I've a table containing more than 27,000 records. I want to fetch all data in Dropdown list. For that I've implemented cache but it seems to be not working as its getting very slow and showing blank page (Sometime browser is getting hanged).
Following is my code (I am using yiiboilerplate):
Configuration of backend/config/main.php in component array:
'cache' => array(
//'class' => 'system.caching.CMemCache',
'class' => 'system.caching.CDbCache',
'connectionID' => 'db',
),
In View page:
$dependency = new CDbCacheDependency('SELECT MAX(bank_id) FROM bank');
$bank = CHtml::listData(Bank::model()->cache(1000, $dependency)->findAll('is_active=1', array('order' => 'name')), 'bank_id', 'concatened');
echo $form->dropDownListRow($model, 'bank_id', $bank, array(
'empty' => 'Select'
));
I think 27000 records is not big data but still its getting very slow and I want to implement cache in my entire application.
Is my configuration correct? Where I am going wrong?
Thanks
I think your parameters in findAll is incorrect.
It should be:
Bank::model()
->cache(1000, $dependency)
->findAll([
'select' => 'bank_id',
'order' => 'name ASC', // if it is in ascending order
'condition' => 'is_active = 1'
]);
I don't know what concatened so I just ignored it. But you can always use scopes for your conditions.
Related
I'm developing a prestashop module and I'm trying to show a category tree in my backoffice configuration page.
I'm trying to follow this instructions below but I don't know exactly where to add this code.
It should be inside main module's php? or inside a separate .php file and call it from the main one (don't know how to do it either).
As much time I'm spending trying to figure out, how to implement the code in the link above, the more I think I'm losing my time.
I see that "use" files, and this JS, " /admin-dev/themes/new-theme/js/components/form/choice-tree.js " are not in any prestashop folders.
Well, you should invest some time and learn Symfony since this is what you need to build backend modules for Prestashop 1.7.
As a pointer, you need to create a form class extending the CommonAbstractType, add a build form method. e.g. :
public function buildForm(FormBuilderInterface $builder, array $options)
{
$this->context = Context::getContext();
$parents = [
['id_category' => 2, 'name' => 'Home', 'children' => $this->getSubCategories(1, true, 2)]
];
$builder->add('category', CategoryChoiceTreeType::class, [
'choices_tree' => $parents,
'choice_value' => 'id_category',
'choice_children' => 'children',
'choice_label' => 'name',
'disabled_values' => $disabledCategories,
'label' => 'Choose a category'
])
then add methods for retrieving the data to populate the form fields.
Then use this class in your controller and display the form:
$form = $this->createForm(YourFormForm::class);
Also add a processForm to process data.
As mentioned, this is not a copy/paste situation you need to understand the Symfony workflow.
The only way that I found to "paint" the categorytree in my configuration page is adding this code to the inputs form array:
Can anyone tell me how to retrieve users selection data to my database?
It does not work as any other form field.
array(
'type' => 'categories',
'label' => $this->l('Destination Category'),
'desc' => $this->l('Select ONE Category'),
'name' => 'CATEGORY_CATEGORY_TO',
'tree' => [
// 'selected_categories' => [],
'disabled_categories' => null,
'use_search' => false,
'use_checkbox' => false,
'id' => 'id_category_tree',
],
'required' => true
),
Well, it is SOLVED!!!! Finally it was very simple, but you must get the correct info for you particular case.
#Robertino's answer might be the best implementation, I don't know, but it became impossible to solve for me,
I uses this code below, and called $categoryTree from the form input. This input must be type=> categories_select
Thanks for your time, and for the help of another post from this forum.
$root = Category::getRootCategory();
//Generating the tree
$tree = new HelperTreeCategories('categories_1'); //The string in param is the ID used by the generated tree
$tree->setUseCheckBox(false)
->setAttribute('is_category_filter', $root->id)
->setRootCategory($root->id)
->setSelectedCategories(array((int)Configuration::get('CATEGORY_1'))) //if you wanted to be pre-carged
->setInputName('CATEGORY_1'); //Set the name of input. The option "name" of $fields_form doesn't seem to work with "categories_select" type
$categoryTree = $tree->render();
And the Form:
array(
'type' => 'categories_select',
'label' => $this->l('Category'),
'desc' => $this->l('Select Category '),
'name' => 'CATEGORY_1', //No ho podem treure si no, no passa la variable al configuration
'category_tree' => $categoryTree, //This is the category_tree called in form.tpl
'required' => true
Hellow , I want to use group by within contain in cakephp. In the following case i want to take only distinct organization within organizationUser array..
