I want to calculate difference between 2 datetimes in hours with PHPSpreadsheet. This is how Excel does it:
A1 and A2 cells format is:
This is the result on web:
When I change value through PHPSpreadsheet, I get #VALUE! and different value formatting.
$reader = PhpSpreadsheet\IOFactory::createReader("Xlsx");
$target_file = __DIR__ . '/test.xlsx';
$spreadsheet = $reader->load($target_file);
$spreadsheet->getActiveSheet()->setCellValue('A1', '24.6.2020 12:30');
$writer = new PhpSpreadsheet\Writer\Html($spreadsheet);
$output = $writer->generateHTMLHeader();
$output .= $writer->generateStyles(true);
$output .= $writer->generateSheetData();
$output .= $writer->generateHTMLFooter();
$doc = new DOMDocument();
#$doc->loadHTML($output);
echo $doc->saveHTML();
I also tried with formatting like this 6/24/2020 14:30 but the result was same (#VALUE!)
$spreadsheet->getActiveSheet()->setCellValue('A1', '6/24/2020 14:30');
Anyone got any idea on how this should be done?
In an Excel document, dates are stored as numbers, not strings. So you need to pass the correct number to setCellValue().
PhpSpreadsheet provides the utility method Date::stringToExcel() to convert strings to Excel dates. You can use it like this:
$date = PhpSpreadsheet\Shared\Date::stringToExcel('2020-06-24 12:30');
$spreadsheet->getActiveSheet()->setCellValue('A1', $date);
I have a form that has the following HTML code. I am trying to get a date out of the form's user in yyyy-mm-dd format for insertion into SQL. I have been using the explode function followed by parts[] in php to change mm/dd/yyyy into yyyy-mm-dd. That process works well. But if my user is using an iPad or iPhone the output is already in yyyy-mm-dd format and does not need to be formatted. Any ideas on how I can streamline the process? Thank you in advance.
<p>Date (mm/dd/yyyy)<br/>
<input type="date" name="flightdate"/></p>
This code did not work on iPad or iPhone. When using iPad or iPhone it doesn't output anything for $flightdate.
$flightdate = $_POST['flightdate'];
if(strstr($_SERVER['HTTP_USER_AGENT'],'iPod') || strstr($_SERVER['HTTP_USER_AGENT'],'iPhone') || strstr($_SERVER['HTTP_USER_AGENT'],'iPad')) {
$flightdate = $yyyy_mm_dd }
else { $parts = explode('/',$flightdate);
$yyyy_mm_dd = $parts[2] . '-' . $parts[0] . '-' . $parts[1];
}
The iPhone can send the date in mm/dd/yyyy format.
Second option - it can send just timestamp and avoid formats at all.
How can I force the date format to output:
12/12/2012, 1/10/2012, 1/5/2012
instead of
12/12/2012, 01/10/2012, 01/05/2012?
My code is the following:
$adatefrom = date_create($_POST['datefrom']);
$adateto = date_create($_POST['adateto']);
$adatefrom = date_format($adatefrom, 'd/m/Y');
$adateto = date_format($adateto, 'd/m/Y');
Please do note that I have to format the date AFTER posting it.
Have a look at the PHP built in date function here
You will find that your solution is as simple as this:
date('j/n/Y',strtotime($_POST['datefrom']));
The key things to note are the characters used in the first parameter.
j represents the day without leading zeros
n represents the month without leading zeros
There are many other options you have, just have a read through the documentation.
Please note that a simple search of 'PHP date' on Google would have found this solution for you
$adatefrom = date_create($_POST['datefrom']);
$adateto = date_create($_POST['adateto']);
$adatefrom = date_format($adatefrom, 'j/n/Y');
$adateto = date_format($adateto, 'j/n/Y');
you are welcome! ;)
I have simple excel(2003 .xls) file I'm reading. I'm using PHP Excel from codeplex, but some cells have custom format type # ##0,00%.
