I am trying to delete a file from folder in php here is my model function
function deleteFiles()
{
$file = "http://localhost/copycopy/img/uploaded/long.jpeg";
if(is_file($file))
{
#unlink($file); // delete file
echo $file.'file deleted';
}
else
{
echo "no file";
}
}
but I always see "no file" and file is never deleted, file is in folder,because the url in $file actually displays the file in browser
help me
instead of using web url
$file = "http://localhost/copycopy/img/uploaded/long.jpeg";
use local path to file:
$file = $pathToYourWebSite . "/copycopy/img/uploaded/long.jpeg";
be sure to set $pathToYourWebSite to real location of your website;
Related
I can download a csv file via a fixed url. The url just doesn't have a file name.
When I open the url in a browser, the file export.csv is generated and after about 10 sec the download starts.
Now I want to download this export csv file directly to my own server,
I have the code below, but it doesn't work in my case.
Can you help me? my thanks are big
<?php
$url =
'https://www.example.com/product-export/link123456789';
$file_name = basename($url);
if (file_put_contents($file_name, file_get_contents($url)))
{
echo "File downloaded successfully";
}
else
{
echo "File downloading failed.";
}
?>
As the generated output filename is always export.csv, we may use the following to specify the filename:
$file_name = dirname(__FILE__) . "/export.csv";
(make sure the directory is write-permitted so that the php can save the file "export.csv")
Hence, the code will be:
<?php
$url = 'http://www.createchhk.com/SOanswers/export1a.csv';
//$file_name = basename($url);
$file_name = dirname(__FILE__) . "/export.csv";
if (file_put_contents($file_name, file_get_contents($url))) {
echo "File downloaded successfully";
} else {
echo "File downloading failed.";
}
?>
For your cronjob, it will be something like :
1 1 * * * php /path_to_the_php/test.php
I am uploading files to a server using php and while the move_uploaded_file function returns no errors, the file is not in the destination folder. As you can see I am using the exact path from root, and the files being uploaded are lower than the max size.
$target = "/data/array1/users/ultimate/public_html/Uploads/2010/";
//Write the info to the bioHold xml file.
$xml = new DOMDocument();
$xml->load('bioHold.xml');
$xml->formatOutput = true;
$root = $xml->firstChild;
$player = $xml->createElement("player");
$image = $xml->createElement("image");
$image->setAttribute("loc", $target.basename($_FILES['image']['name']));
$player->appendChild($image);
$name = $xml->createElement("name", $_POST['name']);
$player->appendChild($name);
$number = $xml->createElement("number", $_POST['number']);
$player->appendChild($number);
$ghettoYear = $xml->createElement("ghettoYear", $_POST['ghetto']);
$player->appendChild($ghettoYear);
$schoolYear = $xml->createElement("schoolYear", $_POST['school']);
$player->appendChild($schoolYear);
$bio = $xml->createElement("bio", $_POST['bio']);
$player->appendChild($bio);
$root->appendChild($player);
$xml->save("bioHold.xml");
//Save the image to the server.
$target = $target.basename($_FILES['image']['name']);
if(is_uploaded_file($_FILES['image']['tmp_name']))
echo 'It is a file <br />';
if(!(move_uploaded_file($_FILES['image']['tmp_name'], $target))) {
echo $_FILES['image']['error']."<br />";
}
else {
echo $_FILES['image']['error']."<br />";
echo $target;
}
Any help is appreciated.
Eric R.
