How can I remove last digit from decimal number in PHP - php

I want to remove last digit from decimal number in PHP.
Lets say I have 14.153. I want it to be 14.15. I will do this step till my number is no longer decimal.


I think this should work:
<?php
$num = 14.153;
$strnum = (string)$num;
$parts = explode('.', $num);
// $parts[0] = 14;
// $parts[1] = 153;
$decimalPoints = strlen($parts[1]);
// $decimalPoints = 3
if($decimalPoints > 0)
{
for($i=0 ; $i<=$decimalPoints ; $i++)
{
// substring($strnum, 0, 0); causes an empty result so we want to avoid it
if($i > 0)
{
echo substr($strnum, 0, '-'.$i).'<br>';
}
else
{
echo $strnum.'<br>';
}
}
}
?>


echo round(14.153, 2); // 14.15
The round second parameter sets the number of digits.


You can try this.
Live DEMO
<?php
$number = 14.153;
echo number_format($number,2);

Related

How to convert word to number using my function?

I created this function to converting numbers to words. And how I can convert words to number using this my function:
Simple function code:
$array = array("1"=>"ЯК","2"=>"ДУ","3"=>"СЕ","4"=>"ЧОР","5"=>"ПАНҶ","6"=>"ШАШ","7"=>"ҲАФТ","8"=>"ХАШТ","9"=>"НӮҲ","0"=>"НОЛ","10"=>"ДАҲ","20"=>"БИСТ","30"=>"СИ","40"=>"ЧИЛ","50"=>"ПАНҶОҲ","60"=>"ШАСТ","70"=>"ҲАФТОД","80"=>"ХАШТОД","90"=>"НАВАД","100"=>"САД");
$n = "98"; // Input number to converting
if($n < 10 && $n > -1){
echo $array[$n];
}
if($n == 10 OR $n == 20 OR $n == 30 OR $n == 40 OR $n == 50 OR $n == 60 OR $n == 70 OR $n == 80 OR $n == 90 OR $n == 100){
echo $array[$n];
}
if(mb_strlen($n) == 2 && $n[1] != 0)
{
$d = $n[0]."0";
echo "$array[$d]У ".$array[$n[1]];
}
My function so far converts the number to one hundred. How can I now convert text to a number using the answer of my function?

So, as #WillParky93 assumed, your input has spaces between words.
<?php
mb_internal_encoding("UTF-8");//For testing purposes
$array = array("1"=>"ЯК","2"=>"ДУ","3"=>"СЕ","4"=>"ЧОР","5"=>"ПАНҶ","6"=>"ШАШ","7"=>"ҲАФТ","8"=>"ХАШТ","9"=>"НӮҲ","0"=>"НОЛ","10"=>"ДАҲ","20"=>"БИСТ","30"=>"СИ","40"=>"ЧИЛ","50"=>"ПАНҶОҲ","60"=>"ШАСТ","70"=>"ҲАФТОД","80"=>"ХАШТОД","90"=>"НАВАД","100"=>"САД");
$postfixes = array("3" => "ВУ");
$n = "98"; // Input number to converting
$res = "";
//I also optimized your conversion of numbers to words
if($n > 0 && ($n < 10 || $n%10 == 0))
{
$res = $array[$n];
}
if($n > 10 && $n < 100 && $n%10 != 0)
{
$d = intval(($n/10));
$sd = $n%10;
$ending = isset($postfixes[$d]) ? $postfixes[$d] : "У";
$res = ($array[$d * 10]).$ending." ".$array[$sd];
}
echo $res;
echo "\n<br/>";
$splitted = explode(" ", $res);
//According to your example, you use only numerals that less than 100
//So, to simplify your task(btw, according to Google, the language is tajik
//and I don't know the rules of building numerals in this language)
if(sizeof($splitted) == 1) {
echo array_search($splitted[0], $array);
}
else if(sizeof($splitted) == 2) {
$first = $splitted[0];
$first_length = mb_strlen($first);
if(mb_substr($first, $first_length - 2) == "ВУ")
{
$first = mb_substr($first, 0, $first_length - 2);
}
else
{
$first = mb_substr($splitted[0], 0, $first_length - 1);
}
$second = $splitted[1];
echo (array_search($first, $array) + array_search($second, $array));
}