$options = array(
'conditions' => array('User.' .$this->User->primaryKey => $userId),
'contain' => array(
'OrganizationUser'=>array(
'conditions'=>['status'=>3],
'group'=> array( 'OrganizationUser.organization_id')),
'OrganizationUser.Organization',
'OrganizationUser.Organization.Noticeboard',
'OrganizationUser.Organization.Newsboard',
'OrganizationUser.Organization.Noticeboard.Branch',
),
'page'=>$page,
'limit'=>$limit
);
$org = $this->User->find('all', $options);
But this is throwing error like 'Column not found', and 'conditions' is working fine within OrganizationUser but 'group' not working.I am using cakephp version 2.Thanks in advance.
I don't think cakephp 2+ offer something like you are doing to make field distinct within contain. So better to try following..
Replace :
'group'=> array( 'OrganizationUser.organization_id')
By
'fields'=> array( 'DISTINCT OrganizationUser.organization_id')
that might work for you.
In my case, I'm using cake version 4+.
In my table the relation I've made
$this->belongsTo('CreatedOperator')
->setClassName(USERS_PLUGIN . '.Users')
->setForeignKey('created_by')
->setJoinType('INNER')
;
and I'm calling the relation like
$query
->disableHydration()
->select([
'CreatedOperator.id',
'CreatedOperator.first_name',
'CreatedOperator.last_name',
'full_name' => $query->func()->concat(['CreatedOperator.first_name' => 'identifier',' ','CreatedOperator.last_name' => 'identifier']),
'total' => $query->func()->count('CreatedOperator.id')])
->contain(['CreatedOperator'])
->group(['CreatedOperator.id'])
;
return $query->toList();
I had asked a question here a while back about setting up database populated dropdowns for SugarCRM. I received a really good answer and, after more php studies and a dev instance running, I decided to give it a shot. The instructions I followed can be found here. After I run the repair and rebuild, I would expect to see the custom field in my Fields list under the module in studio, but have not been able to find it. The module is named Makers (a1_makers as a database table). For good orders sake, there were no errors when I repaired/rebuilt after saving the files. Per the instructions, I first created a php file with a custom function to query the database (custom/Extension/application/Ext/Utils/getMakers.php):
<?php
function getMakers() {
static $makers = null;
if (!$makers){
global $db;
$query = "SELECT id, name FROM a1_maker";
$result = $db->query($query, false);
$accounts = array();
$accounts[''] = '';
while (($row = $db->fetchByAssoc($result)) !=null) {
$accounts[$row['id']] = $row['name'];
}
}
return $makers;
}
?>
Then, I set 'function' field in Vardefs to point to the function (custom/Extension/modules/Maker/Ext/Vardefs/makers_template.php):
<?php
$dictionary['Maker']['fields']['list_of_makers'] = array (
'name' => 'list_of_makers',
'vname' => 'LBL_MKRLST'
'function' => 'getMakers',
'type' => 'enum',
'len' => '100',
'comment' => 'List of makers populated from the database',
);
?>
Unfortunately, there are no errors and the repair/rebuild runs fine. I am just unable to see the custom field when I go into studio. Can anyone please help point out what I may be doing wrong?
I would recommend checking existence of newly created field 'list_of_makers' in cache/modules/Maker/Makervardefs.php file. If new field definition exists in that file, try add 'studio' => 'visible' to custom/Extension/modules/Maker/Ext/Vardefs/makers_template.php to get something like this:
<?php
$dictionary['Maker']['fields']['list_of_makers'] = array (
'name' => 'list_of_makers',
'vname' => 'LBL_MKRLST'
'function' => 'getMakers',
'type' => 'enum',
'studio' => 'visible'
'len' => '100',
'comment' => 'List of makers populated from the database',
);
Try to edit your custom/modules/Maker/metadata/editviewdefs.php manually and insert field definition by hand in proper place if everything above won't work.
