I have a list of names and some buttons with product names. When one of the buttons is clicked the information of the list is sent to a PHP script, but I can't hit the submit button to send its value. How is it done?
I boiled my code down to the following:
The sending page:
<html>
<form action="buy.php" method="post">
<select name="name">
<option>John</option>
<option>Henry</option>
<select>
<input id='submit' type='submit' name='Tea' value='Tea'>
<input id='submit' type='submit' name='Coffee' value='Coffee'>
</form>
</html>
The receiving page: buy.php
<?php
$name = $_POST['name'];
$purchase = $_POST['submit'];
//here some SQL database magic happens
?>
Everything except sending the submit button value works flawlessly.
The button names are not submit, so the php $_POST['submit'] value is not set. As in isset($_POST['submit']) evaluates to false.
<html>
<form action="" method="post">
<input type="hidden" name="action" value="submit" />
<select name="name">
<option>John</option>
<option>Henry</option>
<select>
<!--
make sure all html elements that have an ID are unique and name the buttons submit
-->
<input id="tea-submit" type="submit" name="submit" value="Tea">
<input id="coffee-submit" type="submit" name="submit" value="Coffee">
</form>
</html>
<?php
if (isset($_POST['action'])) {
echo '<br />The ' . $_POST['submit'] . ' submit button was pressed<br />';
}
?>
Use this instead:
<input id='tea-submit' type='submit' name = 'submit' value = 'Tea'>
<input id='coffee-submit' type='submit' name = 'submit' value = 'Coffee'>
The initial post mentioned buttons. You can also replace the input tags with buttons.
<button type="submit" name="product" value="Tea">Tea</button>
<button type="submit" name="product" value="Coffee">Coffee</button>
The name and value attributes are required to submit the value when the form is submitted (the id attribute is not necessary in this case). The attribute type=submit specifies that clicking on this button causes the form to be submitted.
When the server is handling the submitted form, $_POST['product'] will contain the value "Tea" or "Coffee" depending on which button was clicked.
If you want you can also require the user to confirm before submitting the form (useful when you are implementing a delete button for example).
<button type="submit" name="product" value="Tea" onclick="return confirm('Are you sure you want tea?');">Tea</button>
<button type="submit" name="product" value="Coffee" onclick="return confirm('Are you sure you want coffee?');">Coffee</button>
To start, using the same ID twice is not a good idea. ID's should be unique, if you need to style elements you should use a class to apply CSS instead.
At last, you defined the name of your submit button as Tea and Coffee, but in your PHP you are using submit as index. your index should have been $_POST['Tea'] for example. that would require you to check for it being set as it only sends one , you can do that with isset().
Buy anyway , user4035 just beat me to it , his code will "fix" this for you.
Like the others said, you probably missunderstood the idea of a unique id. All I have to add is, that I do not like the idea of using "value" as the identifying property here, as it may change over time (i.e. if you want to provide multiple languages).
<input id='submit_tea' type='submit' name = 'submit_tea' value = 'Tea' />
<input id='submit_coffee' type='submit' name = 'submit_coffee' value = 'Coffee' />
and in your php script
if( array_key_exists( 'submit_tea', $_POST ) )
{
// handle tea
}
if( array_key_exists( 'submit_coffee', $_POST ) )
{
// handle coffee
}
Additionally, you can add something like if( 'POST' == $_SERVER[ 'REQUEST_METHOD' ] ) if you want to check if data was acctually posted.
You can maintain your html as it is but use this php code
<?php
$name = $_POST['name'];
$purchase1 = $_POST['Tea'];
$purchase2 =$_POST['Coffee'];
?>
You could use something like this to give your button a value:
<?php
if (isset($_POST['submit'])) {
$aSubmitVal = array_keys($_POST['submit'])[0];
echo 'The button value is: ' . $aSubmitVal;
}
?>
<form action="/" method="post">
<input id="someId" type="submit" name="submit[SomeValue]" value="Button name">
</form>
This will give you the string "SomeValue" as a result
https://i.imgur.com/28gr7Uy.gif
Related
I created a form which asks for username and password for registration purposes and I sent the data to same page using action="" and checking for $_POST variables, but data is not being passed through this method. When I print $POST array by changing condition to true and reloading the page , the POST array is empty and also I can see the variables passed as POST in URL.Can somebody explain whats the problem?