You didn't specify the input specs but I took the assumption you want it with a space between the words.
//get our input=>"522"
$input = "ПАНҶ САД БИСТ ДУ";
//split it up
$split = explode(" ", $input);
//start out output
$c = 0;
//set history
$history = "";
//loop the words
foreach($split as &$s){
$res = search($s);
//If number is 9 or less, we are going to check if it's with a number
//bigger than or equal to 100, if it is. We multiply them together
//else, we just add them.
if((($res = search($s)) <=9) ){
//get the next number in the array
$next = next($split);
//if the number is >100. set $nextres
if( ($nextres = search($next)) >= 100){
//I.E. $c = 5 * 100 = 500
$c = $nextres * $res;
//set the history so we skip over it next run
$history = $next;
}else{
//Single digit on its own
$c += $res;
}
}elseif($s != $history){
$c += $res;
}
}
//output the result
echo $c;
function search($s){
global $array;
if(!$res = array_search($s, $array)){
//grab the string length
$max = strlen($s);
//remove one character at a time until we find a match
for($i=0;$i<$max; $i++ ){
if($res = array_search(mb_substr($s, 0, -$i),$array)){
//stop the loop
$i = $max;
}
}
}
return $res;
}
Output is 522.

Hide numbers of a phone number

How can I show and hide the some numbers of a phone number by replacing it with * like 0935***3256 by PHP?
EX:
09350943256 -> 0935***3256 09119822432 -> 0911***2432
09215421597 -> 0921***1597...
$number = '09350943256';
echo str_pad(substr($number, -4), strlen($number), '*', STR_PAD_LEFT);
Top php code result is as: *******3256 but i want result as: 0935***3256
How is it?

You could use substr and concat this way
to work for any $number with any number of n digit length
<?php
$number = "112222";
$middle_string ="";
$length = strlen($number);
if( $length < 3 ){
echo $length == 1 ? "*" : "*". substr($number, - 1);
}
else{
$part_size = floor( $length / 3 ) ;
$middle_part_size = $length - ( $part_size * 2 );
for( $i=0; $i < $middle_part_size ; $i ++ ){
$middle_string .= "*";
}
echo substr($number, 0, $part_size ) . $middle_string . substr($number, - $part_size );
}
The output if you make $number = "1" is * and if $number = "12" is *2 and for $number = "112222" is 11**22. and it goes on.

In short:
$phone = 01133597084;
$maskedPhone = substr($phone, 0, 4) . "****" . substr($phone, 7, 4);
// Output: 0113****7084

You can use substr_replace() function
<?php
$mobnum ="09350943256";
for($i=4;$i<7;$i++)
{
$mobnum = substr_replace($mobnum,"*",$i,1);
}
echo $mobnum;
?>

You can use substr() to fetch the first 4 and last 4, and add four * in the middle manually, and put it all together in a string.
$phone = "09350943256";
$result = substr($phone, 0, 4);
$result .= "****";
$result .= substr($phone, 7, 4);
echo $result;
The above would output
0935****3256
Live demo

<?php
$phone='05325225990';
function stars($phone)
{
$times=strlen(trim(substr($phone,4,5)));
$star='';
for ($i=0; $i <$times ; $i++) {
$star.='*';
}
return $star;
}
$result=str_replace(substr($phone, 4,5), stars($phone), $phone);
echo $result;
?>
0532*****90

Instead of doing the math of calculating indices, I suggest this „declarative“ solution:
<?php
$number='0123456789';
$matches=[];
preg_match('/(\\d{4})(\\d+)(\\d{4})/', $number, $matches);
$result=$matches[1].str_repeat('*',strlen($matches[2])).$matches[2];
print($result);
?>

How to display Currency in Indian Numbering Format in PHP?

I have a question about formatting the Rupee currency (Indian Rupee - INR).
For example, numbers here are represented as:
1
10
100
1,000
10,000
1,00,000
10,00,000
1,00,00,000
10,00,00,000
Refer Indian Numbering System
I have to do with it PHP.
I have saw this question Displaying Currency in Indian Numbering Format. But couldn't able to get it for PHP my problem.
Update:
How to use money_format() in indian currency format?

