I want to share my website articles on facebook (content,image,title)!
but facebook doesn't detect correct image.
in this case I put an static image URL.
this is my code:
<li>
<a id="buttton" href="http://www.facebook.com/sharer.php?s=100&p[title]=<?php echo $title;?>&p[summary]=<?php echo $summary;?>&p[url]=<?php echo urlencode($url);?>&p[images][0]=http://www.example.com/images/report/daily_report/KNDR/image(2).jpg" onclick="javascript:window.open(this.href, '', 'menubar=no,toolbar=no,resizable=no,scrollbars=no,height=400,width=600'); return false;">
<img src="<?php echo base_url()?>media/images/share.png" alt=""/>
</a>
</li>
You can use facebook javascript sdk. First add FB Js SDK to your code (please refer to https://developers.facebook.com/docs/javascript)
window.fbAsyncInit = function(){
FB.init({
appId: 'xxxxx', status: true, cookie: true, xfbml: true });
};
(function(d, debug){var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0];
if(d.getElementById(id)) {return;}
js = d.createElement('script'); js.id = id;
js.async = true;js.src = "//connect.facebook.net/en_US/all" + (debug ? "/debug" : "") + ".js";
ref.parentNode.insertBefore(js, ref);}(document, /*debug*/ false));
function postToFeed(title, desc, url, image){
var obj = {method: 'feed',link: url, picture: 'http://www.url.com/images/'+image,name: title,description: desc};
function callback(response){}
FB.ui(obj, callback);
}
So when you want to share something
Share
And finally JS to handle click:
$('.btnShare').click(function(){
elem = $(this);
postToFeed(elem.data('title'), elem.data('desc'), elem.prop('href'), elem.data('image'));
return false;
});
This solution is using javascript to open a new window when a user clicks on your custom share button.
HTML:
<a href="#" onclick="share_fb('http://urlhere.com/test/55d7258b61707022e3050000');return false;" rel="nofollow" share_url="http://urlhere.com/test/55d7258b61707022e3050000" target="_blank">
//using fontawesome
<i class="uk-icon-facebook uk-float-left"></i>
Share
</a>
and in your javascript file. note window.open params are (url, dialogue title, width, height)
function share_fb(url) {
window.open('https://www.facebook.com/sharer/sharer.php?u='+url,'facebook-share-dialog',"width=626, height=436")
}
Well, I use this method on my site:
<a class="share-btn" href="https://www.facebook.com/sharer/sharer.php?app_id=[your_app_id]&sdk=joey&u=[full_article_url]&display=popup&ref=plugin&src=share_button" onclick="return !window.open(this.href, 'Facebook', 'width=640,height=580')">
Works perfectly.
The best way is to use your code and then store the image in OG tags in the page you are linking to, then Facebook will pick them up.
<meta property="og:title" content="Facebook Open Graph Demo">
<meta property="og:image" content="http://example.com/main-image.png">
<meta property="og:site_name" content="Example Website">
<meta property="og:description" content="Here is a nice description">
You can find documentation to OG tags and how to use them with share buttons here
Given that we are in a php code context and the variable $url contains the link the user wants to share, you can try this to use a custom image :
<a class="facebook-share-button" href="https://www.facebook.com/sharer/sharer.php?u=<?php echo urlencode($url); ?>" target="_blank"><img src="/img/facebook-share-button.png" /></a>
or this for just plain text :
<a class="facebook-share-button" href="https://www.facebook.com/sharer/sharer.php?u=<?php echo urlencode($url); ?>" target="_blank">share</a>
You can also style the link purely with css.
The html code :
<a class="facebook-share-button" href="https://www.facebook.com/sharer/sharer.php?u=<?php echo urlencode($url); ?>" target="_blank"></a>
The css code :
.facebook-share-button {
background-image: url("/img/facebook-share-button.png");
display: inline-block;
height: 32px;
width: 32px;
}
.facebook-share-button:active,
.facebook-share-button:focus,
.facebook-share-button:hover {
background-image: url("/img/facebook-share-button-hover.png");
}
You can simply do something like...
