Load menu and sub-menus from two MySQL queries PHP - php

Question

$menu = mysql_query(" query 1");
$k = 1;
for ($s = 0; $s < mysql_num_rows($menu); $s++)
{
$menus= mysql_fetch_assoc($menu);
$mainmenu[]=$menus['name'];
$submenus=mysql_query("query 2");
for ($m = 0; $m < mysql_num_rows($submenus); $m++)
{
$submenu = mysql_fetch_assoc($submenus);
$subitem[]=$submenu['name'];
$url=$submenu['url'];
}
}
foreach($mainmenu as $mains)
{
echo '<li class="hasul"><a><span><b>' .$mains.'</b></span></a></li>';
foreach($subitem as $sub)
{
echo '<ul>';
echo '<li><span>' .$sub. '</span></li>';
echo '</ul>';
}
}
The code above show two queries which load a menu and submenus. Query2 uses some inputs from query1.
The menus do load correctly but they contain same menu items. Ideally each menu should have its own menu items.

Answer 1

You have a foreach inside your foreach, that means, that for every main menu you are outputing all the submenus.
Create some parameter for submenu, like:
$mainmenu = array(
1 => 'about',
2 => 'news',
3 => 'search',
);
$submenu = array(
1 => array( 'about my name', 'about my location' ),
3 => array( 'search me' ),
);
And now check only the submenu you need:
if ( is_array( $mainmenu ) )
{
echo '<ul>';
foreach( $mainmenu as $key=>$menu )
{
echo '<li>'.$menu.'</li>';
if ( is_array( $submenu[$key]) )
{
echo '<ul>';
foreach( $submenu[$key] as $sub )
{
echo '<li>'.$sub.'</li>';
}
echo '</ul>';
}
}
echo '</ul>';
}
This will produce:
<ul>
<li>about</li>
<ul>
<li>about my name</li>
<li>about my location</li>
</ul>
<li>news</li>
<li>search</li>
<ul>
<li>search me</li>
</ul>
</ul>
I hope you get the idea.

Answer 2

use this.. this could be easier to understand..
echo '<ul>';
$qry = mysql_query("query 1");
while ($row = mysql_fetch_array($qry))
{
echo "<li>";
echo "<a href='" . $row['url'] . "'>'" . $row['name'] . "'</a>";
$qry2 = mysql_query("query 2");
if (mysql_num_rows($query2) > 0)
{
echo "<ul>";
while ($row2 = mysql_fetch_array($query2))
{
echo "<li>";
echo "<a href='" . $row2['url2'] . "'>'" . $row2['name2'] . "'</a>";
echo "</li>";
}
echo "</ul>";
}
echo "</li>";
}
echo "</ul>";
let me know if you want any further help...