$dictionary['Maker']['fields']['list_of_makers'] = array (
'name' => 'list_of_makers',
'vname' => 'LBL_MKRLST'
'function' => 'getMakers',
'type' => 'enum',
'studio' => 'visible'
'len' => '100',
'comment' => 'List of makers populated from the database',
'studio' => array(
'listview' => true,
'detailview' => true,
'editview' => true
),
);
I have a table that's been created by a module. I need to include some of its fields into an existing view.
I tried using the table wizard module, but all it does is create a separate view for that table. I'd like to be able to choose fields from that table to be added into an existing view as additional fields, or through relationships or something like that. Is there a workaround to do what I'm trying to do?
Ah. Views. Took me a while as well. This answer is for Drupal 6 and in the abstract shows how to define fields as well as using a relationship to allow the fields to link to the node table.
Inside modulename.module, you want a function that goes:
function modulename_views_api() {
return array(
'api' => 2,
);
}
Then you want to make a file called modulename.views.inc and define a function like this:
function modulename_views_data() {
$data['modulename_table'] = array(
'table' => array(
'group' => 'ModuleName',
'title' => 'Module name title',
),
'join' => array(
// to join to node, we'll use a field in modulename_table called 'nid'
'node' => array(
'left_field' => 'nid',
'field' => 'nid',
),
),
);
// now we define the fields in the table like this
// check out modules/views/handlers to see more specific handlers
$data['modulename_table']['fieldname'] = array(
'title' => 'fieldname',
'help' => 'fieldname description',
'field' => array(
'handler' => 'views_handler_field',
),
);
$data['modulename_table']['nid'] = array(
'title' => 'related node',
'help' => 'the field that relates back to {node}',
// here we implement a relationship to nid
'relationship' => array(
'base' => 'node',
'field' => 'nid',
'handler' => 'views_handler_relationship',
'label' => 'modulename row node',
),
// this relationship can be turned on in views
);
return $data;
}
You can use hook_views_data to define your table in code. As long as you don't want views to do special manipulations, it's almost as simple as defining the table with the schema API.
Your other option is to use table wizard to expose the tables to the database and then use the migrate module to create the views. http://drupal.org/project/migrate
I have found that the Views Custom Field module lets me do just about anything I need as far as adding oddball fields to views .. maybe it'd help ..
I am stuck on pagination in CakePHP 1.3. I am trying to paginate feePayment records based on certain criteria.
feePayments belongs to Students which in turn belongs YearGroups.
I want to paginate 'unpaid' feePayments for each year group. The problem I am having is that the SQL query seems to only take into account the conditions I specified for the FeePayment model and ignores the YearGroup criteria so only overdue unpaid records are returned regardless of the year group specified.
Here is my code:
function unpaidClass($id) {
$this->paginate = array(
'FeePayment' => array ('recursive' => 1, 'conditions' => array('FeePayment.status' => 'Unpaid', 'FeePayment.due_date <= ' => date("Y-m-d"))),
'YearGroup' => array ('recursive' => 1, 'conditions' => array('YearGroup.school_year' => $id))
);
$this->set('feePayments', $this->paginate());
}
Hope this makes sense, appreciate any help.
Thanks,
Sid.
You should consider using the Containable behavior. This behavior allows you to group the necessary data you want without relaying on the "recursiveness" of your query. You can place conditions on your contained data similar to the way you would in your queries and is a more permanent way to structure data across your application instead of specifying conditions over and over again in each query.
Paginate should automatically pick up these associations when you Paginate your main model. Here's an example of what I mean here: http://cakephp.1045679.n5.nabble.com/Paginate-with-Containable-td1300971.html#a1300971
These should make your task easier.
After a lot of searching the net and reading CakePHP's documentation, here is the solution I came up with:
function unpaidClass($id) {
$this->FeePayment->unbindModel(array(
'belongsTo' => array('Student')
), $reset = 0);
$this->FeePayment->bindModel(array(
'belongsTo' => array(
'Student' => array(
'foreignKey' => false,
'conditions' => array('Student.id = FeePayment.student_id')
),
'YearGroup' => array(
'foreignKey' => false,
'conditions' => array('YearGroup.id = Student.year_group_id')
)
)
), $reset = 0);
$this->paginate = array(
'contain' => array('Student','YearGroup'),
'conditions' => array('YearGroup.school_year' => $id,
'FeePayment.status' => 'Unpaid',
'FeePayment.due_date <= ' => date("Y-m-d")));
$this->set('feePayments', $this->paginate());
}