How to echo/print only a certain piece of input? - php

I want to echo/print only a certain piece of input. For example i have this youtube url http://www.youtube.com/watch?v=p963CeTtJVM how would i be able to only echo the last piece of :"p963CeTtJVM" from the input. As far as i know their always 11 symbols.
Code:
if (empty($_POST["website"]))
{$website = "";}
else
{
$website = test_input($_POST["website"]);
// check if URL address syntax is valid (this regular expression also allows dashes in the URL)
if (!preg_match("/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&##\/%?=~_|!:,.;]*[-a-z0-9+&##\/%=~_|]/i",$website))
{
$websiteErr = "Invalid URL";
}
}

list ($void, $query_string) = split('?', $url); // or list(,$qs)
parse_str($query_string, $data);
var_dump($data);
For this specific string substr($str, -11) will take the last 11 chars, but that doesn't include other tags. Check out parse_str, it will probably save you a headache in the long run.

I hope it can help you.
<?php
$url = 'http://www.youtube.com/watch?v=p963CeTtJVM';
$urlParts = explode('v=', $url);
if (count($urlParts) == 2 && isset($urlParts[1])) {
echo "youtube code : {$urlParts[1]}";
} else {
echo "Invalid Youtube url.";
}

You can use substr method to return part of a string.

You can use the explode function to seperate the video ID and the rest of the link like this:
$array = explode("=", $website);
echo $array[1];

This parses the URL into its component parts, then parses the query string into an associative array.
$url = parse_url($url);
parse_str($url['query'], $params);
$v = $params['v'];

Related

Validate an email address in the URL

I will validate this URL with an email address inside.
These two domains are allowed:
https://www.example.com/secure/index.php?ID=john#example.com
https://www.example.com/secure/index.php?ID=john#example-test.com
All names before the # in the email address allowed.
When the user inserts another domain after the #, like this:
https://www.example.com/secure/index.php?ID=john#gmail.com
they will get an error. How can I do this?
Try this:
$email = $_GET['ID']; // remember to filter this!
$regex = '#\w+#(?<domain>\w+\-?\w+\.\w+)#';
preg_match($regex, $email, $matches);
$domain = $matches['domain'];
if ($domain !== 'example-test.com') {
// Unauthorised
}
See a working example here https://3v4l.org/SorhQ
See the regex and tweak if required here https://regex101.com/r/uDzOzm/1/
You can use the simple explode method to extract the domain name. see the code.
$parts = explode("#", "johndoe#domain.com");
$domain = $parts[1];
if(!in_array($domain, array('domain.com')))
{
//Redirect it wherever you want
}
You can do it:
if (isset($_GET['ID'])) {
$domain_name = substr(strrchr($_GET['ID'], "#"), 1);
if ($domain_name != "example-test.com"){
Forbidden....
}
}