...
<head>
...
<script>
window.fbAsyncInit = function() {
FB.init({
appId : 'your-app-id', // you need to create an facebook app
autoLogAppEvents : true,
xfbml : true,
version : 'v3.3'
});
};
</script>
<script async defer src="https://connect.facebook.net/en_US/sdk.js"></script>
</head>
<body>
...
<button id="share-btn"></button>
<!-- load jquery -->
<script>
$('#share-btn').on('click', function () {
FB.ui({
method: 'share',
href: location.href, // Current url
}, function (response) { });
});
</script>
</body>
Include the facebook button on the page which you want to share
<a target="_blank" href="https://www.facebook.com/sharer/sharer.php?u=http://trial.com/news.php?newsid=<?php echo $content; ?>">
<img src="http://trial/new_img/facebook_link.png" style=" border: 1px solid #d9d9d9; box-shadow: 0 4px 7px 0 #a5a5a5; padding: 5px;" title="facebook_link" alt="facebook_link" />
</a>
Related
I have a profile page on which I show details about the author of site. Site have different authors and moderators. Profile Page has three social media buttons which have links to social media accounts of the author of the site. I fetch social media links from SQL database using PHP. Php is working fine. I want if no link to any social media account, then add hidden class to that social media button using Jquery.
I tried this but not working.
$(document).ready(function() {
var facecook = '<?php echo $facebook; ?>';
if (facebook < 0) {
$('.facebook').addClass('hidden')
};
var google = '<?php echo $google; ?>';
if (google > 0) {
$('.google').removeClass('hidden')
}
});
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<div class="btn-group btn-group-justified">
<a href="" class="btn facebook">
<?php echo $facebook; ?>
</a>
<a href="" class="btn twitter">
<?php echo $twitter; ?>
</a>
<a href="" class="btn google-plus">
<?php echo $google; ?>
</a>
</div>
Try this script. Typo error in your code.
var facecook = '<?php echo $facebook; ?>'; to var facebook = '<?php echo $facebook; ?>';
facebook not facecook
$(document).ready(function() {
var facebook = '<?php echo $facebook; ?>';
if (facebook=='') {
$('.facebook').addClass('hidden')
};
var google = '<?php echo $google; ?>';
if (google == '') {
$('.google').removeClass('hidden')
}
});
I am trying to share image and content from a webpage to User's FB wall but it is not posting it. Image is shown in share pop up but not shown in User's wall.
I have following code for this purpose.
In head section i have
<meta property="og:url" content="http://objdevelopment.com/notice/ddfdf" />
<meta property="og:type" content="website" />
<meta property="og:title" content=" Notice of Passing" />
<meta property="og:description" content="Notice of Passing " />
<meta property="og:image" content="http://objdevelopment.com/notice/wp-content/uploads/65a4465e9258729f8085c4d780700dad.jpg" />
and in HTML i have
<div id="fb-root"></div>
<script type='text/javascript'>
(function(d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) return;
js = d.createElement(s); js.id = id;
js.src = "http://connect.facebook.net/en_US/sdk.js#version=v2.3&appId=937475996303874&status=true&cookie=true&xfbml=true";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));</script>
<!-- Your share button code -->
<div class="fb-share-button" data-href="http://objdevelopment.com/notice/onope/ddfdf/"
data-layout="button_count">
</div>
and it is showing like this http://www.awesomescreenshot.com/image/510674/5e1cdc7572ab3946a36a23ff2c49b014
Clicking on Share button it opens following window
https://drive.google.com/file/d/0B54OjkhFLGPXNXI2MWgya1RRWFU/view?usp=sharing
and on wall it is showing like this http://www.awesomescreenshot.com/image/510678/ca4fc6be51aed2db5049b96546a6cd99
where as my expectations are:
https://drive.google.com/file/d/0B54OjkhFLGPXdGluaF9PNzdEakk/view?usp=sharing
For live testing please visit
http://objdevelopment.com/notice/onope/ddfdf/
Found some resources on web and fixed this issue. i have used following code to fix this
HTML
