PHP how to output the top array_count_values value from array? - php

Question

I have a table that I need to find "top trusted builder" from, Trusts are separated by " ; ", So I need to pull all the data, explode the usernames, order and count them, and Im stuck on finally outputting the top username form the array, I have posted up the full segment of PHP, because im sure there has to be a much better way of doing this.
<?php
$GTB = $DBH->query('SELECT builders from griefprevention_claimdata where builders <> ""');
$GMCB->setFetchMode(PDO::FETCH_ASSOC);
$buildersarray = array();
while($row = $GTB->fetch()) {
$allbuilders = explode(";", $row['builders']);
for($i = 0; $i < count($allbuilders); $i++)
{
$buildersarray[] = $allbuilders[$i];
}
}
echo "<pre>";
print_r(array_count_values(array_filter($buildersarray)));
echo "</pre>";
?>
Outputs
Array
(
[username1] => 4
[username2] => 1
[username3] => 1
)

Answer 1

You can return the array from the array_count_values command into a new array called $topbuilders, and then echo out the current (first) record:
$topbuilders = array_count_values(array_filter($buildersarray));
echo current(array_keys($topbuilders)).', Rank = '.current($topbuilders);
current() will return the first item in an associative array.

Answer 2

Instead of using array_count_values() it would be better to use the names as the key to a frequency array:
$GTB = $DBH->query('SELECT builders from griefprevention_claimdata where builders <> ""');
$result = array();
while (($builders = $GTB->fetchColumn()) !== false) {
foreach (explode(";", $builders) as $builder) {
if (isset($result[$builder])) {
$result[$builder]++;
} else {
$result[$builder] = 1;
}
}
// sort descending based on numeric comparison
arsort($result, SORT_NUMERIC);
echo "Name = ", key($result), " Count = ", current($result), "\n";