You have so many options but money_format can do the trick for you.
Example:
$amount = '100000';
setlocale(LC_MONETARY, 'en_IN');
$amount = money_format('%!i', $amount);
echo $amount;
Output:
1,00,000.00
Note:
The function money_format() is only defined if the system has strfmon capabilities. For example, Windows does not, so money_format() is undefined in Windows.
Pure PHP Implementation - Works on any system:
$amount = '10000034000';
$amount = moneyFormatIndia( $amount );
echo $amount;
function moneyFormatIndia($num) {
$explrestunits = "" ;
if(strlen($num)>3) {
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3); // extracts the last three digits
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits; // explodes the remaining digits in 2's formats, adds a zero in the beginning to maintain the 2's grouping.
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++) {
// creates each of the 2's group and adds a comma to the end
if($i==0) {
$explrestunits .= (int)$expunit[$i].","; // if is first value , convert into integer
} else {
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return $thecash; // writes the final format where $currency is the currency symbol.
}

$num = 1234567890.123;
$num = preg_replace("/(\d+?)(?=(\d\d)+(\d)(?!\d))(\.\d+)?/i", "$1,", $num);
echo $num;
// Input : 1234567890.123
// Output : 1,23,45,67,890.123
// Input : -1234567890.123
// Output : -1,23,45,67,890.123

echo 'Rs. '.IND_money_format(1234567890);
function IND_money_format($money){
$len = strlen($money);
$m = '';
$money = strrev($money);
for($i=0;$i<$len;$i++){
if(( $i==3 || ($i>3 && ($i-1)%2==0) )&& $i!=$len){
$m .=',';
}
$m .=$money[$i];
}
return strrev($m);
}
NOTE:: it is not tested on float values and it suitable for only Integer

The example you've linked is making use of the ICU libraries which are available with PHP in the intl Extension­Docs:
$fmt = new NumberFormatter($locale = 'en_IN', NumberFormatter::CURRENCY);
echo $fmt->format(10000000000.1234)."\n"; # Rs 10,00,00,00,000.12
Or maybe better fitting in your case:
$fmt = new NumberFormatter($locale = 'en_IN', NumberFormatter::DECIMAL);
echo $fmt->format(10000000000)."\n"; # 10,00,00,00,000

Simply use below function to format in INR.
function amount_inr_format($amount) {
$fmt = new \NumberFormatter($locale = 'en_IN', NumberFormatter::DECIMAL);
return $fmt->format($amount);
}

Check this code, it works 100% for Indian Rupees format with decimal format.
You can use numbers like :
123456.789
123.456
123.4
123
and 1,2,3,4,5,6,7,8,9,.222
function moneyFormatIndia($num){
$explrestunits = "" ;
$num = preg_replace('/,+/', '', $num);
$words = explode(".", $num);
$des = "00";
if(count($words)<=2){
$num=$words[0];
if(count($words)>=2){$des=$words[1];}
if(strlen($des)<2){$des="$des";}else{$des=substr($des,0,2);}
}
if(strlen($num)>3){
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3); // extracts the last three digits
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits; // explodes the remaining digits in 2's formats, adds a zero in the beginning to maintain the 2's grouping.
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++){
// creates each of the 2's group and adds a comma to the end
if($i==0)
{
$explrestunits .= (int)$expunit[$i].","; // if is first value , convert into integer
}else{
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return "$thecash.$des"; // writes the final format where $currency is the currency symbol.
}

When money_format is not available :
function format($amount): string
{
list ($number, $decimal) = explode('.', sprintf('%.2f', floatval($amount)));
$sign = $number < 0 ? '-' : '';
$number = abs($number);
for ($i = 3; $i < strlen($number); $i += 3)
{
$number = substr_replace($number, ',', -$i, 0);
}
return $sign . $number . '.' . $decimal;
}