PHP Strip domain name from url

I know there is a LOT of info on the web regarding to this subject but I can't seem to figure it out the way I want.
I'm trying to build a function which strips the domain name from a url:
http://blabla.com blabla
www.blabla.net blabla
http://www.blabla.eu blabla
Only the plain name of the domain is needed.
With parse_url I get the domain filtered but that is not enough.
I have 3 functions that stips the domain but still I get some wrong outputs
function prepare_array($domains)
{
$prep_domains = explode("\n", str_replace("\r", "", $domains));
$domain_array = array_map('trim', $prep_domains);
return $domain_array;
}
function test($domain)
{
$domain = explode(".", $domain);
return $domain[1];
}
function strip($url)
{
$url = trim($url);
$url = preg_replace("/^(http:\/\/)*(www.)*/is", "", $url);
$url = preg_replace("/\/.*$/is" , "" ,$url);
return $url;
}
Every possible domain, url and extension is allowed. After the function is finished, it must return a array of only the domain names itself.
UPDATE:
Thanks for all the suggestions!
I figured it out with the help from you all.
function test($url)
{
// Check if the url begins with http:// www. or both
// If so, replace it
if (preg_match("/^(http:\/\/|www.)/i", $url))
{
$domain = preg_replace("/^(http:\/\/)*(www.)*/is", "", $url);
}
else
{
$domain = $url;
}
// Now all thats left is the domain and the extension
// Only return the needed first part without the extension
$domain = explode(".", $domain);
return $domain[0];
}
How about
$wsArray = explode(".",$domain); //Break it up into an array.
$extension = array_pop($wsArray); //Get the Extension (last entry)
$domain = array_pop($wsArray); // Get the domain
http://php.net/manual/en/function.array-pop.php
Ah, your problem lies in the fact that TLDs can be either in one or two parts e.g .com vs .co.uk.
What I would do is maintain a list of TLDs. With the result after parse_url, go over the list and look for a match. Strip out the TLD, explode on '.' and the last part will be in the format you want it.
This does not seem as efficient as it could be but, with TLDs being added all the time, I cannot see any other deterministic way.
Ok...this is messy and you should spend some time optimizing and caching previously derived domains. You should also have a friendly NameServer and the last catch is the domain must have a "A" record in their DNS.
This attempts to assemble the domain name in reverse order until it can resolve to a DNS "A" record.
At anyrate, this was bugging me, so I hope this answer helps :
<?php
$wsHostNames = array(
"test.com",
"http://www.bbc.com/news/uk-34276525",
"google.uk.co"
);
foreach ($wsHostNames as $hostName) {
echo "checking $hostName" . PHP_EOL;
$wsWork = $hostName;
//attempt to strip out full paths to just host
$wsWork = parse_url($hostName, PHP_URL_HOST);
if ($wsWork != "") {
echo "Was able to cleanup $wsWork" . PHP_EOL;
$hostName = $wsWork;
} else {
//Probably had no path info or malformed URL
//Try to check it anyway
echo "No path to strip from $hostName" . PHP_EOL;
}
$wsArray = explode(".", $hostName); //Break it up into an array.
$wsHostName = "";
//Build domain one segment a time probably
//Code should be modified not to check for the first segment (.com)
while (!empty($wsArray)) {
$newSegment = array_pop($wsArray);
$wsHostName = $newSegment . $wsHostName;
echo "Checking $wsHostName" . PHP_EOL;
if (checkdnsrr($wsHostName, "A")) {
echo "host found $wsHostName" . PHP_EOL;
echo "Domain is $newSegment" . PHP_EOL;
continue(2);
} else {
//This segment didn't resolve - keep building
echo "No Valid A Record for $wsHostName" . PHP_EOL;
$wsHostName = "." . $wsHostName;
}
}
//if you get to here in the loop it could not resolve the host name
}
?>
try with preg_replace.
something like
$domain = preg_replace($regex, '$1', $url);
regex
function test($url)
{
// Check if the url begins with http:// www. or both
// If so, replace it
if (preg_match("/^(http:\/\/|www.)/i", $url))
{
$domain = preg_replace("/^(http:\/\/)*(www.)*/is", "", $url);
}
else
{
$domain = $url;
}
// Now all thats left is the domain and the extension
// Only return the needed first part without the extension
$domain = explode(".", $domain);
return $domain[0];
}

