select ID so you can create a dynamic query - php

Question

I am new to php and phpmyadmin and I have a problem with a web application that I am making.
I know how to enter items in the DB and how to displays them. But now I have to do both.
I have to make sure they select a name from the option tag that comes from the db. I need the ID of this name so I can create a new query
/* Hier I get the data*/
<form class="form-signin" role="form" name="SelecteerKlas" method="get" action="<?php $_PHP_SELF ?>" >
<select>
<?php
if (!empty($data)) {
foreach ( $data as $var )
{
$k_id=$var['k_id'];
echo "<option name='klasID' value='$k_id'>",$var['k_leerjaar'],$var['k_naam'],"</option>";
}
}else{
$feedback= '<p class="alert alert-danger">Momenteel staan er nog geen klassen in de database!</p>';
echo $feedback;
}
?>
</select>
<input name="btnSelectKlas" type="submit" id="btnSelectKlas" value="Selecteer klas" >
</form>
But I don' know how to proceed ...

Answer 1

you have syntax errors in concate string in below line:
echo "<option name='klasID' value='$k_id'>",$var['k_leerjaar'],$var['k_naam'],"</option>";
and you also need to echo your message outside of the form if array is empty.
Try like this:
<?php
if (!empty($data)) {
?>
<form class="form-signin" role="form" name="SelecteerKlas" method="get" action="<?php $_PHP_SELF ?>" >
<select name="my_select">
<?php
foreach ( $data as $var )
{
$k_id=$var['k_id'];
echo "<option name='klasID' value='$k_id'>".$var['k_leerjaar'].$var['k_naam']."</option>";
}
}
?>
</select>
<input name="btnSelectKlas" type="submit" id="btnSelectKlas" value="Selecteer klas" >
</form>
<?php
else{
$feedback= '<p class="alert alert-danger">Momenteel staan er nog geen klassen in de database!</p>';
echo $feedback;
}
?>
you need check if form is submit after submitting the form you can get select value by $_REQUEST['my_select']