Code:
<!DOCTYPE html>
<html>
<?php
if(isset($_POST['user']))
{
echo "Data coming";
die();
}
else {
?>
<form method="POST" enctype="multiform/form-data" action="">
<b> Username: </b><input type='text' name='user'> <br> <br><br>
<b> Password:</b> <input type='password' name='pass'><br> <br>
<input type='submit' value="Submit">
</form>
<?php
}
?>
</html>
You have to give the name to submit button also.
<input type='submit' name="Submit" value="Submit">
You are checking the index 'Submit' in $_POST and the submitted form is take the value with the name of input type. So you have to given the name to submit button also like above.
You are checking in your if isset for a post named:
$_POST['Submit']
Your submit button doesn't have
name=Submit
As a test to see what you are sending for debug purposes, try putting this in your code, it will help you self-debug:
print_r($_REQUEST);
"input type='submit' name="Submit" ...
Change to this.
$_POST['Submit']
looks for a resource with the name of Submit when you reload the page, as in your code there is no resource with the name of Submit, the if statement returns false and the control switches back to the else part.
Give a name to the submit button and use the same name in the post varibale option.
I want to create a checkbox and check whether checkbox is checked or not in another PHP page so I created form like :
<form action="heartbeat.php" method="post">
<input type="checkbox" name="keepme">
<input type="submit" value="log in">
</form>
and then I tried to extract this input on heartbeat.php like:
<?php
/*
* A PHP file for laying down a heartbeat JavaScript call.
*/
if(!isset($_POST["keepme"])){
$auto_logout = 10;
}
else{
$auto_logout = 1000;
}
?>
but it never gets $_POST["keepme"] value. Any idea??
If you don't pass value to checkbox tag, the POST array will be empty. You need to do something like that
<input type="checkbox" name="keepme" value='1'>
Make Sure you have submit button
If(isset($_POST['submit-btn'])){
echo $_POST['keepme'];
}
This is my second code but the problem is I have 3 queries. So it only returns the last product_id when i Click update it always return product_id=3, but i want update the product_id=2
<form action="update_qty.php" method="POST">
<?php while($getorder = mysqli_fetch_array($order)){ ?>
<input type="hidden" value="<?=$getorder['price']?>" name="actual_price">
<input type="hidden" value="<?=$getorder['product_id']?>" name="product">
<input type="text" value="<?=$getorder['qty']?>" name="qty" size="1" style="text-align:center">
<input type="submit" value="update" name="update">
<?php } ?>
</form>
Your problem is that the PHP is server side and you need something client side to read the value of the text box. You would need a page refresh to pass the text field value to the server so it could write it to the url in the anchor tag. Which is what the form submit would do, but as it would have submitted the value already the anchor tag would be pointless
To do it without a page refresh use Javascript. It would be easy to do with jQuery. You could add an event that writes whatever is entered in the text box the the anchor tags href as it is typed.
I'll do something more like this.
One form per product.In your case when you submit the form the qty value will always be the las found.
<?php while($getorder = mysqli_fetch_array($order)){ ?>
<form action="update_qty.php" method="POST">
<input type="hidden" value="<?=$getorder['price']?>" name="actual_price">
<input type="hidden" value="<?=$getorder['product_id']?>" name="product">
<input type="text" value="<?=$getorder['qty']?>" name="qty" size="1" style="text-align:center">
<input type="submit" value="update" name="update">
</form>
<?php } ?>
You can add more information like this
update
You can not get all values as like that because input name overwrite in every loop iteration.
For multiple values you can try in two ways like:
<?php
while($getorder = mysqli_fetch_array($order)){
$newArr[] = $getorder['price']."~".$getorder['product_id']."~". $ getorder['qty'];
} //while end
?>
<input type="hidden" name="allinputs" value="<?=$newArr?>">
Input field outside the loop.