<?php
$amount = '-100000.22222'; // output -1,00,000.22
//$amount = '0100000.22222'; // output 1,00,000.22
//$amount = '100000.22222'; // output 1,00,000.22
//$amount = '100000.'; // output 1,00,000.00
//$amount = '100000.2'; // output 1,00,000.20
//$amount = '100000.0'; // output 1,00,000.00
//$amount = '100000'; // output 1,00,000.00
echo $aaa = moneyFormatIndia($amount);
function moneyFormatIndia($amount)
{
$amount = round($amount,2);
$amountArray = explode('.', $amount);
if(count($amountArray)==1)
{
$int = $amountArray[0];
$des=00;
}
else {
$int = $amountArray[0];
$des=$amountArray[1];
}
if(strlen($des)==1)
{
$des=$des."0";
}
if($int>=0)
{
$int = numFormatIndia( $int );
$themoney = $int.".".$des;
}
else
{
$int=abs($int);
$int = numFormatIndia( $int );
$themoney= "-".$int.".".$des;
}
return $themoney;
}
function numFormatIndia($num)
{
$explrestunits = "";
if(strlen($num)>3)
{
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3); // extracts the last three digits
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits; // explodes the remaining digits in 2's formats, adds a zero in the beginning to maintain the 2's grouping.
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++) {
// creates each of the 2's group and adds a comma to the end
if($i==0) {
$explrestunits .= (int)$expunit[$i].","; // if is first value , convert into integer
} else {
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return $thecash; // writes the final format where $currency is the currency symbol.
}
?>

So if I'm reading that right, the Indian Numbering System separates the thousands, then every power of a hundred past that? Hmm...
Perhaps something like this?
function indian_number_format($num) {
$num = "".$num;
if( strlen($num) < 4) return $num;
$tail = substr($num,-3);
$head = substr($num,0,-3);
$head = preg_replace("/\B(?=(?:\d{2})+(?!\d))/",",",$head);
return $head.",".$tail;
}

$amount=-3000000000111.11;
$amount<0?(($sign='-').($amount*=-1)):$sign=''; //Extracting sign from given amount
$pos=strpos($amount, '.'); //Identifying the decimal point position
$amt= substr($amount, $pos-3); // Extracting last 3 digits of integer part along with fractional part
$amount= substr($amount,0, $pos-3); //removing the extracted part from amount
for(;strlen($amount);$amount=substr($amount,0,-2)) // Now loop through each 2 digits of remaining integer part
$amt=substr ($amount,-2).','.$amt; //forming Indian Currency format by appending (,) for each 2 digits
echo $sign.$amt; //Appending sign

I think this a quick and simplest solution:-
function formatToInr($number){
$number=round($number,2);
// windows is not supported money_format
if(setlocale(LC_MONETARY, 'en_IN')){
return money_format('%!'.$decimal.'n', $number);
}
else {
if(floor($number) == $number) {
$append='.00';
}else{
$append='';
}
$number = preg_replace("/(\d+?)(?=(\d\d)+(\d)(?!\d))(\.\d+)?/i", "$1,", $number);
return $number.$append;
}
}

You should check the number_format function.Here is the link
Separating thousands with commas will look like
$rupias = number_format($number, 2, ',', ',');

I have used different format parameters to money_format() for my output.
setlocale(LC_MONETARY, 'en_IN');
if (ctype_digit($amount) ) {
// is whole number
// if not required any numbers after decimal use this format
$amount = money_format('%!.0n', $amount);
}
else {
// is not whole number
$amount = money_format('%!i', $amount);
}
//$amount=10043445.7887 outputs 1,00,43,445.79
//$amount=10043445 outputs 1,00,43,445

Above Function Not working with Decimal
$amount = 10000034000.001;
$amount = moneyFormatIndia( $amount );
echo $amount;
function moneyFormatIndia($num){
$nums = explode(".",$num);
if(count($nums)>2){
return "0";
}else{
if(count($nums)==1){
$nums[1]="00";
}
$num = $nums[0];
$explrestunits = "" ;
if(strlen($num)>3){
$lastthree = substr($num, strlen($num)-3, strlen($num));
$restunits = substr($num, 0, strlen($num)-3);
$restunits = (strlen($restunits)%2 == 1)?"0".$restunits:$restunits;
$expunit = str_split($restunits, 2);
for($i=0; $i<sizeof($expunit); $i++){
if($i==0)
{
$explrestunits .= (int)$expunit[$i].",";
}else{
$explrestunits .= $expunit[$i].",";
}
}
$thecash = $explrestunits.$lastthree;
} else {
$thecash = $num;
}
return $thecash.".".$nums[1];
}
}
Answer : 10,00,00,34,000.001

