How to insert multiple records to MySQL - php

Question

i have small page with cart. All things is storage in session. Now i need to save this data to mysql databse.
I think, that i need use foreach cycle to do this, but i cant construct it. Does anybody know the solution?
This is the function that displays cart.
function showCart() {
global $db;
$cart = $_SESSION['cart'];
if ($cart) {
$items = explode(',',$cart);
$contents = array();
foreach ($items as $item) {
$contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1;
}
$output[] = '<form action="cart.php?action=update" method="post" id="cart">';
$total=0;
$output[] = '<table>';
foreach ($contents as $id_menu=>$qty) {
$sql = 'SELECT * FROM menu WHERE id_menu = '.$id_menu;
$result = $db->query($sql);
$row = $result->fetch();
extract($row);
$output[] = '<tr>';
$output[] = '<td>Delete</td>';
$output[] = '<td>' .$name. '</td>';
$output[] = '<td>' .$price.' Kč</td>';
$output[] = '<td><input type="text" name="qty'.$id_menu.'" value="'.$qty.'" size="5" maxlength="5" /></td>';
$output[] = '<td>' .($price * $qty).' Kč</td>';
$total += $price * $qty;
$output[] = '</tr>';
}
$output[] = '</table>';
$output[] = '<p>Total: <strong>'.$total.' EUR</strong></p>';
$output[] = '<div><button type="submit">Update</button></div>';
$output[] = '</form>';
} else {
$output[] = '<p>Cart is empty.</p>';
}
return join('',$output);
}

Answer 1

i think you need something like this....
foreach ($contents as $id_menu=>$qty)
{
$sql1 = 'INSERT INTO tablename (colum1, colum2, column3, ... ) SELECT * FROM menu WHERE id_menu = '.$id_menu;
//rest of your program
}

Answer 2

You can use:
Insert into mytable SELECT * FROM menu WHERE id_menu = ...
To construct the multiple insert and insert all in one statement, do the following:
Insert into mytable (col1, col2, col3) values
('Val1a','val2a','val3a'),
('Val1b','val2b','val3b'),
('Val1f','val2d','val3c'),
Etc...
;
Each iteration will concatenate one line of values. Insert is then done after the loop.