<a class="fb-share-button fb_share" href="#" data-href="[page_url]" data-image="[image_url]" data-title="[Post_title] " data-desc="[Post_description]" > <i class="fa fa-facebook"></i> </a>
Javascript
<script>
/**FB SHARE**/
window.fbAsyncInit = function() {
FB.init({
appId: 937475996303874,
status: true,
cookie: false,
xfbml: true
});
};
(function(d, debug){var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0];if (d.getElementById(id)) {return;}js = d.createElement('script'); js.id = id; js.async = true;js.src = "//connect.facebook.net/en_US/all" + (debug ? "/debug" : "") + ".js";ref.parentNode.insertBefore(js, ref);}(document, /*debug*/ false));
function postToFeed(title, desc, url, image) {
var obj = {method: 'feed',link: url, picture: image,name: title,description: desc};
function callback(response) {}
FB.ui(obj, callback);
}
var fbShareBtn = document.querySelector('.fb_share');
//fbShareBtn.addEventListener('click', function(e) {
jQuery('.fb_share').click(function(e){
e.preventDefault();
//alert();
var title = fbShareBtn.getAttribute('data-title'),
desc = fbShareBtn.getAttribute('data-desc'),
url = fbShareBtn.getAttribute('href'),
image = fbShareBtn.getAttribute('data-image');
//console.log(image+ "Hello");
postToFeed(title, desc, url, image);
return false;
});
/**FB SHARE**/
</script>
In Html replace text between [ ] with your own values.
I looked at the source of the provided page, and found no open graph meta tags. You should make sure those meta tags are printed.
You're seeing the correct image on the share box because you specified the path in the data-image attribute on the share button. But Facebook uses a crawler to pick up stuff from your page to show on the wall, and that crawler depends on open graph meta tags, which are missing
I think you have to debug your website url, Here you can see what image facebook is sharing. (https://developers.facebook.com/tools/debug/). Please try it.
I am using facebook's graph api Version 3.1.1
It is working fine but the logout url is not working properly.
With the logout url it is being logged out from the facebook but it is not being logged out in my application. Strange but true.
I am pasting necessary snipet from the code.
index.php
<script type="text/javascript">
function streamPublish(name, description, hrefTitle, hrefLink, userPrompt) {
FB.ui({method: 'feed',
message: userPrompt,
link: hrefLink,
caption: hrefTitle,
picture: ''
});
//http://developers.facebook.com/docs/reference/dialogs/feed/
}
function publishStream() {
streamPublish("Stream Publish", 'Checkout personalized products at www.picpixa.com. I found some of them are just awesome!', 'Checkout www.picpixa.com', 'http://www.picpixa.com', "Personalized Products");
}
</script>
<style type="text/css">
.box{
margin: 5px;
border: 1px solid #60729b;
padding: 5px;
width: 500px;
height: 200px;
overflow:auto;
background-color: #e6ebf8;
}
</style>
<div id="fb-root"></div>
<script type="text/javascript" src="http://connect.facebook.net/en_US/all.js"></script>
<script type="text/javascript">
FB.init({
appId: '',
status: true, // check login status
cookie: true, // enable cookies to allow the server to access the session
xfbml: true // parse XFBML
});
</script>
<body>
<div id="load" class="loader"></div>
<div class="container">
<div class="row">
<div class="col-lg-12 col-md-12 col-sm-12 col-xs-12">
<div class="modal-footer">
<?php
echo "User: $user";
if (!$user) { ?>
<h1>You have to login using Facebook Login Button to see your uploaded images.</h1>
<a class='btn btn-primary' href="<?= $loginUrl ?>" onClick='loader()'><img src="Images/login.png"></a>
<?php } else { ?>
<a class='btn btn-primary' href="<?= $logoutUrl ?>" onClick='loader()'><img src="Images/logout.png"></a>
<?php } ?>
</div>
basefacebook.php
public function getLogoutUrl($params = array()) {
return $this->getUrl(
'www', 'logout.php', array_merge(array(
'next' => $this->getCurrentUrl(),
'access_token' => $this->getAccessToken(),
), $params)
);
}
Feel free to ask for more info.