When I'm reading the file, I'm always getting a failed value(110.2f%)
Now I solved this case:
$workSheet->getStyle('G'.$line)->getNumberFormat()->setFormatCode(PHPExcel_Cell_DataType::TYPE_STRING);
$turnover_str = $workSheet->getCell('G'.$line);
output in browser: -0.22878905524141
but I need this format: -22,87
I convert using this function:
function conv_to_percent($str){
$str = (int)$str * 100;
$str = number_format($str, 2, ',', '');
return $str;}
Output in browser all result is 100 example when $str value is -0.22878905524141:
But I have created a clean PHP for this function and working fine(I have only this function):
print conv_to_percent("-0.22878905524141"); //output: -22,88
I tried (int), floatval($str) but problem is same.
What am I doing wrong?
im trying to validate a date to see if it matchs the mysql format
this is the code
$match = "/^\d{4}-\d{2}-\d{2} [0-2][0-3]:[0-5][0-9]:[0-5][0-9]$/";
$s = $this->input->post("report_start"). " " . $this->input->post("report_start_time").":00";
$e = $this->input->post("report_end"). " " . $this->input->post("report_end_time").":59";
if($this->input->post("action") != "")
{
echo trim($s). " => " . preg_match($match, trim($s));
echo "<br>";
echo trim($e). " => " . preg_match($match, trim($e));
}
the date format goes into $s and $e are
$s = 2011-03-01 00:00:00
$e = 2011-03-01 23:59:59
and they both return false (0).
i tested the pattern on http://www.spaweditor.com/scripts/regex/index.php and it returns true (1)
http://pastebin.com/pFZSKYpj
however if i manual inter the date strings into preg_match like
preg_match($match, "2011-03-01 00:00:00")
it works.
i have no idea what im doing wrong
======================
now that i think about it, i only need to validate the houre:min part of the datetime string.
im manually adding the seconds and the date is forced by a datepicker and users cant edit it
You're making your work harder that it needs to be. In php there are many date handling functions that mean you don't have to treat dates like strings. So, rather than test that your input dates are in the correct format, just insist on the correct format:
$adate= date_create('January 6, 1983 1:30pm'); //date format that you don't want
$mysqldate= $adate->format("Y-m-d h:i:s");//date format that you do want
There are also functions to check that a date is a real date, like checkdate.
ok heres wat i did.
since im forcing the date format and the ending seconds of the time part
i just validated the hour:mini part using "/^2[0-3]|[01][0-9]:[0-5][0-9]$";
and if that returns true i put everything together end reconstructed the final datetime string
$match = "/^2[0-3]|[01][0-9]:[0-5][0-9]$/";
$s_d = $this->input->post("report_start");
$s_t = $this->input->post("report_start_time");
$e_d = $this->input->post("report_end");
$e_t = $this->input->post("report_end_time");
if($this->input->post("action") != "")
{
if(
( preg_match($match , trim($s_d." ".$s_t.":00")) )
&& ( preg_match($match , trim($e_d." ".$e_t.":59")) )
)
{
$r = $this->model_report->client_hours_logged(array($s,$e));
$data['report'] = $r;
var_dump($r);
//$this->load->view("report/client_hours_per_client",$data);
}
}
Watch out:
[0-2][0-3] is not a good regex for hour values - it will match 01, 12, 23 and others, but it will fail 04 through 09 and 14 through 19.
Better use (2[0-3]|[01][0-9]) instead.
I use this to validate a 'Y-m-d H:i:s' format date string:
match = '/^[12][0-9]{3}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[01]) ([01][0-9]|2[0-3]):[0-5][0-9]:[0-5][0-9]$/';
You could use strtotime and date to parse and format the date properly.
Why not just simply force the date into the format you want:
$e = '2011-03-01 00:00:00';
$mysqlFormat = date('Y-m-d H:i:s', strtotime($e));
Also, there is a bit of an error in your regex [0-2][0-3]:[0-5][0-9]:[0-5][0-9] will only match the hours of 00,01,02,03,10,11,12,13,20,21,22,23 so it will never match 4am, or 3pm among others. That aside I looked over your RegEx and I don't see any problems with it matching the test cases you've offered. I would check to make sure there is not extra whitespace on either side of date string with trim().
I concur with Tim : MySQL behaves in quirks mode and always tries to go easy on DATE and DATE_TIME column types. You can omit certain parts of your input and it still will try to compensate and achieve that goal successfully to some degree... That's why, most numbers your Reg-ex considers as invalid, MySQL will accept as valid.