Searching from MySql database and display the results as a hyperlink - php

Question

Here is my code, what I want to do is display the first names of my friends in another page as Hyperlinks and when a link is clicked I want to display the data.
<?php
$con=mysqli_connect("localhost","root","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM friends");
while($row = mysqli_fetch_array($result))
{
echo "<p>" . $row['FirstName'] . "</p>";
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
}
mysqli_close($con);
?>

Answer 1

<?php
$con=mysqli_connect("localhost","root","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM friends");
while($row = mysqli_fetch_array($result))
{?>php
<a href=<?php "echo "<p>" . $row['FirstName'] . "</p>";"?>> `your page name`</a><?php
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
}
mysqli_close($con);
?>

Answer 2

Your file from questions change:
while($row = mysqli_fetch_array($result))
{
echo "<p>" . $row['FirstName'] . "</p>";
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
}
to
while($row = mysqli_fetch_array($result))
{
echo ' . $row['FirstName'] . "";
}
show.php
$con=mysqli_connect("localhost","root","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if(isset($_GET['UserId'])){
if(is_numeric($_GET['UserId'])){
$UserId = (int)$_GET['UserId'];
$result = mysqli_query($con,"SELECT * FROM friends WHERE UserId= $UserId");
if(count($result)){
while($row = mysqli_fetch_array($result))
{
echo "<p>" . $row['FirstName'] . "</p>";
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
}}}}
Important: I'm not sure what is UserId column name, so change it.
Also, please check for syntax errors.

Answer 3

Try connection it with an incremental ID out of the database. So every row in your friends table must have a unique ID. In that way you can connect it and get the row data from your friends table.
So your friends table must look like this:
friend_id (unique id)
firstname
lastname
email
address
And your code can be something like (this is not save from any attacks):
<?php
$con = mysqli_connect("localhost","root","abc123","my_db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if(isset($_GET['friendid'])) {
$result = mysqli_query($con,"SELECT * FROM friends");
while($row = mysqli_fetch_array($result)) {
echo "<p>" . $row['FirstName'] . "</p>";
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
echo "<p>Details</p>";
}
} else {
$result = mysqli_query($con,"SELECT * FROM friends WHERE friend_id = '".$_GET['friendid']."'");
$row = mysqli_fetch_assoc($result);
echo "<p>" . $row['FirstName'] . "</p>";
echo "<p>" . $row['LastName'] . "</p>";
echo "<p>" . $row['Email'] . "</p>";
echo "<p>" . $row['Address'] . "</p>";
}
mysqli_close($con);
?>