Please help me out with this.
Thank you,
I wonder whether someone may be able to help me please.
The code below allows users to delete images from a gallery.
Full Script Minus Styling
<?php session_start();
$_SESSION['userid']=$_POST['userid'];
$_SESSION['locationid']=$_POST['locationid'];
//echo $_SESSION['userid'];
//echo $_SESSION['locationid'];
?>
<?php
$galleryPath = 'UploadedFiles/' . $_SESSION['userid'] . '/' . $_SESSION['locationid'] . '/';
$absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR;
$descriptions = new DOMDocument('1.0');
$descriptions->load($absGalleryPath . 'files.xml');
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width,initial-scale=0.3">
<title>Galleria Twelve Theme</title>
<style>
<script src="js/jquery-1.7.2.min.js"></script>
<script src="js/jquery-ui-1.8.19.custom.min.js"></script>
<script src="galleria/galleria-1.2.7.min.js"></script>
<script src="galleria/themes/twelve/galleria.twelve.min.js"></script>
<script src="galleria/plugins/history/galleria.history.min.js"></script>
<link rel="stylesheet" href="galleria/themes/twelve/galleria.twelve.css">
<style>
.galleria-thumbnails .btn-delete {
display: block; /* Or just use a div instead of a span*/
position: absolute; bottom : 0px; /*align at the bottom*/
width: 80px;
height: 17px;
cursor: pointer;
background: url(trash8.gif) no-repeat bottom; }
</style>
<script type="text/javascript">
Galleria.ready(function() {
this.$('thumblink').click();
$(".galleria-image").append(
"<span class='btn-delete ui-icon ui-icon-trash'></span>");
$(".btn-delete").live("click", function(){
// you do not need to find img and then src... just use id of image
var img = $(this).closest(".galleria-image").find("img");
var userid=$(".hiddenvals").attr('userid');
var locationid=$(".hiddenvals").attr('locationid');
// send the AJAX request
$.ajax({
url : 'delete3.php?userid='+userid+'&locationid='+locationid,
type : 'post',
data : { image : img.attr('src') },
success : function(){
alert('Deleting image... ');
img.parent().fadeOut('slow');
}
});
return false;
});
});
</script>
</head>
<body>
<ul id="navigation">
<li class="left">
<div align="center">← Add Images</div>
</li>
</ul>
<form id="viewimages" name="viewimages" class="page" action="index.php" method="post"> <input name="userid" class="hiddenvals" type="hidden" value="<?php echo $_SESSION['userid']; ?>"> <input name="locationid" class="hiddenvals" type="hidden" value="<?php echo $_SESSION['locationid']; ?>"></form>
<div class="content">
<h1>Galleria Twelve Theme</h1>
<p>Demonstrating a simple example.</p>
<!-- Adding gallery images. We use resized thumbnails here for better performance, but it’s not necessary -->
<div id="galleria">
<?php for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) :
$xmlFile = $descriptions->documentElement->childNodes->item($i);
$name = htmlentities($xmlFile->getAttribute('originalname'), ENT_COMPAT, 'UTF-8');
$description = htmlentities($xmlFile->getAttribute('description'), ENT_COMPAT, 'UTF-8');
$source = $galleryPath . rawurlencode($xmlFile->getAttribute('source'));
?>
<img data-title="<b>Image Name: </b> <?php echo $name; ?>" data-description="<b>Description:</b> <?php echo $description; ?>" src="<?php echo $source; ?>">
<?php endfor; ?>
</body>
</html>
In essence, the user clicks on a delete icon, then the 'delete.php' script called in the code above deletes the image from the server. This all works well.
What I'm struggling with is how to pass two variable values to the 'delete.php' script. These are 'userid' and 'locationid'.