It's my very own function to do the task
function bd_money($num) {
$pre = NULL; $sep = array(); $app = '00';
$s=substr($num,0,1);
if ($s=='-') {$pre= '-';$num = substr($num,1);}
$num=explode('.',$num);
if (count($num)>1) $app=$num[1];
if (strlen($num[0])<4) return $pre . $num[0] . '.' . $app;
$th=substr($num[0],-3);
$hu=substr($num[0],0,-3);
while(strlen($hu)>0){$sep[]=substr($hu,-2); $hu=substr($hu,0,-2);}
return $pre.implode(',',array_reverse($sep)).','.$th.'.'.$app;
}
It took 0.0110 Seconds per THOUSAND query while number_format took 0.001 only.
Always try to use PHP native functions only when performance is target issue.

$r=explode('.',12345601.20);
$n = $r[0];
$len = strlen($n); //lenght of the no
$num = substr($n,$len-3,3); //get the last 3 digits
$n = $n/1000; //omit the last 3 digits already stored in $num
while($n > 0) //loop the process - further get digits 2 by 2
{
$len = strlen($n);
$num = substr($n,$len-2,2).",".$num;
$n = round($n/100);
}
echo "Rs.".$num.'.'.$r[1];

If you dont want to use any inbuilt function in my case i was doing on iis server so was unable to use one the function in php so did this
$num = -21324322.23;
moneyFormatIndiaPHP($num);
function moneyFormatIndiaPHP($num){
//converting it to string
$numToString = (string)$num;
//take care of decimal values
$change = explode('.', $numToString);
//taking care of minus sign
$checkifminus = explode('-', $change[0]);
//if minus then change the value as per
$change[0] = (count($checkifminus) > 1)? $checkifminus[1] : $checkifminus[0];
//store the minus sign for further
$min_sgn = '';
$min_sgn = (count($checkifminus) > 1)?'-':'';
//catch the last three
$lastThree = substr($change[0], strlen($change[0])-3);
//catch the other three
$ExlastThree = substr($change[0], 0 ,strlen($change[0])-3);
//check whethr empty
if($ExlastThree != '')
$lastThree = ',' . $lastThree;
//replace through regex
$res = preg_replace("/\B(?=(\d{2})+(?!\d))/",",",$ExlastThree);
//main container num
$lst = '';
if(isset($change[1]) == ''){
$lst = $min_sgn.$res.$lastThree;
}else{
$lst = $min_sgn.$res.$lastThree.".".$change[1];
}
//special case if equals to 2 then
if(strlen($change[0]) === 2){
$lst = str_replace(",","",$lst);
}
return $lst;
}

This for both integer and float values
function indian_money_format($number)
{
if(strstr($number,"-"))
{
$number = str_replace("-","",$number);
$negative = "-";
}
$split_number = #explode(".",$number);
$rupee = $split_number[0];
$paise = #$split_number[1];
if(#strlen($rupee)>3)
{
$hundreds = substr($rupee,strlen($rupee)-3);
$thousands_in_reverse = strrev(substr($rupee,0,strlen($rupee)-3));
$thousands = '';
for($i=0; $i<(strlen($thousands_in_reverse)); $i=$i+2)
{
$thousands .= $thousands_in_reverse[$i].$thousands_in_reverse[$i+1].",";
}
$thousands = strrev(trim($thousands,","));
$formatted_rupee = $thousands.",".$hundreds;
}
else
{
$formatted_rupee = $rupee;
}
if((int)$paise>0)
{
$formatted_paise = ".".substr($paise,0,2);
}else{
$formatted_paise = '.00';
}
return $negative.$formatted_rupee.$formatted_paise;
}

Use this function:
function addCommaToRs($amt, &$ret, $dec='', $sign=''){
if(preg_match("/-/",$amt)){
$amts=explode('-',$amt);
$amt=$amts['1'];
static $sign='-';
}
if(preg_match("/\./",$amt)){
$amts=explode('.',$amt);
$amt=$amts['0'];
$l=strlen($amt);
static $dec;
$dec=$amts['1'];
} else {
$l=strlen($amt);
}
if($l>3){
if($l%2==0){
$ret.= substr($amt,0,1);
$ret.= ",";
addCommaToRs(substr($amt,1,$l),$ret,$dec);
} else{
$ret.=substr($amt,0,2);
$ret.= ",";
addCommaToRs(substr($amt,2,$l),$ret,$dec);
}
} else {
$ret.= $amt;
if($dec) $ret.=".".$dec;
}
return $sign.$ret;
}
Call it like this:
$amt = '';
echo addCommaToRs(123456789.123,&$amt,0);
This will return 12,34,567.123.

