displaying mysql column names in an array along with its data - php

Question

I am trying to fetch records from MySql and display them in an array along with column headers using PDO, reason I am doing this is because i want to export them in an excel and I am using php-excel
right now the following code displays the records perfectly fine in an array and I am able to export them just fine
while ($row[] = $stmt->fetch(PDO::FETCH_ASSOC)) :
$data = $row;
endwhile;
The array i get as a result of above code is as following
Array
(
[0] => Array
(
[user_id] => 1
[fname] => First Name
[lname] => Last Name
)
[1] => Array
(
[user_id] => 91
[fname] => First Name
[lname] => Last Name
)
)
But the problem is I am missing column headers in excel, so for that I need to display the MySql column headers in an array as well.
I am using the following code to create an array for column headers
for ($i = 0; $i < $stmt->columnCount(); $i++) {
$col = $stmt->getColumnMeta($i);
$columns[] = $col['name'];
}
but this gives me an array in following format
Array
(
[0] => user_id
[1] => fname
[2] => lname
)
whereas I need the column header array in following format
Array
(
[0] => Array
(
[user_id] => user_id
[fname] => fname
[lname] => lname
)
)
I will appreciate any help.

Answer 1

I assume you want the headers to be in the same array. In that case you would do this before the while loop
$data[0] = array();
for ($i = 0; $i < $stmt->columnCount(); $i++) {
$col = $stmt->getColumnMeta($i);
$data[0][$col['name']] = $col['name'];
}
Also, the while loop is a little inefficient. You're pushing each row into the $row array and then copying it into $data every single time. It should be done like this instead:
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) :
$data[] = $row;
endwhile;
This should get you:
$data = Array
(
[0] => Array
(
[user_id] => user_id
[fname] => fname
[lname] => lname
)
[1] => Array
(
[user_id] => value...
...
)
...
)

Answer 2

Instead of letting it auto-number, just provide the name again as the key:
for ($i = 0; $i < $stmt->columnCount(); $i++) {
$col = $stmt->getColumnMeta($i);
$columns[$col['name']] = $col['name'];
}
Example: https://eval.in/117424

Answer 3

Might be easier:
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
if(!isset($data)) {
$data[] = array_combine(array_keys($row), array_keys($row));
}
$data[] = $row;
}
Or you could add them after the fact using array_unshift().
Or in a separate array:
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
if(!isset($col)) {
$col[] = array_combine(array_keys($row), array_keys($row));
}
$data[] = $row;
}