Get youtube id for all url types

The following code works with all YouTube domains except for youtu.be. An example would be: http://www.youtube.com/watch?v=ZedLgAF9aEg would turn into: ZedLgAF9aEg
My question is how would I be able to make it work with http://youtu.be/ZedLgAF9aEg.
I'm not so great with regex so your help is much appreciated. My code is:
$text = preg_replace("#[&\?].+$#", "", preg_replace("#http://(?:www\.)?youtu\.?be(?:\.com)?/(embed/|watch\?v=|\?v=|v/|e/|.+/|watch.*v=|)#i", "", $text)); }
$text = (htmlentities($text, ENT_QUOTES, 'UTF-8'));
Thanks again!
//$url = 'http://www.youtube.com/watch?v=ZedLgAF9aEg';
$url = 'http://youtu.be/ZedLgAF9aEg';
if (FALSE === strpos($url, 'youtu.be/')) {
parse_str(parse_url($url, PHP_URL_QUERY), $id);
$id = $id['v'];
} else {
$id = basename($url);
}
echo $id; // ZedLgAF9aEg
Will work for both versions of URLs. Do not use regex for this as PHP has built in functions for parsing URLs as I have demonstrated which are faster and more robust against breaking.
Your regex appears to solve the problem as it stands now? I didn't try it in php, but it appears to work fine in my editor.
The first part of the regex http://(?:www\.)?youtu\.?be(?:\.com)?/matches http://youtu.be/ and the second part (embed/|watch\?v=|\?v=|v/|e/|.+/|watch.*v=|) ends with |) which means it matches nothing (making it optional). In other words it would trim away http://youtu.be/ leaving only the id.
A more intuitive way of writing it would be to make the whole if grouping optional I suppose, but as far as I can tell your regex is already solving your problem:
#http://(?:www\.)?youtu\.?be(?:\.com)?/(embed/|watch\?v=|\?v=|v/|e/|.+/|watch.*v=)?#i
Note: Your regex would work with the www.youtu.be.com domain as well. It would be stripped away, but something to watch out for if you use this for validating input.
Update:
If you want to only match urls inside [youtube][/youtube] tags you could use look arounds.
Something along the lines of:
(?<=\[youtube\])(?:http://(?:www\.)?youtu\.?be(?:\.com)?/(?:embed/|watch\?v=|\?v=|v/|e/|[^\[]+/|watch.*v=)?)(?=.+\[/youtube\])
You could further refine it by making the .+ in the look ahead only match valid URL characters etc.
Try this, hope it'll help you
function YouTubeUrl($url)
{
if($url!='')
{
$newUrl='';
$videoLink1=$url;
$findKeyWord='youtu.be';
$toBeReplaced='www.youtube.com';
if(IsContain('watch?v=',$videoLink1))
{
$newUrl=tMakeUrl($videoLink1);
}
else if(IsContain($videoLink1, $findKeyWord))
{
$videoLinkArray=explode('/',$videoLink1);
$Protocol='';
if(IsContain('://',$videoLink1))
{
$protocolArray=explode('://',$videoLink1);
$Protocol=$protocolArray[0];
}
$file=$videoLinkArray[count($videoLinkArray)-1];
$newUrl='www.youtube.com/watch?v='.$file;
if($Protocol!='')
$newUrl.=$Protocol.$newUrl;
else
$newUrl=tMakeUrl($newUrl);
}
else
$newUrl=tMakeUrl($videoLink1);
return $newUrl;
}
return '';
}
function IsContain($string,$findKeyWord)
{
if(strpos($string,$findKeyWord)!==false)
return true;
else
return false;
}
function tMakeUrl($url)
{
$tSeven=substr($url,0,7);
$tEight=substr($url,0,8);
if($tSeven!="http://" && $tEight!="https://")
{
$url="http://".$url;
}
return $url;
}
You can use bellow function for any of youtube URL
I hope this will help you
function checkYoutubeId($id)
{
$youtube = "http://www.youtube.com/oembed?url=". $id ."&format=json";
$curl = curl_init($youtube);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$return = curl_exec($curl);
curl_close($curl);
return json_decode($return, true);
}
This function return Youtube video detail if Id match to youtube video ID
A little improvement to #rvalvik answer would be to include the case of the mobile links (I've noticed it while working with a customer who used an iPad to navigate, copy and paste links). In this case, we have a m (mobile) letter instead of www. Regex then becomes:
#(https?://)?(?:www\.)?(?:m\.)?(?:youtu\.be/|youtube\.com(?:/embed/|/v/|/watch?.*?v=))([\w\-]{10,12}).*#x
Hope it helps.
A slight improvement of another answer:
if (strpos($url, 'feature=youtu.be') === TRUE || strpos($url, 'youtu.be') === FALSE )
{
parse_str(parse_url($url, PHP_URL_QUERY), $id);
$id = $id['v'];
}
else
{
$id = basename($url);
}
This takes into account youtu.be still being in the URL, but not the URL itself (it does happen!) as it could be the referring feature link.
Other answers miss out on the point that some youtube links are part of a playlist and have a list paramater also which is required for embed code. So to extract the embed code from link one could try this JS code:
let urlEmbed = "https://www.youtube.com/watch?v=iGGolqb6gDE&list=PL2q4fbVm1Ik6DCzm9XZJbNwyHtHGclcEh&index=32"
let embedId = urlEmbed.split('v=')[1];
let parameterStringList = embedId.split('&');
if (parameterStringList.length > 1) {
embedId = parameterStringList[0];
let listString = parameterStringList.filter((parameterString) =>
parameterString.includes('list')
);
if (listString.length > 0) {
listString = listString[0].split('=')[1];
embedId = `${parameterStringList[0]}?${listString}`;
}
}
console.log(embedId)
Try it out here: https://jsfiddle.net/AMITKESARI2000/o62dwj7q/
try this :
$string = explode("=","http://www.youtube.com/watch?v=ZedLgAF9aEg");
echo $string[1];
would turn into: ZedLgAF9aEg

