jquery date picker doesn't appear - php

Question

jQuery code:
<script src="js/jquery-1.10.1.min.js"></script>
<script src="js/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#book').validate({
rules : {
name : 'required',
sdate : {
required : true,
date : true
},
seats :{
required : true,
number : true,
range:[1,9]
},
},// end rules
}); // end validate()
$('#sdate').datepicker({
minDate : new Date("<?php echo $start;?>"),
maxDate : new Date("<?php echo $end?;>")
});
});
</script>`
Value for date is retrieved from the MySQL database and stored in the variable after converting it to date format. Its passed to the date picker - minDate and maxDate. If I manually pass the date to the minDate and maxDate, the datepicker appears, in the above case even the validation doesn't work nor does the datepicker appear.
PHP code:
$st=$value->getStart();
$start = date("Y-m-d h:i:s", strtotime($st));
$ed=$value->getEnd();
$end = date("Y-m-d h:i:s", strtotime($ed));
HTML code:
Show Date <input name="sdate" type="text" id="sdate" />
Any help on this issue is appreciated. Thanks in advance.

Answer 1

Time in format Y-m-d h:i:s will not with javascript's Date object. Try to use for example this format: D M d Y H:i:s O
$st=$value->getStart();
$start = date("D M d Y H:i:s O", strtotime($st));
$ed=$value->getEnd();
$end = date("D M d Y H:i:s O", strtotime($ed));