I'm trying to design a control page for my website that allows admins to delete requests to use a 3D printer at my school. The page displays a query of the schedule from the MySQL database and puts a delete button next to every entry. However, I would like to link the information in each entry to its respective delete button and have no idea how to do that. You can see the page itself here: http://kepler.covenant.edu/~techclub/PHP/manage%20printer%20schedule.php and this is my code for displaying the information
if ($result = $mysqli->query($query)) {
// see if any rows were returned
if ($result->num_rows > 0) {
// yes
// print them one after another
echo "<table cellpadding=10 border=1>";
echo "<tr>";
echo "<th>Control</th>";
echo "<th>Student ID</th>";
echo "<th>Last Name</th>";
echo "<th>First Name</th>";
echo "<th>Date and Time</th>";
echo "<th>Description</th>";
echo "</tr>";
$key = 1;
while($row = $result->fetch_array()) {
echo '<form method="POST" name="deleterequest" action = "delete request.php">';
echo "<tr>";
echo "<td><input name='".$row[5]."'type='submit' value='Delete' ></td>";
echo "<td>".$row[0]."</td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "</tr>";
echo "</form>";
}
echo "</table>";
}
else {
// no
// print status message
echo "No upcoming prints found!";
}
// free result set memory
$result->close();
}
I can't figure out how to link the information in a row with the delete button that I put in the row to send to the delete request.php program (which I have no code for yet)
you should put hidden field that hold each record id.
As below
while($row = $result->fetch_array()) {
echo "<tr>";
echo "<td>";
echo '<form method="POST" name="deleterequest" action = "delete request.php">';
echo "<input name='recored_id' type='hidden' value='".$row['id']."' >";
echo "<input name='delete'type='submit' value='Delete' >";
echo "</form>";
echo "</td>";
echo "<td>".$row[0]."</td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "</tr>";
echo "</form>";
}
Now from your request.php page you should do something like this
$recored_id = (int) $_POST['recored_id'];
$sql = "DELETE FROM table_name WHERE recored_id='$recored_id'";
Don't forget to give this code some security validation
all the best,
You're going to need some hidden inputs, like so:
while($row = $result->fetch_array()) {
echo "<tr>";
echo '<td><form method="POST" name="deleterequest" action = "deleterequest.php">';
echo "<input type='hidden' name='val0' value='" . $row[0] . "'>";
echo "<input type='hidden' name='val1' value='" . $row[1] . "'>";
echo "<input type='hidden' name='val2' value='" . $row[2] . "'>";
echo "<input type='hidden' name='val3' value='" . $row[3] . "'>";
echo "<input type='hidden' name='val4' value='" . $row[4] . "'>";
echo "<input name='".$row[5]."'type='submit' value='Delete' >";
echo "</form></td>";
echo "<td>".$row[0]."</td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "</tr>";
}
You should change the name of these inputs though
Related
I have displayed the values from mysql table along with radio buttons with different values. On submit button it should redirect to next page and display the selected values. My code on first file is as follows :
$query1 = "select * from booking";
$result1 = $connection->query($query1);
echo "<form method='post' action='edit.php'>";
echo "<center>";
echo "<table border='1'>";
$count = 0;
while($row = $result1->fetch_row())
{
echo "<tr>";
echo "<td width=".'10'.">";
$count = $count + 1;
#$sr=$sr+1;
echo "<input type='radio' name='select' value='".$count."' />";
#$row = mysqli_fetch_row($result1);
#echo "<tr>";
echo "<td width=".'10'.">";
$rooms = $row[0];
$srrooms = $rooms;
echo "<input type='text' name='srrooms' value='".$srrooms."' hidden='hidden'>";