I've tried adding the following to the beginning of my 'delete.php':
<?php session_start();
$_SESSION['userid']=$_POST['userid'];
$_SESSION['locationid']=$_POST['locationid'];
But the values are not carried over. I suspect that this may be down to the fact the the forms 'POST' action is being used to navigate to another HTML page, although I'm no expert, so I may have got this wrong.
I've done quite a bit of reading and searched for tutorials on how to go about getting around this problem, but I've not found anything that seems to suggest a solution.
I just wondered whether someone may be able to look at this please, and offers some guidance on how I can pass these two values to my 'delete.php' script.
Many thanks and kind regards
If they are in the html page add them to the ajax request:
{ image : img.attr('src'), userid: "VALUE", locationid: "VALUE"},
Try to send ids from your html page like
$.ajax({
url : 'delete.php?userid=2&locationid=4',
........
Then in php
$uid=$_POST['userid'];
$locid=$_POST['locationid'];
If you want to get userid and locationid dynamically for each image.
FIRST; in you btn-delete class add uid and locid attribute. I suppose you are looping through PHP.
LIKE ===>
<input type="button" class="btn-delete" uid="2" locid="5">
Then in your script
<script type="text/javascript">
Galleria.ready(function() {
this.$('thumblink').click();
$(".galleria-image").append(
"<span class='btn-delete ui-icon ui-icon-trash'></span>");
$(".btn-delete").live("click", function(){
// you do not need to find img and then src... just use id of image
var img = $(this).closest(".galleria-image").find("img");
var uid=$(this).attr('uid');
var locid=$(this).attr('locid');
// send the AJAX request
$.ajax({
url : 'delete.php?userid='+uid+'&locationid='+locid,
type : 'post',
data : { image : img.attr('src') },
success : function(){
alert('Deleting image... ');
img.parent().fadeOut('slow');
}
});
return false;
});
});
</script>
var id=$(this).attr('id');
var userid=$('#userid').val();
var locationid=$('#locationid').val();
$.ajax({
url : 'delete.php',
type : 'post',
dataType : 'json',
data : { image : img.attr('src'), userid: userid, locationid: locationid},
,
success : function(){
alert('Deleting image... ');
img.parent().fadeOut('slow');
}
});
add dataType : 'json' and get posted value in delete.php by
$userid=$_POST['userid'];
$locationid=$_POST['locationid'];
Can anyone explain how to embed a swf object into a facebook canvas page via PHP.
<?php
function sswf($swf,$swfh,$swfw) {
echo "<OBJECT classid='clsid:D27CDB6E-AE6D-11cf-96B8-444553540000'
codebase='http://active.macromedia.com/flash2/cabs/swflash.cab#version=4,0,0,0' ID=objects WIDTH=$swfw HEIGHT=$swfh><PARAM
NAME=movie VALUE='$swf'><EMBED src='$swf' WIDTH=$swfw HEIGHT=$swfh TYPE='application/x-shockwave-flash'
PLUGINSPAGE='http://www.macromedia.com/shockwave/download/index.cgi?P1_Prod_Version=ShockwaveFlash'></OBJECT>";
}
$mf = "mmmm1.swf";
sswf($mf,690,1000);
?>
The code above no longer works although it did last week.... What's wrong with it?
<script type="text/javascript" src="swfobject.js"></script>
<script type="text/javascript">
var params = {allowFullScreen:'false', allowscriptaccess:'always', wmode:'opaque'};
var flashvars = {};
var attributes = { name:"xxx", id:"xxx" };
swfobject.embedSWF("xxx.swf?<? echo(time()) ?>", "xxx", "520", "500", "9.0", null, flashvars, params, attributes);
</script>
<div id="fb-root"></div>
<div id="xxx">
<h1>You need at least Flash Player 9 to view this page.</h1>
<p><img src="https://www.adobe.com/images/shared/download_buttons/get_flash_player.gif" alt="Get Adobe Flash player" /></p>
</div>