Most like this is a permissions issue. I'm going to assume you don't have any kind of direct shell access to check this stuff directly, so here's how to do it from within the script:
Check if the $target directory exists:
$target = '/data/etc....';
if (!is_dir($target)) {
die("Directory $target is not a directory");
}
Check if it's writeable:
if (!is_writable($target)) {
die("Directory $target is not writeable");
}
Check if the full target filename exists/is writable - maybe it exists but can't be overwritten:
$target = $target . basename($_FILES['image']['name']);
if (!is_writeable($target)) {
die("File $target isn't writeable");
}
Beyond that:
if(!(move_uploaded_file($_FILES['image']['tmp_name'], $target))) {
echo $_FILES['image']['error']."<br />";
}
Echoing out the error parameter here is of no use, it refers purely to the upload process. If the file was uploaded correctly, but could not be moved, this will still only echo out a 0 (e.g. the UPLOAD_ERR_OK constant). The proper way of checking for errors goes something like this:
if ($_FILES['images']['error'] === UPLOAD_ERR_OK) {
// file was properly uploaded
if (!is_uploaded_File(...)) {
die("Something done goofed - not uploaded file");
}
if (!move_uploaded_file(...)) {
echo "Couldn't move file, possible diagnostic information:"
print_r(error_get_last());
die();
}
} else {
die("Upload failed with error {$_FILES['images']['error']}");
}
You need to make sure that whoever is hosting your pages has the settings configured to allow you to upload and move files. Most will disable these functions as it's a sercurity risk.
Just email them and ask whether they are enabled.
Hope this helps.
your calls to is_uploaded_file and move_uploaded_file vary. for is_uploaded_file you are checking the 'name' and for move_uploaded_file you are passing in 'tmp_name'. try changing your call to move_uploaded_file to use 'name'
I have two directories:
/publichtml
/csp.example.com
My code is in csp.example.com/classes/ep-class.php and I want to upload my file on /publichtml/upload/photo folder. How can I achieve that also /publichtml is accessible using example.com so I am taking target directory as a absolute url?
Here is my code:
if(isset($_FILES["imagefile"]["type"][0]))
{
$filename=$_FILES["imagefile"]["name"][0];
// Storing source path of the file in a variable
$sourcePath = $_FILES['imagefile']['tmp_name'][0];
// Target path where file is to be stored
$targetPath = SITEURL."upload/photo/".$filename;
if(move_uploaded_file($sourcePath,$targetPath))
{
return "Yes";
}
else
{
echo $_FILES["imagefile"]["errors"][0];
die("File upload error !");
}
}
Any help would be highly appreciated.
Going out of my mind with php unlinking
Here is my delete file script
$pictures = $_POST['data'];
//print_r ($pictures);
$imageone = $pictures[0];
$filename = "file:///Users/LUJO/Documents/CODE/REVLIVEGIT/wp-content/uploads/dropzone/" . $imageone;
echo $filename;
if (is_file($filename)) {
chmod($filename, 0777);
if (unlink($filename)) {
echo 'File deleted';
} else {
echo 'Cannot remove that file';
}
} else {
echo 'File does not exist';
}
The above does not work, error response is file does not exist
however if i change the filename path to this (the echo data from the echo above)
$filename = "file:///Users/LUJO/Documents/CODE/REVLIVEGIT/wp-content/uploads/dropzone/1420291529-whitetphoto.jpeg "
works fine and deletes the image.
Why can i not use the $imageone variable?
Do a print_r($pictures) to see if $pictures[0] is indeed the filename you're looking for.
Also note that if $pictures[0] is "//windows/*" you'll loose your windows if the user running PHP has administrative rights... so just using $pictures=$_POST["data"] is very VERY unsafe!
I have a simple code that checks whether a file exists or not in the server.
<?php
$filename = 'www.testserver/upload/productimg/IN.ZL.6L_sml.jpg';
if (file_exists($filename)) {
echo "The file $filename exists";
} else {
echo "The file $filename does not exist";
}
?>
Problem: My local webserver says that the file does not exist even though when I copy paste the url in the browser, I can see the image.
How can I make the condition say that the file does not really exist?
Another option would be, making a request and checking for the response headers:
<?php
$headers = get_headers('http://www.example.com/file.jpg');
if($headers[0]=='HTTP/1.0 200 OK'){
return true; // file exists
}else{
return false; // file doesn't exists
}
?>
Code live example:
http://codepad.viper-7.com/qfnvme
for real path of image you can try:
<?php
$filename = 'www.testserver/upload/productimg/IN.ZL.6L_sml.jpg';
$testImage = #file_get_contents($filename);
if ($testImage != NULL) {
echo "The file $filename exists";
} else {
echo "The file $filename does not exist";
}
?>
Use
$filename = $_SERVER["DOCUMENT_ROOT"]."/upload/productimg/IN.ZL.6L_sml.jpg";
for testing the file.