Check if a user entered an email address that has a domain similar to the domain name they enter above

In my signup form, I ask users to enter an email with the same domain name as they enter in the url field above.
Right now, I collect data this way:
URL : http://www.domain.com The domain.com part is what the user enters. The http://www is hard coded.
Email : info# domain.com The bold part is entered by the user. The # is hard coded.
The domain.com part in the url and domain.com part in the email should match. Right now, I can match the two fields since they are separate.
But I want to give up the above approach and make the user enter the entire domain name and email. When that's the case, what would be a good way to check if a user entered an email with the same domain he entered in the url field above.
I'm doing all this using php.
<?php
//extract domain from email
$email_domain_temp = explode("#", $_POST['email']);
$email_domain = $email_domain_temp[1];
//extract domain from url
$url_domain_temp = parse_url($_POST['url']);
$url_domain = strip_out_subdomain($url_domain_temp['host']);
//compare
if ($email_domain == $url_domain){
//match
}
function strip_out_subdomain($domain){
//do nothing if only 1 dot in $domain
if (substr_count($domain, ".") == 1){
return $domain;
}
$only_my_domain = preg_replace("/^(.*?)\.(.*)$/","$2",$domain);
return $only_my_domain;
}
So what this does is :
First, split the email string in 2 parts in an array. The second part is the domain.
Second, use the php built in function to parse the url, then extract the "host", while removing the (optionnal) subdomain.
Then compare.
you can do this by explode()
supp url = bla#gmail.com
$pieces = explode("#", $url);
$new = $pieces[1]; //which will be gmail.com
now again explode
$newpc= explode(".", $new );
$new1 = $newpc[0]; //which will be gmail
This is my version (tested, works):
<?php
$domain = 'www2.example.com'; // Set domain here
$email = 'info#example.com'; // Set email here
if(!preg_match('~^https?://.*$~i', $domain)) { // Does the URL start with http?
$domain = "http://$domain"; // No, prepend it with http://
}
if(filter_var($domain, FILTER_VALIDATE_URL)) { // Validate URL
$host = parse_url($domain, PHP_URL_HOST); // Parse the host, if it is an URL
if(substr_count($host, '.') > 1) { // Is there a subdomain?
$host = substr($host, -strrpos(strrev($host), '.')); // Get the host
}
if(strpos(strrev($email), strrev($host)) === 0) { // Does it match the end of the email?
echo 'Valid!'; // Valid
} else {
echo 'Does not match.'; // Invalid
}
} else {
echo 'Invalid domain!'; // Domain is invalid
}
?>
you could do:
$parsedUrl = parse_url($yourEnteredUrl);
$domainHost = str_replace("www.", "", $parsedUrl["host"]);
$emailDomain = array_pop(explode('#', $yourEnteredEmail));
if( $emailDomain == $domainHost ) {
//valid data
}
$email = 'myemail#example.com';
$site = 'http://example.com';
$emailDomain = ltrim( strstr($email, '#'), '#' );
// or automate it using array_map(). Syntax is correct only for >= PHP5.4
$cases = ['http://'.$emailDomain, 'https://'.$emailDomain, 'http://www.'.$emailDomain, 'https://www.'.$emailDomain];
$bSameDomain = in_array($site, $cases);
var_dump($bSameDomain);
Use regular expressions with positive lookbehinds(i.e only return the expression I'd like to match if it is preceded by a certain pattern, but don't include the lookbehind itself in the match), like so:
<?php
$url = preg_match("/(?<=http:\/\/www\.).*/",$_POST['url'],$url_match);
$email = preg_match("/(?<=#).*/",$_POST['email'],$email_match);
if ($url_match[0]==$email_match[0]) {
// Success Code
}
else {
// Failure Code
}
?>
Of course this is a bit oversimplified as you also need to account for https or www2 and the likes, but these require only minor changes to the RegExp, using the question mark as the "optional" operator

