Dynamically display the result of a MySQL query into an HTML page - php

Question

I use the YII Framework and I would like to put the results of a MySQL query in a table in index.php.
The MySQL query is already good:
SELECT categories.name,
systemes.name,
systemes.etat_de_base,
maintenances.name,
maintenances.date,
maintenances.duree
FROM systemes_maintenances
LEFT JOIN systemes
ON systemes_maintenances.id_systemes = systemes.id_systemes
LEFT JOIN categories
ON systemes.id_categories = categories.id_categories
LEFT JOIN maintenances
ON systemes_maintenances.id_maintenances = maintenances.id_maintenances;
And my PHP page looks like this at the moment:
<?php
/* #var $this SiteController */
$this->pageTitle=Yii::app()->name;
?>
<!--<h1>Welcome to <i><?php echo CHtml::encode(Yii::app()->name); ?></i></h1>
<p>Congratulations! You have successfully created your Yii application.</p>
<p>You may change the content of this page by modifying the following two files:</p>
<ul>
<li>View file: <code><?php echo __FILE__; ?></code></li>
<li>Layout file: <code><?php echo $this->getLayoutFile('main'); ?></code></li>
</ul>
<p>For more details on how to further develop this application, please read
the documentation.
Feel free to ask in the forum,
should you have any questions.</p>-->
<table>
<caption>État des systèmes</caption>
<tr>
<th>Catégorie</th>
<th>Nom</th>
<th>État actuel</th>
<th>Maintenance prévue</th>
<th>Début de l'incident</th>
</tr>
<tr>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
</table>
I want to display the results in the empty <td> </ td>.
Does anyone know how to do it without jQuery?

Answer 1

Since you are using Yii framework you can use CGridView component. This give nice set of features such as sorting, pagination and filtering.
Check following link for example usage.
http://www.yiiplayground.com/index.php?r=UiModule/dataview/gridView

Answer 2

To connect to the database and the connection was defined in the config yii. Must be added to the top of page two line of code.
$sql = 'querySQL';
$connection=Yii::app()->db;
$dataReader=$connection->createCommand($sql)->query();

Answer 3

their is a tutorial How to display data in php from Mysql.
Link: http://hightechnology.in/how-to-display-data-in-php-from-mysql/
may it will help you.

Answer 4

Try sth like this:
$query = "SELECT categories.name,
systemes.name,
systemes.etat_de_base,
maintenances.name,
maintenances.date,
maintenances.duree
FROM systemes_maintenances
LEFT JOIN systemes
ON systemes_maintenances.id_systemes = systemes.id_systemes
LEFT JOIN categories
ON systemes.id_categories = categories.id_categories
LEFT JOIN maintenances
ON systemes_maintenances.id_maintenances = maintenances.id_maintenances";
$count= Yii::app()->db->createCommand($query)->queryScalar();
$dataProvider = new CSqlDataProvider($query, array(
'totalItemCount'=>(int) $count,
'keyField' => 'SOME_UNIQUE_ID_FROM_THE_SQL',
'pagination'=>array( 'pageSize'=>30, ),
));
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'yourGrid',
'dataProvider'=> $dataProvider,
));
You will have to customize the grid yourself, so that it displays only what you need, but you can find this in the Yii documentation of CGridView

Answer 5

I am not so sure of the YII framework but this should definitely help you out.
Let the result of the mySql query be in a variable $result
now , start with while/for loop like this :
<?php
while ($row=mysqli_fetch_array($result)){
//Do something with the $row variable data
?>
<td>Some Data</td>
<td>echo $row["SomeColoumn1"];</td>
<td>echo $row["SomeColoumn2"];</td>
<td>echo $row["SomeColoumn3"];</td>
<td>echo $row["SomeColoumn4"];</td>
<?php
}
?>
This should print all the rows of the table as required and add the table and th parts before and after accordingly.