Center Logo Inside Dynamic li Navigation - php

So i have a CMS which uses a foreach loop to generate the navigation which consists of individual list items inside a ul.
Basically what I want is to have my logo inserted in the center of these links, with an equal number of links on either side.
I've got my code to split up into two different columns of navigation with a gap, but I cant figure out where to place the logo div so it doesn't repeat more than once, current code also throws out some empty list items which I don't need.
<ul>
<?php $i = 0; foreach($items as $item): ?>
<li><a<?php ecco($item->isOpen(), ' class="active"') ?> href="<?php echo $item->url() ?>"><?php echo html($item->title());?></a></li>
<?php if (++$i % 3 === 0 && $i !== count($items)) echo "</li><li>"; endforeach ?>
</ul>
Thanks.

How about something like this?
UPDATE
Since your count doesn't work, try this:
<ul>
<?php
$j = 0;
$breakPoint = 0;
foreach($items as $item) {
$j++;
$breakPoint = $j;
}
$i = 0;
foreach($items as $item) { ?>
if ($i === $breakPoint) {
/* insert Logo Code */
} else { ?>
<li><a<?php ecco($item->isOpen(), ' class="active"') ?> href="<?php echo $item->url() ?>"><?php echo html($item->title());?></a></li>
<?php
}
$i++;
} ?>
</ul>
Haven't tested it. And it depends if you have a odd or even number of $item elements.

Related

PHP - How to use a div to wrap all items Inside a foreach loop

I have been scratching my head for half hour now trying to figure this out
I have a wrapper div inside a foreach loop and I'm trying to force it to echo one and not duplicate
foreach ($apples as $apple) {
//echo only once bellow
<div class="Wrapper">
//echo only once Above
echo $apple;
//echo only once bellow
</div>
//echo only once Above
}
I do not wish to move my Wrapper div outside the foreach, It is very important for the div to be inside the foreach and to be without duplicates.
You didn't mention but If you need to put Wrapper div only if you have any count in $apples variable then simply check with if(count($apples)) and then put Wrapper
<?php
if(count($apples)){
echo '<div class="Wrapper">';
foreach ($apples as $apple) {
echo $apple;
}
echo '</div>';
}
?>
Note: I know this is not good way to write but as per his condition I am suggesting this code.
I don't know why you don't want to put div outside foreach loop but anyway you can use the following code to achieve that...
<?php
foreach ($apples as $apple) {
static $i = 0;
if ($i == 0) {
echo "<div class='Wrapper'>";
}
echo $apple;
$i++;
if ($i == count($apples)){
echo "</div>";
}
}
?>
Maybe this will help since you want to keep it inside foreach loop
$numItems = count($arr);
$i = 0;
foreach($arr as $ar) {
$i = $i+1;
if ($i == 1) {
echo '<div class="class">';
}
// do your stuff
if($i == $numItems) {
echo "</div>";
}
}