#echo $srrooms;
echo $rooms;
echo "</td>";
echo "<td width=".'10'.">";
$no_roomss = $row[1];
$nosrrooms = $no_roomss;
echo "<input type='text' name='nosrrooms' value='".$nosrrooms."' hidden='hidden'>";
echo $no_roomss;
echo "</td>";
echo "<td width=".'10'.">";
$no_dayss = $row[2];
$nodays = $no_dayss;
echo "<input type='text' name='nodays' value='".$nodays."' hidden='hidden'>";
echo $no_dayss;
echo "</td>";
echo "<td width=".'10'.">";
$name = $row[3];
echo $name;
echo "</td>";
echo "</tr>";
#$count++;
}
echo "<input name='count' type='hidden' id='count'>"; // hidden input where counter value will be stored
echo "</table>";
echo "<input type='submit' name='submitRooms' />";
echo "</center>";
echo "</form>";
The javascript code is :
$(function(){
$('input[name="select"]').change(function(){
$('#count').val($("input[name='select']:checked").val());
});
});
edit.php code is :
<?php
if(isset($_POST['submitRooms'])){
#$count = $_POST['count'];
#$srrooms=$_POST['srrooms'.$count];
#$nosrrooms=$_POST['nosrrooms'.$count];
#$nodays=$_POST['nodays'.$count];
echo 'Selected values are: '. $srrooms . $nosrrooms . $nodays;
}
?>
You can use counter for submitting the values of the selected radiobutton's row as:
<?php
$query1 = "select * from booking";
$result1 = $connection->query($query1);
echo "<form method='post' action='edit.php'>";
echo "<center>";
echo "<table border='1'>";
$count = 0; // counter variable
while($row = $result1->fetch_row())
{
echo "<tr>";
echo "<td width=".'10'.">";
echo "<input type='radio' name='select' value='".$count."' />";
echo "<td width=".'10'.">";
$rooms = $row[0];
$srrooms = $rooms;
echo "<input type='hidden' name='srrooms".$count."' value='".$srrooms."' >"; // add counter value to every name of the input fields
echo $rooms;
echo "</td>";
echo "<td width=".'10'.">";
$no_roomss = $row[1];
$nosrrooms = $no_roomss;
echo "<input type='hidden' name='nosrrooms".$count."' value='".$nosrrooms."'>";
echo $no_roomss;
echo "</td>";
echo "<td width=".'10'.">";
$no_dayss = $row[2];
$nodays = $no_dayss;
echo "<input type='hidden' name='nodays".$count."' value='".$nodays."' >";
echo $no_dayss;
echo "</td>";
echo "<td width=".'10'.">";
$name = $row[3];
echo $name;
echo "</td>";
echo "</tr>";
$count++;
}
echo "<input name='count' type='hidden' id='count'>"; // hidden input where counter value will be stored
echo "</table>";
echo "<input type='submit' name='submitRooms' />";
echo "</center>";
echo "</form>";
?>
and then use jquery for saving the active radiobuttons count in the hidden count input field [after the above php code]
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script type='text/javascript'>
$(function(){
$('input[name="select"]').change(function(){
$('#count').val($("input[name='select']:checked").val());
});
});
</script>
then on your edit.php fetch the posted data as:
<?php
if(isset($_POST['submitRooms'])){
#$count = $_POST['count'];
#$srrooms = $_POST['srrooms'.$count];
#$nosrrooms = $_POST['nosrrooms'.$count];
#$nodays = $_POST['nodays'.$count];
echo 'Selected values are: '. $srrooms . $nosrrooms . $nodays;
}
?>
You didn't have added the whole form code so please add the above mentioned form code and the reason why your code is not working is that you haven't added the count with the input field names. And their is no use of fetching the posted data with count in the edit.php till you don't have the input fields named with the $count variable
echo "<input type='hidden' name='srrooms".$count."' value='".$srrooms."' >";
There is an error in my php that I cannot solve. Everything is working including 'insert' but not update but I don't know why. If you can help me it would be great. Thank you!
