POST ) {
$arr['Id'] = $_POST['Id'];
$arr['NP'] = $_POST['NP'];
$jsdecode = json_decode($arr);
foreach ($jsdecode as $values){
echo $values->Time;
}
Can PLEASE somebody help me?
if( $_POST ) {
$arr['Id'] = $_POST['Id'];
$arr['NP'] = $_POST['NP'];
$jsdecode = json_decode($arr,true);
foreach ($jsdecode as $values){
echo $values->Time;
}
Adding 'true' to json_decode converts it to array
You are processing it correct , Just add true as the second parameter to json_decode which will be converted to an Array like
$jsdecode = json_decode($arr,true);