Following db structure:
Table cms_pages containing pages with id, name, title, etc.
Table cms_pagerows containing rows with a cms_page_id and rank
(Unique index over cms_page_id, rank)
The Pagerows are supposed to contain cols which in turn contain the... content.
I now want to insert a new pagerow into cms_pagerows on an existing page using php.
Ranks are not necessarily consecutive numbers because of the deletion of old pagerows.
For this, I have a function insertRowAt($page_name, $offset) with the following SQL:
INSERT INTO `cms_pagerows` (`cms_page_id`, `rank`)
SELECT `cms_pages`.`id`, `cms_pagerows`.`rank` + 1
FROM `cms_pages`, `cms_pagerows`
WHERE `cms_pages`.`name` = "'.$page_name.'"
AND `cms_pagerows`.`cms_page_id` = `cms_pages`.`id`
ORDER BY `rank` DESC
LIMIT 0, "'.$offset.'"
ON DUPLICATE KEY UPDATE `cms_pagerows`.`rank` = `cms_pagerows`.`rank` + 1
When trying to run it, I get the following error message: "Column 'cms_pagerows.rank' in field list is ambiguous"
The key is to always use table aliases to disambiguate the columns:
INSERT INTO `cms_pagerows`(`cms_page_id`, `rank`)
SELECT p.`id`, pr.`rank` + 1
FROM `cms_pages` p join
`cms_pagerows` pr
on pr.`cms_page_id` = p.`id`
WHERE p.`name` = "'.$page_name.'"
ORDER BY pr.`rank` DESC
LIMIT 0, "'.$offset.'"
ON DUPLICATE KEY UPDATE `rank` = pr.`rank` + 1;
You can also say:
ON DUPLICATE KEY UPDATE `rank` = VALUES(`rank`)
This works because the select is already going to insert the correct rank, so you can just use that value.
try this..
INSERT INTO `cms_pagerows` (`cms_page_id`, `rank`)
SELECT `cms_pages`.`id`, `cms_pagerows`.`rank` + 1 AS rank1
FROM `cms_pages`, `cms_pagerows`
WHERE `cms_pages`.`name` = "'.$page_name.'"
AND `cms_pagerows`.`cms_page_id` = `cms_pages`.`id`
ORDER BY rank1 DESC
LIMIT 0, "'.$offset.'"
ON DUPLICATE KEY UPDATE `rank` = rank1 + 1
two rank fields are conflicting because you are using same name... use AS keyword of mysql..
Related
Hey guys i have a table structure like
CREATE TABLE CUSTOMERS(
ID INT NOT NULL,
NAME VARCHAR (20) NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR (25) ,
SALARY DECIMAL (18, 2),
PRIMARY KEY (ID)
)
INSERT INTO CUSTOMERS (ID,NAME,AGE,ADDRESS,SALARY)
VALUES (1,'aff',2,3,5)
VALUES (2,'afff',1,31,52)
update CUSTOMERS
set NAME = 'somenewname'
where age = 1;
I just want to get output as 'somename'
I have tried creating a column updatedtime with timestamp and used query like
SELECT * FROM CUSTOMERS ORDER BY updatetime DESC LIMIT 1;
But this one shows the whole values ..
I just need only the updated value 'somenewname` as output.
I have also tried using triggers and functions but it didnt helped..
Please help me with a solution..I will accept it as an answer if it helps me ..remember i want an output as a single value like somenewname.
Thanx
The trigger which i have used
CREATE TRIGGER getrandom
AFTER UPDATE ON CUSTOMERS
FOR EACH ROW
BEGIN
UPDATE CUSTOMERS
SET NAME = 'anewname'
WHERE ADDRESS = 3;
END;
Why don't you try to SELECT only the name-column
SELECT name FROM CUSTOMERS ORDER BY updatetime DESC LIMIT 1; //outputs the name
instead of the whole result
SELECT * FROM CUSTOMERS ORDER BY updatetime DESC LIMIT 1;
Your UPDATE statement should look like
update CUSTOMERS
set NAME = 'somenewname',
updatetime = now()
where age = 1;
Now a example of how to get only the name if tables are joined.
SELECT c.name FROM CUSTOMERS as c INNER JOIN orders as o c.id=o.id ORDER BY c.updatetime DESC LIMIT 1;
I have a table with named "user-recent-activity" which has following columns: id, userid, activity and datetime. Now, I want to delete the records if any unique userid has more than 50 items, deleting the oldest records. For example, if the user id(lets say 1234) has more than 50 records in this table, then I have to save latest 50 records of user id(1234) and delete the oldest one.