<?php
function moneyFormatIndia($num)
{
//$num=123456789.00;
$result='';
$sum=explode('.',$num);
$after_dec=$sum[1];
$before_dec=$sum[0];
$result='.'.$after_dec;
$num=$before_dec;
$len=strlen($num);
if($len<=3)
{
$result=$num.$result;
}
else
{
if($len<=5)
{
$result='Rs '.substr($num, 0,$len-3).','.substr($num,$len-3).$result;
return $result;
}
else
{
$ls=strlen($num);
$result=substr($num, $ls-5,2).','.substr($num, $ls-3).$result;
$num=substr($num, 0,$ls-5);
while(strlen($num)!=0)
{
$result=','.$result;
$ls=strlen($num);
if($ls<=2)
{
$result='Rs. '.$num.$result;
return $result;
}
else
{
$result=substr($num, $ls-2).$result;
$num=substr($num, 0,$ls-2);
}
}
}
}
}
?>

heres is simple thing u can do ,
float amount = 100000;
NumberFormat formatter = NumberFormat.getCurrencyInstance(new Locale("en", "IN"));
String moneyString = formatter.format(amount);
System.out.println(moneyString);
The output will be , Rs.100,000.00 .

declare #Price decimal(26,7)
Set #Price=1234456677
select FORMAT(#Price, 'c', 'en-In')
Result:
1,23,44,56,677.00

getting a fatal error on return value in ajax

I am making an ajax call in jquery
$.get("validate_isbn.php", {isbn: obj[16]},
function(answer)
{
console.log(answer);
if (answer == "valid")
{
var checked1 = $(elements[index]).val();
//$(elements[index]).val().append("<img src = 'pics/green_checkmark.png'>"); //doesn't work
//elements.after("<img src = 'pics/green_checkmark.png'>"); //sets all the elements with this pic
elements.eq(index).after("<img src='pics/green_checkmark.png' id='checkmark'>");
var checked = $(elements[index]).val();
}
});
which worked fine. I saw in the debugger that it was properly sending over the variable isbn with a isbn number from the obj array. My problem is on the php side. When I was testing, I simply had the code echo "valid" and everything worked out fine. But now when I put the real code in it stopped working:
<?php
//This algorithm is for ISBN 10
function is_isbn_10_valid($n){
$check = 0;
for ($i = 0; $i < 9; $i++)
{
$check += (10 - $i) * substr($n, $i, 1); //starting at the leftmost digit, multiple each digit by a constant, starting at 10, add the total
}
$t = substr($n, 9, 1); // tenth digit (aka checksum or check digit)
$check += ($t == 'x' || $t == 'X') ? 10 : $t; //now add the tenth digit
return $check % 11 == 0;
}
//The algorithm for ISBN 13 validation is as follows:
//Multiply each digit of teh isbn, starting at the left, with 1,3,3... etc for the entire isbn (including the check digit becuase its
//just going to be multiplied by 1 anyways.
//Add them all together, do mod 10 and voila!
function is_isbn_13_valid($n){
$check = 0;
for ($i = 0; $i < 13; $i+=2) //this does digits 1,3,5,7,9,10,11,13
{
$check += substr($n, $i, 1);
}
for ($i = 1; $i < 12; $i+=2) //this does digits 2,4,6,8,10,12
{
$check += 3 * substr($n, $i, 1);
}
return $check % 10 == 0;
}
$isbn = $_GET["isbn"];
if (strlen($isbn) = 10)
{
$result = is_isbn_10_valid($isbn);
}
else if (strlen($isbn) = 13)
{
$result = is_isbn_13_valid($isbn);
}
else
{
$result false;
}
if ($result === true)
{echo "valid";}
else if ($result === false)
{echo "not valid";}
?>
(Note: I'm sure that I can be more efficient and just return the boolean, but I refrained from that at the moment since I wasn't sure how the jquery .get would take it, as a boolean or text...)
Anyways, it doesn't work. The error on the console.log gives me:
Fatal error: Can't use function return value in write context in ...pathname here...\validate_isbn.php on line 31

