how explode country code from number php - php

Question

how explode country code from number php, i need 1-3 characters from number for country validation. I have array with ( code => country), i have script example, but it works only if i explode 1 character, but country code can be 2 or 3 characters too. i know that i can explode by $number = explode(" ", 1 777777); , but i need full number without additional symbols or spaces.
$number = "1777777";
$we = substr($number, 0, 2);
$countrys = array(
'1' => 'us',
'2' => 'uk',
'3' => 'de',
'44' => 'fi', // dont work if 2 characters..
'123' => 'no' // dont work if 3 characters..
);
$array = "$we";
echo $country = $countrys[$array[0]];
echo "<br>country";
how i can modificate this code? thank you! or any other suggestions?

Answer 1

I would assume if the number is like 123777777, the country code would be considered as 123 instead of 12 or 1, if both 1, 12 and 123 exist.
In this case, just start by checking the first 3 digits against the countrys array. If none is found, then go on by checking the first 2 digits, and so on.
$number = "123777777";
$countrys = array(
'1' => 'us',
'2' => 'uk',
'3' => 'de',
'44' => 'fi',
'123' => 'no',
);
$i = 3;
$country = "";
while ($i > 0) {
if (isset($countrys[substr($number, 0, $i)])) {
$country = $countrys[substr($number, 0, $i)];
break;
} else {
$i--;
}
}
echo $country;

Answer 2

In your code, you are always assigning the first country in $countrys to your $country. So you will always end up with us.
Instead of doing that, you should get the first 3, 2, or 1 digit(s) from your phone number, and check if the array key exists. If it does, you use that as the lookup index to your array.
Here's a pseudocode for you to get started:
perform a loop to get the first 3, 2, and 1 digit(s) from the phone number:
// Order is important as you want to match '123' before you match '1'
Check if the array key for the digit exists in the $countrys
If yes, get the country name and quit the loop
If not, go to the next less digit
If the key is found:
Print the country name
Else:
Print the country is not found
Here is partial code for how you'd do it for the 3 digits. You just need to add a loop (such as for-loop) to simplify your work.
$number = "123777777";
// Add your loop here to check for 3, 2, 1 digit
$we = substr($number, 0, 3);
$countrys = array(
'1' => 'us',
'2' => 'uk',
'3' => 'de',
'44' => 'fi',
'123' => 'no'
);
$array = "$we"; // You don't need this
if (array_key_exists ($we, $countrys))
{
// Remember to break out of your loop when the country is found
$country = $countrys[$we];
}
else
{
$country = "Non in list";
}
// End your loop here
echo "${we} is ${country}\n";

Answer 3

Use krsort to sort the array (longest numbers first). In this case "123" will be checked before "1". Then you can simply iterate over your array and check if the number begins with the country's number. If it matches, save the country code to a variable:
$number = '123777777';
$countrys = array(
'1' => 'us',
'2' => 'uk',
'3' => 'de',
'44' => 'fi',
'123' => 'no'
);
// sort the array by key, descending
krsort($countrys, SORT_NUMERIC);
// iterate over all countries
foreach ($countrys as $we => $ccode) {
// if number begins with current number
if (strpos($number, '' . $we) === 0) {
// store country code and break the loop
$country = $ccode;
break;
}
}
echo 'country: ' . $country; // expected: "no"