Before inserting, query for the last 50 records with that ID (ordering from newer to older). If there is a 50th, substitute it (via update) instead of inserting a new row.
Assuming you are using a RDBMS that supports standard SQL the following stored procedure should do it.
create procedure remove-old-activities
(
#userid int
)
as
delete from user-recent-activity where userid=#userid and id not in (select top 50 id from user-recent-activity where userid=#userid order by datetime desc)
If you're DB does not support stored procedures then you should be able to use SQL parameters to pass the userid value...
Hope that helps
You could use rank method to precisely defined the rows number and thus delete the rows you want.
delete from tblName where id=
(select id from (
select #i := CASE WHEN ( #userid <> userid ) THEN 1
ELSE #i+1
END AS rank , id,userid, datetime2 ,#userid:=userid AS clset
from tblName x,(SELECT #i:=0) a ,(SELECT #userid:= 0) s
order by x.userid, datetime2 desc) T
where T.rank='50') ;
Another option:
Use the select query to select the rank <=50 and insert into a new table. Delete the old table and rename the new table afterwards.
insert into newtable (userid,activity,datetime2)
select userid,datetime2 from (
select #i := CASE WHEN ( #userid <> userid ) THEN 1
ELSE
#i+1
END AS rank , userid, activity,datetime2 ,#userid:=userid AS clset
from tblName x,(SELECT #i:=0) a ,(SELECT #userid:= 0) s
order by x.userid, datetime2 desc) T
where t.rank <=50
so I'm trying to create a ranking system for my website, however as a lot of the records have same number of points, they all have same rank, is there a way to avoid this?
currently have
$conn = $db->query("SELECT COUNT( * ) +1 AS 'position' FROM tv WHERE points > ( SELECT points FROM tv WHERE id ={$data['id']} )");
$d = $db->fetch_array($conn);
echo $d['position'];
And DB structure
`id` int(11) NOT NULL,
`name` varchar(150) NOT NULL,
`points` int(11) NOT NULL,
Edited below,
What I'm doing right now is getting records by lets say
SELECT * FROM tv WHERE type = 1
Now I run a while loop, and I need to make myself a function that will get the rank, but it would make sure that the ranks aren't duplicate
How would I go about making a ranking system that doesn't have same ranking for two records? lets say if the points count is the same, it would order them by ID and get their position? or something like that? Thank you!
If you are using MS SQL Server 2008R2, you can use the RANK function.
http://msdn.microsoft.com/en-us/library/ms176102.aspx
If you are using MySQL, you can look at one of the below options:
http://thinkdiff.net/mysql/how-to-get-rank-using-mysql-query/
http://www.fromdual.ch/ranking-mysql-results
select #rnk:=#rnk+1 as rnk,id,name,points
from table,(select #rnk:=0) as r order by points desc,id
You want to use ORDER BY. Applying on multiple columns is as simple as comma delimiting them: ORDER BY points, id DESC will sort by points and if the points are the same, it will sort by id.
Here's your SELECT query:
SELECT * FROM tv WHERE points > ( SELECT points FROM tv WHERE id ={$data['id']} ) ORDER BY points, id DESC
Documentation to support this: http://dev.mysql.com/doc/refman/5.0/en/sorting-rows.html
Many Database vendors have added special functions to their products to do this, but you can also do it with straight SQL:
Select *, 1 +
(Select Count(*) From myTable
Where ColName < t.ColName) Rank
From MyTable t
or to avoid giving records with the same value of colName the same rank, (This requires a key)
Select *, 1 +
(Select Count(Distinct KeyCol)
From myTable
Where ColName < t.ColName or
(ColName = t.ColName And KeyCol < t.KeyCol)) Rank
From MyTable t
I have a table that is is sorted 1st by Reminder Date then ID
Table Looks like:
ID | remind_date
1 2011-01-23
2 2010-02-21
4 2011-04-04
5 2011-04-04
6 2009-05-04
I am using a PHP front end to move forward and back thur the records. I want to have forward and back buttons but i am running into a problem with the 2 reminder dates that are the same.
Just to note the ID's are NOT in order, they are here but in the actual database they are mixed up when sorting by reminder_date
The select statement i am using is: ($iid is the current record i am on)
SELECT id FROM myDB.reminders where remind_date > (SELECT remind_date FROM myDB.reminders where id=$iid) order by remind_date ASC LIMIT 1
So what happens when i get to the dates that are the same its skips over one because its asking for remind_date >.
If i use remind_date >= it returns the current record. My solution was then to use limit 2 and check via PHP to if the 1st record = my current ID, if it did use the next one. but what it there are 3 dates the same or 4 etc..