i cannot make update on PHP (Mysqli)
<?php
include("conn.php");
echo "<meta charset='utf-8'>";
?>
<?php
$id = $_GET['edi'];
$showrecs = "SELECT ID, English, Georgian FROM register WHERE ID='$id'";
$result = $conn->query($showrecs);
if(isset($_POST['update'])){
$Updatee = "UPDATE register SET English='".$_POST['English']."', Georgian='".$_POST['Georgian']."' WHERE ID='$id'";
$res=mysqli_query($conn, $Updatee);
if($res==1){
echo "წარმატებით განხორციელდა რედაქტირება.";
echo "<br>";
echo "<a href='view.php'>ჩანაწერების ნახვა</a>";
}
if($res==0){
echo "არაფერიც არ მოხდა";
}
exit();
} elseif ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "<form method=POST>";
echo "<tr>";
echo "<td>" . "<input type='text' name='id' value=" . $row['ID'] ." disabled>". "</td>";
echo "<td>" . "<input type='text' name='English' value=" . $row['English'] .">". " </td>";
echo "<td>" . "<input type='text' name='Georgian' value=" . $row['Georgian'] .">". " </td>";
echo "<td>" . "<input type='submit' name='update' value='შეცვლა'>" . " </td>";
echo "</form>";
echo "</br>";
echo "</br>";
}
} else {
echo "Error;";
}
$conn->close();
?>
I am trying to create a php page where the materials from database are populated. Users should be able to enter the quantity next to the item they wish to order and I have created a qty text field for this
<?php
session_start();
include("db.php");
$pagename="Order Material";
echo "<html>";
echo "<title>".$pagename."</title>";
echo "<h2>".$pagename."</h2>";
include ("detectlogin.php");
echo "<link rel=stylesheet type=text/css href=mystylesheet.css>";
$sql="select * from material";
$result=mysqli_query($con, $sql) or die(mysqli_error($con));
echo "<table border=1>";
echo "<tr>";
echo "<th>Material Name</th>";
echo "<th>Material Description</th>";
echo "<th>Toxicity Level</th>";
echo "</tr>";
while ($arraymaterials=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>".$arraymaterials['materialName']."</td>";
echo "<td>".$arraymaterials['materialDescrip']."</td>";
echo "<td>".$arraymaterials['materialToxicity']."</td>";
echo "<td>Enter Quantity</td>";
echo "<td><input type=text name=qty value=qty size=5></td>";
echo "<form action=request_material.php method=post>";
echo "<input type=hidden name=materialcode value=".$arraymaterials['materialCode'].">";
echo "<td><input type=submit value='Request'></td>";
echo "</form>";
echo "</tr>";
}
echo "</table>";
?>
However, I cannot successfully post the value of qty on to the next page even though I have $qty=$_POST['qty']; on my request_material.php. Do you know why this value entered in the qty field cannot be posted onto the request_material.php page? Do I need a session variable?
thanks
Because input tag name="qty" is outside the form tag
echo "<td><input type=text name=qty value=qty size=5></td>";// outside form tag
echo "<form action=request_material.php method=post>";
echo "<input type=hidden name=materialcode value=" . $arraymaterials['materialCode'] . ">";
echo "<td><input type=submit value='Request'></td>";
echo "</form>";
You need to add it inside your form tag as
echo "<form action=request_material.php method=post>";
echo "<td><input type=text name=qty value=qty size=5></td>";// add inside it
echo "<input type=hidden name=materialcode value=".$arraymaterials['materialCode'].">";
echo "<td><input type=submit value='Request'></td>";
echo "</form>";
Please try this: I have updated the code:
echo "<table border=1>";
echo "<tr>";
echo "<th>Material Name</th>";
echo "<th>Material Description</th>";
echo "<th>Toxicity Level</th>";
echo "</tr>";
if(mysqli_num_rows($result)>0)
{
echo "<form action=request_material.php method=post>";
while ($arraymaterials=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>".$arraymaterials['materialName']."</td>";
echo "<td>".$arraymaterials['materialDescrip']."</td>";
echo "<td>".$arraymaterials['materialToxicity']."</td>";
echo "<td>Enter Quantity</td>";
echo "<td><input type='text' name='qty[]' value='qty' size=5></td>";
echo "<input type=hidden name='materialcode[]' value=".$arraymaterials['materialCode'].">";
echo "<td><input type=submit value='Request'></td>";
echo "</tr>";
}
echo "</form>";
}
echo "</table>";
In request_material.php check value of $qty.It will be an array.for more details print_r($_POST) in request_material.php
I am creating an online examination system where am fetching questions and answers from database and displays options in radio button. But, the problem is if i click save it just saves one answer not answer from all questions
php codes for fetching questions
$quer=" SELECT * FROM questionset ORDER BY RAND() ";
$query=mysqli_query($sql,$quer);