PHP - Assign some class to li tag based on some condition inside loop

I have following Two-dimensional array:
$data = array
(
array("1.2"),
array("2.5"),
array("4.7"),
array("5.7"),
array("3.5"),
array("7.2"),
array("4.7"),
array("3.5")
);
Now I am displaying my records through loop:
<ul>
<?php
for($i=0; $i<count($data); $i++):
?>
<li><?php echo $data[$i][0]; ?></li>
<?php
endfor;
?>
</ul>
and this is the result:
Now I want to check some condition inside loop and add class="red" to li.
Example 1:
If 4.7 found inside the loop, add class="red" to next all li tags.
Example 2:
If 3.5 found inside the loop, add class="red" to next all li tags.
Example 3:
If 5.7 found inside the loop, add class="red" to next all li tags.
Any idea how to add class to li tags when some condition match.
Thanks.
You can just switch on the class as soon as a matching item is found.
$switch_value = '4.7'; // set the value where you want to switch colors
$class = ''; // initialize the class to empty string
foreach ($data as $value) {
echo "<li$class>$value[0]</li>";
// set the class to red the first time the value is found
if ($value[0] == $switch_value) $class = ' class="red"';
}
It's important to set the class after echoing the list item to get the output you want.
You can do it this way:
<ul>
<?php
$class = ''; $num = 4.7;
for($i=0; $i<count($data); $i++):
?>
<li class='<?php echo $class; ?>'><?php echo $data[$i][0]; ?></li>
<?php
if( $data[$i][0] == $num ) $class = 'red';
endfor;
?>
</ul>
Just change the $num to desired value programmatically.
Edit: move the if block to end of for block to leave the number's occurrence.
Just check a condition with a value, and assign it
<ul>
<?php
$isRed = false;
$value_to_search = 3.5;
for($i=0; $i<count($data); $i++):
?>
<li class="<?php echo ($isRed == true)?'redClass':'';"><?php echo $data[$i][0]; ?></li>
<?php
if($data[$i][0] == $value_to_search )
$isRed = true;
endfor;
?>
</ul>
I guess you can use something like:
<ul>
<?php
$red = false;
for($i=0; $i<count($data); $i++){
if($data[$i][0] == "3.5" or $data[$i][0] == "4.7" or $data[$i][0] == "5.7" or $red){
echo "<li class=\"red\">{$data[$i][0]}</li>";
$red = true;
}else{
echo "<li>{$data[$i][0]}</li>";
}
}
?>
</ul>
Output:
<ul><li>1.2</li><li>2.5</li><li class="red">4.7</li><li class="red">5.7</li><li class="red">3.5</li><li class="red">7.2</li><li class="red">4.7</li><li class="red">3.5</li></ul>
Ideone Demo
http://ideone.com/s2gdmG

Embed div elements in php foreach? [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I tried to embed 2 elements with class "elementcontent" in element with class "row", can someone tell me what's wrong in my code (see second code block)?
This is raw code without if request to embed 2 elements in one:
<?php
$i = 1;
foreach ($items as $key=>$item) {
?>
<div class="row">
<div class="elementcontent">element content</div>
</div>
<?php
$i++;
}
?>
This is my code where i try to embed elements:
<?php
$i = 1;
foreach ($items as $key=>$item) {
?>
<div class="row">
<div class="elementcontent">element content</div>
<?php
if ($i % 2 == 0) {
echo '</div><div class="row">';
}
?>
</div>
<?php
$i++;
}
?>
This way i found with help from this source: How can I alternate div elements in php foreach loop
To place two elements in each row you want to test the $key -
<?php
$items = array('foo', 'bar', 'glorp', 'baz');
foreach ($items as $key=>$item) {
if($key % 2 == 0){
echo '<div class="row">';
echo '<div class="elementcontent">'. $item . '</div>';
} else {
echo '<div class="elementcontent">'. $item . '</div>';
echo '</div>';
}
}
?>
By doing it with the key there is no need for an iterator.
If I understood you, what you want is a ROW element, with 2 ELEMENTCONTENT inside of it.
You can do this like this:
<?php
$i = 0;
foreach ($items as $key => $item) {
$row = ($i % 2 == 0); ?>
<?php if ($row): ?><div class="row"><?php endif; ?>
<div class="elementcontent">element content</div>
<?php if (!$row): ?></div><?php endif; ?>
<?php
$i++;
}
if (count($items) % 2 === 1) {
echo '</div>';
}
?>
Every 2 items will be wrapped with a div with a class row.
I've used PHP's alternative syntax for more elegant code.
Answer updated due to an error and also checking if the number of items is an odd number, to close the div tag.

str_replace in model or the view?