I also thought about using the ID field but since they are out of order i can't add in a ID > $iid.
Any ideas? it works great except for 2 dates that are the same.
You might be able to use this:
SELECT ID, remind_date
FROM
(
SELECT #prev_id := -1
) AS vars
STRAIGHT_JOIN
(
SELECT
ID,
remind_date,
#prev_id AS prev_id,
#prev_id := id
FROM myDB.reminders
ORDER BY remind_date, ID
) T1
WHERE prev_id = $iid
Here is a test of the above with your test data from your comment:
CREATE TABLE Table1 (ID INT NOT NULL, remind_date DATE NOT NULL);
INSERT INTO Table1 (ID, remind_date) VALUES
(45, '2011-01-14'),
(23, '2011-01-22'),
(48, '2011-01-23'),
(25, '2011-01-23'),
(63, '2011-02-19');
SELECT ID, remind_date
FROM
(
SELECT #prev_id := -1
) AS vars
STRAIGHT_JOIN
(
SELECT
ID,
remind_date,
#prev_id AS prev_id,
#prev_id := id
FROM table1
ORDER BY remind_date, ID
) T1
WHERE prev_id = 25
Result:
ID remind_date
48 2011-01-23
add a condition WHERE ID<>MY_LAST_ID. This can not work with triple and more same dates, so you can collect already taken ID's to array like (4,5,6) - see array_push(), implode it with "," to convert to a string (let's call it YOUR_IDS_STRING) and add to your query:
WHERE id NOT IN( YOUR_IDS_STRING )
And after each query make check, does date has changed and if it does - you can unset your array and start from begining (this is not neccesary, but gives you more performance, because YOUR_ID_STRING will be only that long as is need).
If your page is refreshing between queries, maybe try to push YOUR_ID_STRING in session variable, _GET or cookies, and simply concat next id's by operator .=
I used the code provided by Mark Byers and with small changes I adapted it to navigate in opposite directions (and to pass other columns too, not only the date and ID):
$results = $mysqli->query("SELECT * FROM (SELECT #prev_id := -1) AS vars STRAIGHT_JOIN (SELECT *, #prev_id AS prev_id, #prev_id := ID FROM my_table ORDER BY data, ID) T1 WHERE prev_id = ".$ID);
$results = $mysqli->query("SELECT * FROM (SELECT #next_id := 1) AS vars STRAIGHT_JOIN (SELECT *, #next_id AS next_id, #next_id := ID FROM my_table ORDER BY data DESC, ID DESC) T1 WHERE next_id = ".$ID);
I tested it on duplicate dates and it navigates well trough a list of records displayed with:
$results = $mysqli->query("SELECT * FROM my_table ORDER BY data DESC, ID DESC");
I have a table with 4 columns: place_id, username, counter, last_checkin
I'm writing a check-in based system and I'm trying to get a query that will give me the "mayor" of each place. The mayor is the one with most check-ins, and if there is more than 1 than the minimum last_checkin wins.
For example, if I have:
place_id, username, counter, last_checkin
123, tom, 3 , 13/4/10
123, jill, 3, 14/4/10
365, bob, 2, 15/4/10
365, alice, 1, 13/4/10
I want the result to be:
123, tom
365, bob
I'm using it in PHP code
Here is the test data:
CREATE TABLE `my_table` ( `place_id` int(11), `username` varchar(50), `counter` int(11), `last_checkin` date);
INSERT INTO `my_table` VALUES (123,'tom',3,'2010-04-13'),(123,'jill',3,'2010-04-14'),(365,'bob',2,'2010-04-15'),(365,'alice',1,'2010-04-13');
How about..
SELECT
place_id,
(SELECT username
FROM my_table MT2
WHERE MT2.place_id = MT1.place_id
ORDER BY counter DESC, last_checkin ASC
LIMIT 1) AS mayor
FROM my_table MT1
GROUP BY place_id;
Edited as Unreason suggests to have ascending order for last_checkin.
Brian's correlated query is something I would write. However I found this different take and it might perform differently depending on the data
SELECT
mt1.place_id,
mt1.username
FROM
my_table mt1 LEFT JOIN my_table mt2
ON mt1.place_id = mt2.place_id AND
(mt1.counter < mt2.counter OR
(mt1.counter = mt2.counter AND mt1.last_checkin > mt2.last_checkin)
)
WHERE
mt2.place_id IS NULL
Which uses left join to get to the top records according to certain conditions.
$data = query("SELECT max(counter) counter,username FROM table GROUP By place_id ORDER By last_checkin DESC");