while($row = mysqli_fetch_array($query))
{
$na= $row['qus'];
$opa= $row['opa'];
$opb= $row['opb'];
$opc= $row['opc'];
$opd= $row['opd'];
echo "<div class='pr3'>";
echo "<div id='question'>";
echo $na;
echo "</div>";
echo "<br/>";
echo "<form name='cart' method='post'>";
echo "<input type='radio' name='ans' value='" . $opa. "' onclick='answ(this.value)' >";
echo $opa;
echo "<br/>";
echo "<input type='radio' name='ans' value='" . $opb. "' onclick='answ(this.value)'>";
echo $opb;
echo "<br/>";
echo "<input type='radio' name='ans' value='" . $opc. "' onclick='answ(this.value)'>";
echo $opc;
echo "<br/>";
echo "<input type='radio' name='ans' value='" . $opd. "' onclick='answ(this.value)'>";
echo $opd;
echo "<br/>";
echo "<input type='text' id='ansval' name='ansval' >";
echo "</form>";
echo " </div>";
}
Javascript that updates just one text box
<script>
function answ(answer) {
document.getElementById("ansval").value = answer;
}
</script>
The radio buttons name are all same for all questions. You have to make the radio buttons names dynamically for each answer set. You can use the following code :
$quer=" SELECT * FROM questionset ORDER BY RAND() ";
$query=mysqli_query($sql,$quer);
while($row = mysqli_fetch_array($query))
{
$questionId = $row['questionId']; //primary key of question table
$na= $row['qus'];
$opa= $row['opa'];
$opb= $row['opb'];
$opc= $row['opc'];
$opd= $row['opd'];
echo "<div class='pr3'>";
echo "<div id='question'>";
echo $na;
echo "</div>";
echo "<br/>";
echo "<form name='cart' method='post'>";
echo "<input type='radio' name='ans<?php echo $questionId; ?>' value='" . $opa. "' onclick='answ(this.value,'<?php echo $questionId; ?>')' >";
echo $opa;
echo "<br/>";
echo "<input type='radio' name='ans<?php echo $questionId; ?>' value='" . $opb. "' onclick='answ(this.value,'<?php echo $questionId; ?>')'>";
echo $opb;
echo "<br/>";
echo "<input type='radio' name='ans<?php echo $questionId; ?>' value='" . $opc. "' onclick='answ(this.value,'<?php echo $questionId; ?>')'>";
echo $opc;
echo "<br/>";
echo "<input type='radio' name='ans<?php echo $questionId; ?>' value='" . $opd. "' onclick='answ(this.value,'<?php echo $questionId; ?>')'>";
echo $opd;
echo "<br/>";
echo "<input type='text' id='ansval<?php echo $questionId; ?>' name='ansval<?php echo $questionId; ?>' >";
echo "</form>";
echo " </div>";
}
And You javascript function will be looks like :
<script>
function answ(answer,qId) {
document.getElementById("ansval"+qId).value = answer;
}
</script>
After the answer submit you can get the submitted values in same way. i.e $_POST['ansval'.$questionId]; Before get the value you have to create another loop to get all question Ids.
ID field must be unique
++$counter;
echo "";
$_POST['ansval1'],$_POST['ansval2'],$_POST['ansval3'].....
Please refer to the image below:
http://i.stack.imgur.com/6hBPC.png
For instance, if a user clicks the button on the row which says "You have a quiz for math", the "Quiz ID" value of THAT row would then be passed to another PHP file.
Here's my current code:
<?php
$con=mysqli_connect("127.0.0.1", "root", "", "quizmaker");
if (mysqli_connect_errno($con))
{
echo "MySqli Error: " . mysqli_connect_error();
}
$now=date("m/d/Y");
$sql=mysqli_query($con,"SELECT * FROM quiz_query WHERE quiz_date='$now'");
$count=mysqli_num_rows($sql);
if($count>=1)
{
echo "<table border='1' width='50%'>";
echo "<form action='answer_quiz.php' method='post'>";
echo "<tr>
<td>You have a pending quiz!</td><td> </td><td> </td>
</tr>";
$number=1;
while($result=mysqli_fetch_array($sql))
{
echo "<tr>";
echo "<td>You have a quiz for " . $result['subject'] . "</td>";
echo "<td>Quiz ID: " .$result['quiz_ID']. "</td>";
echo "<td><input type='submit' name='button' id='button' value='Take Quiz'>";
echo "<input type='hidden' name='quiz[$number]' value='$result[quiz_ID]'>";
echo "</td>";
echo "</tr>";
$number++;
}
echo "</form>";
echo "</table>";
}
else
{
"You have no quiz! :D";
}
mysqli_close($con);
?>
Move this line:
echo "<form action='answer_quiz.php' method='post'>";
Inside of the while loop.
Also, change
echo "<input type='hidden' name='quiz[$number]' value='$result[quiz_ID]'>"
with
echo "<input type='hidden' name='quizId' value='$result[quiz_ID]'>"
Now, in answer_quiz.php you'll receive $_POST['quizId'] with the value you need.
Change your while to :
while( $row = $result->fetch_array(MYSQLI_ASSOC)){
echo $row['subject'];
}
You are forgetting quotes around your variable:
Instead of
echo "<input type='hidden' name='quiz[$number]' value='$result[quiz_ID]'>";
It should be
echo "<input type='hidden' name='quiz[$number]' value='$result[\"quiz_ID\"]'>";