Model
function Show_all_products()
{
return $this->db->get('printer')->result();
}
View
The table contents is being echoed in a loop
$i = -1;
echo '<ul class="products">'; foreach($products as $product) :
if($i % 11 == 10) echo '</ul><ul class="products">';
?>
<li><?php echo $product->name; ?> </li>
<?php
$i += 1;
endforeach;
echo "</ul>";
The product names are saved as Something_Something_Blah I cannot modify the product names as they are configured to show clean URL's and Breadcrumbs.
The issue is that the links in this view show as Something_Something_Blah
I tried to do a str_replace as $product = str_replace('_',' ', $product); However this isn't working.
How do i strip the '_' and insert \s ?
I see you have <?php echo $product->name; ?> which would mean $product is an object.
So you should call str_replace('_', ' ', $product->name);
<?php
$i = -1;
echo '<ul class="products">'; foreach($products as $product) :
$product->name = str_replace('_',' ', $product->name);
if($i % 11 == 10) echo '</ul><ul class="products">';
?>
<li><?php echo $product->name; ?> </li>
<?php
$i += 1;
endforeach;
echo "</ul>";
?>
str_replace must be called from within the foreach or an error will be returned. That was my mistake.
As per PHP documentation, str_replace() accepts a string or array as it's third argument. You are passing it an object. You should pass $product->name to it.
Furthermore, please strive to embed PHP in your HTML and not HTML in your PHP. You're going to find yourself echoing everything. You don't need to manually create the $i iterator either, because the foreach loop will create one for you, provided you use the foreach($x as $key => $val) syntax. You can lose the <?php echo $var;?> for <?= $var;?> too, AND concatenate with the . symbol:
<ul class="products">
<? foreach($products as $pK => $pV):?>
<? if($pK % 11 == 10):?></ul><ul class="products"><? endif;?>
<li>
<?= $pV->name;?>
</li>
<? endforeach;?>
</ul>

Looping Through Set Number of Posts in Wordpress, Then running same loop again on next set, etc

I have looked and looked and tried to find an answer for what I've been looking for, but I have yet to see an answer for this:
I am trying to generate a Wordpress loop that takes all the posts from a single category and displays them three at a time inside <li></li> tags.
Output should look like this:
<li>My post title | Another Title | Third title</li>
<li>The next post title | A different post | Post #6</li>
<li>And so on | And so forth</li>
I need this to loop through all the entries in the category until finished, and then exit the loop.
My code is completely non-working at this point, but I've provided what I'm working with below. If anyone has any solution to this, I'd love to give mad props to you, as this has hounded me for three days without any solution so far.
<?php // Loop through posts three at a time
$recoffsetinit = '0';
$recoffset = '3';
query_posts('cat=1&showposts=0');
$post = get_posts('category=1&numberposts=3&offset='.$recoffsetinit.');
while (have_posts()) : the_post();
?>
<li>
<?php
$postslist = get_posts('cat=1&order=ASC&orderby=title');
foreach ($postslist as $post) : setup_postdata($post);
static $count = 0; if ($count == "3") { break; } else { ?>
<?php $count++; } ?>
<?php endforeach; ?>
<?php $recoffsetinit = $recoffset + $recoffsetinit; ?>
</li>
<?php endwhile; ?>
I hacked up your solution to make it work. It took a little doing, since my code-fu is not what you'd call "good." Here's the solution:
<ul>
<?php
query_posts('category=1&showposts=0');
$posts = get_posts('category_name=my_cat&order=ASC&orderby=title&numberposts=0');
$postsPerLine = 3;
$currentPostNumber = 0;
foreach ($posts as $post) :
if ($currentPostNumber == 0) {
echo '<li>';
}
?>
<?php
$currentPostNumber++;
if ($currentPostNumber >= $postsPerLine) {
$currentPostNumber = 0;
echo '</li>';
}
endforeach;
?>
</ul>
Thanks for the input!
No wordpress to test with, and no time, but something like this might be a better way of going about it?
<?php
$postList = get_posts('cat=1&order=ASC&orderby=title');
$postsPerLine = 3;
echo "<ul>";
echo buildPosts($postList, $postsPerLine);
echo "</ul>";
function buildPosts($list, $perLine) {
$out = '';
$currentPostNumber = 0;
foreach ($list as $post) {
if ($currentPostNumber == 0) {
$out .= '<li>';
}
$out .= "<a href='" . the_permalink() . "'></a> ";
$currentPostNumber++;
if ($currentPostNumber <= $perLine) {
$currentPostNumber = 0;
$out .= '</li>';
}
}
return $out;
}
?>
Just snag all the posts for a category, at once, then iterate over it. Create a link to every post, toss in the separator, and on every third post start a new <li>
<ul>
<?php
global $post;
$postsPerLine = 3;
$counter = 0;
$myposts = get_posts('category=1&orderby=title&order=ASC');
foreach($myposts as $post) :
echo (++$counter % postsPerLine) ? : '<li>';
?>
<?php the_title(); ?></li>
<?php
echo ($counter % postsPerLine) ? ' | ' : '</li>';
endforeach;
?>
</ul>

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