Determining URL or String PHP

I'm making a link and text service, but I have a problem, which is: there is only 1 input text form, and the user could paste something like this:
http:// asdf .com - which would register as a link, or 'asdf http:// test .com' because of the http://, it would register as a url, or
asdf - which would register as a string, because it doesn't contain http://
BUT my problem arises when the user writes something like:
asdf http://asdf.com, which in my current program outputs a "url" value. I've been experimenting for about an hour now, and I've got 3 bits of code (they were all in the same document being commented, so forgive me if they give errors!)
<?
$str = $_POST['paste'];
if(stristr($str, "http://")) {
$type = "url";
}
if(stristr($str, "https://")) {
$type = "url";
}
if($type!="url") {
$type = "string";
}
?>
Next:
<?
$type = "url";
if($type=="url"){
$t = substr($str, 8);
if(stristr($t, "https://")==$t){
$type = "url";}
if(stristr($t, "https://")==$t){
$type = "url";}
if(stristr($t, "http://")!=$t){
$type = "string";}
if(stristr($t, "https://")!=$t){
$type = "string";}
}
echo $type;
?>
Next:
<?
$url = "hasttp://cake.com";
if(stristr($url, "http://")=="") {
$type = "string"; } else {
$type = "url";
$sus = 1;}
if(stristr($url, "http://")==$url) {
$type = "url"; }
if($sus==1) {
$r = substr($url, 7);
if(stristr($r,"http://")!="http://") {
$type = "url"; }
if($r=="") {
$type = "string";
}
}
echo $type;
?>
I have no clue how I could go about classifying a string like 'asdf http://asdf.com' as a string, whilst classifying 'asdf' as a string, and classifying 'http://asdf.com' as a url.. Another idea I haven't tried yet is strpos, but that's what I'm working on now.
Any ideas?
Thanks alot! :)
Some parts of this question are getting cut off for some reason, apologies!
$type = '';
if (preg_match('%^https?://[^\s]+$%', $url)) {
$type = 'url';
} else {
$type = 'string';
}
This will match any value which starts with http:// or https://, and does not contain any space in it as type url. If the value does not start with http:// or https://, or it contains a space in it, it will be type string.
PHP parse_url is your function:
On seriously malformed URLs, parse_url() may return FALSE.
If the component parameter is omitted, an associative array is returned. At least one element will be present within the array. Potential keys within this array are:
scheme - e.g. http
host
port
user
pass
path
query - after the question mark ?
fragment - after the hashmark #
If the component parameter is specified, parse_url() returns a string (or an integer, in the case of PHP_URL_PORT) instead of an array. If the requested component doesn't exist within the given URL, NULL will be returned.
If I'm understanding the problem correctly you want to detect when the user inputs both a string and a url and parse each of them correspondingly.
Try using explode(" ", $userInput);, this will return an array containing all strings separated by a space. Than you can check that for each element in the array and set the type.
$type = strpos($str, 'http') === 0 ? 'url' : 'string':
The strpos function returns the position of a match within a string or FALSE if no match. The tripple equals checks that the result does not only translates to 0 (as FALSE would have done), but that it is in fact integer as well (i.e., the string begins with http).
You could also use something like
switch (true) {
case strpos(trim($str), 'http://') === 0:
case strpos(trim($str), 'https://') === 0:
$type = 'url';
break;
default:
$type = 'string';
break; // I know this is not needed, but it is pretty :-)
}
You should use a regular expression to check if the string starts with http
if(preg_match('/^http/',$string_to_check)){
//this is a url
}

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