In php explode array value with ~ and get the all values.
Other solution is that
Your input field name must be change like:
<?php while($getorder = mysqli_fetch_array($order)){ ?>
<input type="hidden" value="<?=$getorder['price']?>" name="actual_price_<?=$getorder['product_id']?>">
<?php } ?>
Change field name in every iteration.
In current scenario either you need three different buttons or the best solution to use AJAX request .
update
On update_qty.php u can use like this
<?php echo $_GET['product_id'];?>
When I create i form - I do something like this:
<form name="form-name" method="post" action="?<?=$_SERVER['QUERY_STRING']?>">
[...some elements...]
<input type="submit" name="form-name" value="button">
</form>
Now I need to get the value of the name="" of the submit button, and not the actual value="".
In this case : "form-name".
And here's why:
When I submit a form; I write the action to database - and therefor need the name of the form submitted.
I know I can just have a hidden field with the form name. But I would like to make it simpler by just extracting the name from the submit button because I have a couple of other hidden form elements that I need to add on every single form I create to make my template system work.
And no javascript...
So, let's say your HTML form is this:
<form name="form-name" method="post" action="">
<input type="submit" name="form-name" value="button">
</form>
And you want to get what is inside name="form-name" in this case the form-name
Well, then in the PHP side you can, treat the $_POST global as associative array, and extract the key from it like this:
<?php
if(isset($_POST)){
foreach($_POST as $key=>$each){
echo $key; // this will output "form-name"
}
}
I might have come up with a solution to my question...
Here's a example form:
<form name="vehicle-vinNr" method="post" action="?<?=$_SERVER['QUERY_STRING']?>">
<input type="hidden" name="hello" value="world" readonly>
<input type="text" name="element">
<input type="submit" name="vehicle-vinNr" value="send">
</form>
First I need to extract and place the element-names into a new array:
<?php
if ($_POST){
foreach($_POST as $_FORM_ELEMENT_name => $_FORM_ELEMENT_value){
$_FORM_ELEMENT_names[] = $_FORM_ELEMENT_name;
}
}
?>
In this case the array now contains:
hello
element
vehicle-vinNr
If the submit-button is, and always is, the last element in the form - this would work:
$_FORM_name = end($_FORM_ELEMENT_names); // vehicle-vinNr
But sometimes the submit-button is not the last element, so I needed to make a change:
If I always start the name of the submit-button with submit_ - e.g. submit__vehicle-vinNr or with multiple submit buttons for different actions like submit_update__vehicle-vinNr/submit_delete_vehicle-vinNr I can just do this:
if ($_POST){
foreach($_POST as $_FORM_ELEMENT_name => $_FORM_ELEMENT_value){
if(strstr($_FORM_ELEMENT_name,'submit_')){
$_FORM_ELEMENT_submit_name = explode('__',$_FORM_ELEMENT_name);
$_FORM_name = $_FORM_ELEMENT_submit_name[1]; // vehicle-vinNr
}
}
}
This is the solution I came up with - any thoughts?
I have two submit buttons in a form which has different values, one to voteup a post and another to votedown a post, how do i submit the value of the input type="submit" buttons?
Without using javascript, i'm making my script flexible to browsers with javascript disabled.
<?php
if (isset($_POST)) {
var_dump($_POST);
}
echo '
<form action="" method="post">
<input type="submit" name="vote_up" value="up">
<input type="submit" name="vote_down" value="down">
</form>';
?>
The value of the clicked button will always be submitted with the form. This is how you can disambiguate between different submit buttons on the same form.
Further clarification can be found at: http://www.javascript-coder.com/html-form/html-form-submit.phtml
Just include it into the form you are submitting and do something like this for disambiguate the buttons:
<input class="submitButton" type="submit" name="up" id="up">
Then in your code you can do something like:
if (isset($_POST["up"])){
// do something
}
you can also use
print_r($_POST);
in place of
var_dump($_POST);