I have a signup page designed with PHP and HTML for back end connectivity.
After the button click is made entering the details, I display the message Success on the same page with the help of JavaScript.
I need the details to get stored after the button click (its working fine), what I want is after the button is clicked and the PHP database page is opened. I don't want that page to be opened after the button click.
The same signup page should be retained with the entered information saved in the database.
Is there any way to do this?
So right now, on submit, it goes to a page that stores all the data and displays a "database page". But you don't want it to do that, you just want it to go back to the index page, or to a page that says success. Correct?
If that's the case, you can use this on your "database page".
header('Location:http://yoursite.com/path/to/login.php');
Related
I have a web page that loads all the data from a mysql database called datalist.php
From this page I can edit record by record with a button that redirects you to an editdata.php page adapted to the fid of the record.
Once edited as they want to see the changes, I don't redirect them to the main one letting them see the changes and simply clicking back or with a button they return to the datalist.php without any problem.
The button is this
echo "<p id='parrafo'><a style='padding:1px 20px'class='button rounded-0 primary-bg text-white w-0 btn_1 boxed-btn' href='javascript:history.back() '><--</a></p>";
PROBLEM
I added a search engine where the displayed data can be filtered.
When they use the search engine from datalist.php, I direct them to a page called search engine.php where, through a post method, I store what they are looking for in a variable and the data that users want appears.
But when they edit a filtered record, it is edited without problems, but when they go back, they return to the search engine.php and the message appears:
"Confirm form resubmission In order to display correctly, this web page needs the data you entered earlier. You can submit that data again, but that will cause the page to repeat all previous actions. Press Reload to submit the data and display the page.
Hit the page refresh button to resubmit the data needed to load the page."
Of course, if they update, they come back when the filtered data comes out.
Isn't there any way to store the variable used in the search so that when I go back I don't get this error or any solution??
simple! when user will submit form for that variable instead of making post request
option1: just use get request __url__?variable=... but this will not remember the variable when you go back
option2: store the variable in the cookie and just go to next page (eg. window.location.href = '...';). and in next page access the cookie from php.
If you are wanting to show the form to the user as a confirmation, but without the possibility of another post, then remove the form element and the button. Display all other boxes as they are (with the values populated from the POST array).
And display another message telling them that it has been successful.
You are using PHP, you can achieve this easily with it. If you are unsure, then post a short version of your code in a separate question.
I would like to show certain image on a page which is open in a tab, only when the other page press a button. I know I can post on the other page, but is it going to be live? Because I am not gonna be refreshing the page at all. My whole plan is to press a button on one page and show live result on an another page without refreshing it. How can I make it possible? I just need the basic idea behind it. Sorry if I made it sound complicated.
Thanks
When page loaded http://something.com/user/mycourses address in the browser url. In the page there are two ajax requests are there. One is http://something.com/user/learnnow address(Shows learning courses) and http://something.com/user/teaching(shows teaching courses). If I click on teaching, ajax will load the page. If I click on browser back button to go to learnnow page, it takes me another url before mycourses page. I want when user click on browser back button it should go to learnow page from teaching page. How to do this please help me.
I have a standard PHP form that has a series of checkboxes, radio, selects and text. The form works fine and proceeds to a search results page. My problem is that when you click Back browser in any browser the search page shows the previous selects. How do I ensure that the back button displays the form as if its the first time the visitor visits the page?
You can reset form on window.onload or $(document).ready(for jQuery)
function formReset()
{
document.getElementById("formId").reset();
}
you can do one thing.
Using jquery onReady function you can make form reset.
So, whenever user will press back button of browser page will be reload and onReady function your code for form reset will work.
$(document).ready(function() {
$('#myform').get(0).reset();
});
You shouldn't reset it automatically. Provide a reset button.
The back button returns the user to the previous page, in the state he left it. This includes the settings of any form. I'm relying heavily on this feature, cannot count the times this back button saved me from loosing my efforts that went into a textbox for answering questions...
It's a different game if the user is on your result page and clicks a link that takes him to the search page again, but does not use the back button.
I am trying to build a web app like this using php, it has two pages:
select.php has some radio buttons in a html form for users to choose. and there is a submit button post the form to a confirmation page.
confirm.php echos the summery from previous page and there is a "back" button allow users to change their selections in the previous page.
In this point, when I hit the "back" button and previous page restored, I would like all my previous selections displayed. (more clearly, if I chose a radio button and submit in select.php, I want the radio button still being chose after I go back to select page by hitting "back" button from confirm.php page.)
Please give me some idea about how to do this kind of restore page thing.
Save your selection in session.
In select.php pre-select the radio buttons if its found in session.
BTW, You should not rely on back button of browser. Create you own back button on confirm.php page. This back button will go to select.php using no history.back()
The HTTP-Protocol is stateless.
So when calling select.php the server doesn't know anything about your previous selection.
You can either save the selection in the session or in a cookie and restore in in selection.php