PHP - count array based other array (array('a','d')=array('d','a')) - php

Question

I have array like this:
$array1 = array(Array('a','d'),
Array('c','a'),
Array('d','a'),
Array('a','b','c','d','e'),
);
$array2 = array(array('a','d'), array('a','b','c','d','e')) ;
$result = array();
Here's my code:
foreach ($array2 as $part) {
$key = implode(', ', $part);
if( ! array_key_exists ($key, $array1)) {
$result[$key] = 0;
}
$result[$key] = $result[$key] + 1;
}
foreach ($result as $key => $value) {
echo "$value of {$key}<br/>";
}
I want to count values $array2 based on $array1
I got this one:
1 of a,d
1 of a,b,c,d,e
But I want a result like this:
3 of a,d
1 of a,b,c,d,e
If anybody wonders why there's (3 of a,d), it count from array('a','d'), array('d','a') also counted as array('a','d') and array('a','b','c','d','e')

Answer 1

Try this. Here is a working demo https://eval.in/117810
<?
$array1 = array(array('a','d'),
array('c','a'),
array('d','a'),
array('a','b','c','d','e'),
);
$array2 = array(array('a','d'), array('a','b','c','d','e')) ;
$result = array();
foreach ($array2 as $key=>$part2) {
sort($part2);
if(!isset($result[$key]))$result[$key]=0;
foreach($array1 as $part1) {
$intersect = array_intersect($part1, $part2);
sort($intersect);
if ($intersect === $part2) {
$result[$key]++;
}
}
}
foreach($result as $k=>$v) {
echo $v . " of " . implode(',', $array2[$k]) . "<br/>";
}
?>