mySQL to PHP dynamic table - php

Question

This question has been asked many times but I'm sorry I still can't make it work.
I have a simple mySQL DB like this table:
In this DB I have a column with people and 3 other columns that represent days - Day 1, Day 2 and Day 3.
The letter "M" means Morning and "A" Afternoon.
So I want to query this DB and ask: "Who was working Day 1 in the morning?" and it returns "John".
I know how to do this query, but I don't know how to format the return.
Let's say that 3 people worked Day 1 morning (because the actual DB is bigger then this one) I want the HTML to return a 3 row table stating their names, but if only 2 persons worked Day one in the morning, it would return only a 2 row table stating their names.
This is my PHP:
<?php
$con = mysql_connect(".",".",".");
$db_selected = mysql_select_db("xbizh_14391723_horario", $con);
$sql = "SELECT `AM` FROM HORARIO WHERE `1` ='N'";
$result = mysql_query($sql);
$num = mysql_numrows($result);
if (!$result) {
$message = 'Invalid query: ' . mysql_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
}
while($row = mysql_fetch_array($result))
{
print_r($row);
}
mysql_free_result($result);
?>

Answer 1

It seems to me you are most of the way there already.
print("<table>");
while($row = mysql_fetch_array($result))
{
print("<tr><td>" . $row['name_field'] . "</td></tr>");
}
print("</table>");
You also need to make sure your query is returning the name field.
$sql = "SELECT * FROM HORARIO WHERE `1` ='N'";
or
$sql = "SELECT `name_field` FROM HORARIO WHERE `1` ='N'";