I'm trying to create a simple fileupload form in my custom Wordpress template:
<form action="<?php echo $current_url = home_url(add_query_arg(array(),$wp->request)); ?>" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>
On submit, the $_FILES array is empty.
I think the problem is in the action, as the url that is generated is the nice URL, instead of http://domain.com/somepost.php
What should I put into the action, so I get the $_FILES?
Try this
<?php
if(isset($_POST['submit'])){
if($_FILES["file"]["error"] > 0){
echo $_FILES["file"]["error"];
}
else{
echo $_FILES['file']["name"]; // your file name
}
}
?>
<form method="post" action="#" enctype="multipart/form-data">
<input type="file" name="file" />
<input type="submit" name="submit"/>
</form>
Related
<form action='' method='post'>
<input type="file" class="form-control" name="kk">
<input type="submit" class="form-control" name="submit">
</form>
<?php
if(isset($_POST['submit'])){
echo $_FILES["kk"]["name"];
}
?>
hi,i'm new to php,In this code undefined index kk coming on uploading file,i just want the file name...please help me out
add enctype="multipart/form-data" to form tag
You need to pass enctype="multipart/form-data" when you have to upload file
<form action='' method='post' enctype="multipart/form-data">
<input type="file" class="form-control" name="kk">
<input type="submit" class="form-control" name="submit">
</form>
<?php
if(isset($_POST['submit'])){
echo $_FILES["kk"]["name"];
}
?>
I have a form where i want to upload files with multiple inputs.My form looks like:
<form action="" method="post">
<input type="file" name="tax" />
<input type="file" name="ta" />
<input type="submit" name="submit" />
</form>
I do not know how to process this form..
You form doesn't work until you don't include 'enctype="multipart/form-data"', because it is necessary to use input type file.
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="tax" />
<input type="file" name="ta" />
<input type="submit" name="submit" />
</form>
Now browse the file and submit the form. You will get all file data inside $_FILES. so to check what you get inside the file data, you can use :
echo '<pre>';
print_r($_FILES)
I'm not sure whether you have gone through the tutorials before, however below is the code which will help you to process it.
<form action="upload_file.php" method="post" enctype="multipart/form-data">
<input type="file" name="tax" />
<input type="file" name="ta" />
<input type="submit" name="submit" />
</form>
If you upload the file, you can get the files from,
$_FILES global array, i.e. $_FILES['tax'] and $_FILES['ta'].
More info can be found on php.net
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="tax" />
<input type="file" name="ta" />
<input type="submit" name="submit" />
</form>
<?php
//print_r($_POST);
if(isset($_POST['submit'])){
$name = $_FILES['tax']['name'];
$name1 = $_FILES['ta']['name'];
$temp_name = $_FILES['tax']['tmp_name'];
$temp_name1 = $_FILES['ta']['tmp_name'];
var_dump($_FILES);
if(isset($name)){
if(!empty($name)){
var_dump($_FILES);
$location = 'images/'.$name;
if(move_uploaded_file($temp_name, $location)){
echo 'File uploaded successfully';
}
}
} else {
echo 'You should select a file to upload !!';
}
if(isset($name1)){
if(!empty($name1)){
var_dump($_FILES);
$location = 'images/'.$name1;
if(move_uploaded_file($temp_name1, $location)){
echo 'File uploaded successfully';
}
}
} else {
echo 'You should select a file to upload !!';
}
}
?>
Have a look at the following code:
<?php
if (isset($_POST['email']))
{
$expertmail=trim($_POST['email']);
echo $expertmail;
$expertfile=$_FILES['upfile']['tmp_name'];
echo $expertfile;
}
?>
<form action="test.php" method="post" name="users" id="users" >
<input name="upfile" id="upfile" type="file" />
<input name="email" id="email" type="text" />
<input type="submit" name="submit_button" id="submit_button" value="ΑΠΟΣΤΟΛΗ" />
</form>
Why 'echo $expertfile' does not display anything?
Thank you
POST Method Uploads gives all the information you need to handle file uploads in PHP. For your case you need: enctype="multipart/form-data":
<form action="test.php" method="post" name="users" id="users" enctype="multipart/form-data">
As Salman A points out, you will also need to check to see if a file was uploaded.
I have a iframe with a name, in this case an email address that changes from users.
I need to deal with this var:
<iframe name="asd#asd.lol" src="index.html">
index.html is a simple data form like this:
<form ENCTYPE="multipart/form-data" action="upload.php" method="POST">
<p>Upload: <input type="file" name="file1"> <br /></p>
<input type="submit" value="Upload">
</form>
I need to pass the value "asd#asd.lol" to the "upload.php" file.
Is this possible?
Is it possible for you to add a querystring parameter into the index.html file?
So:
<iframe name="asd#asd.lol" src="index.html?email=asd#asd.lol">
Then in the index.html file set a hidden variable:
<form ENCTYPE="multipart/form-data" action="upload.php" method="POST">
<p>Upload: <input type="file" name="file1"> <br /></p>
<input type="hidden" name="email" id="email" value="">
<input type="submit" value="Upload">
</form>
If this is a plain HTML file you could set the value of the hidden field with some javascript.
Then use $_POST["email"] to get the email value out of the hidden field.
<form ENCTYPE="multipart/form-data" action="upload.php" method="POST" onsubmit='$(this).append('<input type="hidden" name="iframeEmail" value="'+$("iframe[src='index.html']").attr('name')+'">')'>
<p>Upload: <input type="file" name="file1"> <br /></p>
<input type="submit" value="Upload">
</form>
Try this out ,if it wont work ,than place the iFrame and ID and find it with the ID on jQuery Selector
Why won't this print "success" when I submit the form? I'm pretty sure it should.
<?php
if (count($_POST) > 0) {
echo "success!!";
}
?>
<form method="post" enctype="multipart/form-data">
<input type="file" name="userfile" />
<input type="submit" value="upload" />
</form>
At a guess, the submit field has no name, so it won't be included in $_POST. Your file upload will be placed in $_FILES, see Handling file uploads.
It is also good practice to NOT ommit the action attribute.
If you want the form to submit to itself, try
<form method="post" action="?" enctype="multipart/form-data">
or
<form method="post" action="<?php echo htmlspecialchars($_SERVER['REQUEST_URI']); ?>" enctype="multipart/form-data">
Further reading on second method Disclaimer: Link to my own blog
<?php
if (count($_POST['submit']) > 0) {
echo "success!!";
}
?>
<form method="post" enctype="multipart/form-data" action="">
<input type="file" name="userfile" />
<input type="submit" value="upload" name="submit"/>
</form>