I am iOS developer and I am making Webservices in PHP for getting JSON Response.
Code which I wrote is:
$result = mysqli_query($con,"SELECT * FROM wp_marketcatagories");
$data =array();
while($row = mysqli_fetch_array($result))
{
$data[] = array_push($data, array('id' => $row['id']));
}
$json = json_encode($data);
echo $json;
This is what I want in result:
[{"id":"1"},{"id":"2"},{"id":"3"},{"id":"4"},{"id":"5"},{"id":"6"},{"id":"7"},{"id":"8"},{"id":"9"},{"id":"10"},{"id":"11"},{"id":"12"}]
But above code is giving me like this:
[{"id":"1"},1,{"id":"2"},3,{"id":"3"},5,{"id":"4"},7,{"id":"5"},9,{"id":"6"},11,{"id":"7"},13,{"id":"8"},15,{"id":"9"},17,{"id":"10"},19,{"id":"11"},21,{"id":"12"},23]
From where this 1, 3, 5 ,.... are coming ?
no need to assign it to $data[]. You are already pushing the values to the array $data
Just simply use
array_push($data, array('id' => $row['id']));
instead of
$data[] = array_push($data, array('id' => $row['id']));
Array_Push(): Returns the new number of elements in the array.
...this is were your numbers are coming from and you're adding them to the array with your $data[] = statement
array_push($data, array('id' => $row['id']));
or
$data[] = array('id' => $row['id']);
Same result in this scenario
You don't require to assign $data twice as you have written like this:
$data[] = array_push($data, array('id' => $row['id']));
array_push — Push one or more elements onto the end of array
syntax : array_push(array,value1,value2...)
Just write
array_push($data, array('id' => $row['id']));
or
$data[] = array('id' => $row['id']);
Related
Im generating Chart4PHP.
In sample it takes data like this
$p->data = array(array(array("2010/10",-48),array("2011/01",238),array("2011/02",395)));
I have array "rows" constructed of row[date][units].
Im storing it in this way:
$rows = array();
for(...)
{
$row[date] = $mydate;
$row[units]= $myunits;
$rows[]=$row;
}
What I should make additionally to be able to use it as $p->data = $rows;
To add the extra array container, call array() with the rows array as the argument.
$data = array(array('date' => "2010/10", 'units' => -48),
array('date' => "2011/01", 'units' => 238),
array('date' => "2011/02", 'units' => 395));
foreach ($data as $d) {
$mydate = $d['date'];
$myunits = $d['units'];
$rows[] = array($mydate, $myunits);
}
$p->data = array($rows);
I am trying to make a dynamic JSON array in PHP, however when I try to do so it returns "Array". Here is the code I am currently using:
<?php
require '../../scripts/connect.php';
$array = '';
if($result = $db->query("SELECT * FROM art") or die ($db->error)){
if($count = $result->num_rows) {
while($row = $result->fetch_object()){
$array .= array(
'title' => $row->title,
'image' => "http://www.thewebsite.com/img/2.jpg",
'rating' => 7.7,
'releaseYear' => 2003,
'genre' => array(
'0' => $row->category,
'1' => $row->subcategory
)
);
}
}
}
echo json_encode($array);
?>
Can anyone suggest how I might go about fixing this?
And if anyone has suggestions about creating a dynamic JSON array, some help would be much appreciated.
Change your declaration of $array to be an array:
$array = array();
Then in your while loop, when you add the new array to $array, push it like this:
$array[] = array('title'=>$row->title, etc...)
I'm building an angular application, so I have a PHP script extracting the database data into a JSON when requested.
This is what I'm using to extract the data into an array:
$values = array();
$query = "SELECT * FROM photos ORDER BY id";
$result = $mysqli->query($query);
while ($row = $result->fetch_array(MYSQL_ASSOC)) {
array_push($values, $row);
}
json_encode($values);
But it gives no result.
After some testing, if I change json_encode($values); to print_r($values); it actually print the table array, here an extract:
Array (
[0] => Array (
[id] => 4
[title] => Feel the Moment
[views] => 6
)
It seems the script is not creating a valid array.
$query = "SELECT * FROM photos ORDER BY id";
if ($result = $this->mysqli->query($query)) {
$json = array();
while ($row = $result->fetch_assoc()) {
$json[] = $row;
}
echo json_encode($json);
}
Your while is not executing, probably because you don't have any returned values from database.
I tested this code and it works well:
$json = array();
$json[] = array(
"id" => 1,
"category" => 'a',
"tags" => 't');
$json[] = array(
"id" => 2,
"category" => 'b',
"tags" => 'tt');
echo json_encode($json);
The result is:
[{"id":1,"category":"a","tags":"t"},{"id":2,"category":"b","tags":"tt"}]
And you'd better use mysqli_fetch_row or mysqli_fetch_assoc.
Try to debug your code. You may use var_dump($result->fetch_assoc()) to see if the query has some results.
$result = mysql_query($query);
$leaderboard = array();
while($row = mysql_fetch_assoc($result)) {
$leaderboard[$row["username"]] = $row["score"];
}
$output = array
(
'status' => 1,
'content' =>$leaderboard
);
print_r(json_encode($output));
right now the $output array is such JSON:
{"tim":"120","john":"45","larry":"56"}
but I want to have them as key-value pair so instead I want to be like:
{"name":"tim","score":120","name":"john","score="45", etc.}
and if I need that way, how do I modify the $leaderboard array so the output would be like that?
$leaderboard[] = Array('name' => $row["username"], 'score' => $row["score"]);
I have been looking around for PHP tutorials and I found a very detailed one that have been useful to me.
But now, I have a question. The results showed by the API are stored into a $results array. This is the code (for instance):
$fetch = mysql_fetch_row($go);
$return = Array($fetch[0],$fetch[1]);
$results = Array(
'news' => Array (
'id' => $return[0],
'title' => $return[1]
));
My question is.. I want to display the last 10 news.. how do I do this? On normal PHP / mySQL it can be done as:
while($var = mysql_fetch_array($table)) {
echo "do something"
}
How can I make it so the $results can print multiple results?
I have tried like:
while($var = mysql_fetch_array($table)) {
$results = Array(
'news' => Array (
'id' => $return[0],
'title' => $return[1]
));
}
But this only shows me one result. If I change the $results .= Array(...) it gives error.
What can I do?
Thanks!
Edit
My function to read it doesn't read when I put it the suggested way:
function write(XMLWriter $xml, $data){
foreach($data as $key => $value){
if(is_array($value)){
$xml->startElement($key);
write($xml, $value);
$xml->endElement();
continue;
}
$xml->writeElement($key, $value);
}
}
write($xml, $results);
$results[] = Array(
'news' => Array (
'id' => $return[0],
'title' => $return[1]
));
That should do it.
If you are familiar with arrays, this is the equivalent of an array_push();
array_push() treats array as a stack, and pushes the passed variables onto the end of array. The length of array increases by the number of variables pushed. Has the same effect as:
<?php
$array[] = $var;
?>
Use [] to add elements to an array:
$results = array();
while($var = mysql_fetch_array($table)) {
$results[] = Array(
'news' => Array (
'id' => $var[0],
'title' => $var[1]
));
}
}
You can then loop through the $results array. It's not an optimal structure but you should get the hang of it with this.