On line 31, you have this:
if ($strlen($isbn) = 10)
Remove the $ on the strlen function, and change the = (assignment operator) to a == (equivalence operator). It should now look like this:
if (strlen($isbn) == 10)
You'll need to do the same a few lines after that, too.
Edit: One more thing. About five lines from the bottom, you're missing an equal sign.
$result false;
Should be:
$result = false;

IMEI validation function

Does anybody know a PHP function for IMEI validation?

Short solution
You can use this (witchcraft!) solution, and simply check the string length:
function is_luhn($n) {
$str = '';
foreach (str_split(strrev((string) $n)) as $i => $d) {
$str .= $i %2 !== 0 ? $d * 2 : $d;
}
return array_sum(str_split($str)) % 10 === 0;
}
function is_imei($n){
return is_luhn($n) && strlen($n) == 15;
}
Detailed solution
Here's my original function that explains each step:
function is_imei($imei){
// Should be 15 digits
if(strlen($imei) != 15 || !ctype_digit($imei))
return false;
// Get digits
$digits = str_split($imei);
// Remove last digit, and store it
$imei_last = array_pop($digits);
// Create log
$log = array();
// Loop through digits
foreach($digits as $key => $n){
// If key is odd, then count is even
if($key & 1){
// Get double digits
$double = str_split($n * 2);
// Sum double digits
$n = array_sum($double);
}
// Append log
$log[] = $n;
}
// Sum log & multiply by 9
$sum = array_sum($log) * 9;
// Compare the last digit with $imei_last
return substr($sum, -1) == $imei_last;
}

Maybe can help you :
This IMEI number is something like this: ABCDEF-GH-IJKLMNO-X (without “-” characters)
For example: 350077523237513
In our example ABCDEF-GH-IJKLMNO-X:
AB is Reporting Body Identifier such as 35 = “British Approvals Board of Telecommunications (BABT)”
ABCDEF is Type Approval Code
GH is Final Assembly Code
IJKLMNO is Serial Number
X is Check Digit
Also this can help you : http://en.wikipedia.org/wiki/IMEI#Check_digit_computation
If i don't misunderstood, IMEI numbers using Luhn algorithm . So you can google this :) Or you can search IMEI algorithm

Maybe your good with the imei validator in the comments here:
http://www.php.net/manual/en/function.ctype-digit.php#77718
But I haven't tested it

Check this solution
<?php
function validate_imei($imei)
{
if (!preg_match('/^[0-9]{15}$/', $imei)) return false;
$sum = 0;
for ($i = 0; $i < 14; $i++)
{
$num = $imei[$i];
if (($i % 2) != 0)
{
$num = $imei[$i] * 2;
if ($num > 9)
{
$num = (string) $num;
$num = $num[0] + $num[1];
}
}
$sum += $num;
}
if ((($sum + $imei[14]) % 10) != 0) return false;
return true;
}
$imei = '868932036356090';
var_dump(validate_imei($imei));
?>

IMEI validation uses Luhn check algorithm. I found a link to a page where you can validate your IMEI. Furthermore, at the bottom of this page is a piece of code written in JavaScript to show how to calculate the 15th digit of IMEI and to valid IMEI. I might give you some ideas. You can check it out here http://imei.sms.eu.sk/index.html

Here is a jQuery solution which may be of use: https://github.com/madeinstefano/imei-validator

good fun from kasperhartwich
function validateImei($imei, $use_checksum = true) {
if (is_string($imei)) {
if (ereg('^[0-9]{15}$', $imei)) {
if (!$use_checksum) return true;
for ($i = 0, $sum = 0; $i < 14; $i++) {
$tmp = $imei[$i] * (($i%2) + 1 );
$sum += ($tmp%10) + intval($tmp/10);
}
return (((10 - ($sum%10)) %10) == $imei[14]);
}
}
return false;
}

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