Array not displaying, Notice: array to string conversion - php

Question

I am attempting to display the contents of an array. I have a SELECT query that transfers two rows from the data base with a WHERE statement;
<?php
session_start();
include 'connection.php';
$inspectit = array();
$update1 = $_POST['inspect'];
$query1 = "SELECT title, reason FROM daysoff WHERE DATE(start) = '$update1' AND gighold = 1";
$day = mysql_query($query1);
while($requesting = mysql_fetch_array($day)) {
$inspectit[] = $requesting;
}
$_SESSION['inspect'] = $inspectit;
header('Location: '. $_SERVER['HTTP_REFERER']) ;
?>
I place the session variable into a new variable,$inspect, defined on a different page. I then try to display the array using;
<?php
session_start();
$inspect = $_SESSION['inspect'];
if($inspect == true) {
echo " </br>Name: </br><a> ". implode($inspect) ."</a></br></br>";
unset ($_SESSION['inspect']);
}
?>
If i var_dump($inspect) all the expected data is there, but it looks like an array holding another array. If i execute code as shown above, this gives a notice of array to string conversion. Where am i going wrong?

Answer 1

<?php
session_start();
$inspect = $_SESSION['inspect'];
if($inspect) {
echo " </br>Name: </br><a> ". implode($inspect) ."</a></br></br>";
unset ($_SESSION['inspect']);
}
?>

Answer 2

You are adding an array of query result into an array. try to change:
from:
while($requesting = mysql_fetch_array($day)) {
$inspectit[] = $requesting;
}
to:
$inspectit = mysql_fetch_array($day);

Answer 3

$_SESSION['inspect'] is an array, so you can used check like
$inspect = $_SESSION['inspect'];
if(count($inspect)>0) {
instead of
if($inspect == true) {

Answer 4

try
<?php
session_start();
$inspect = $_SESSION['inspect'];
if($inspect) {
echo " </br>Name: </br><a> ". implode("-",$inspect) ."</a></br></br>";
unset ($_SESSION['inspect']);
}
?>
or you can use empty() function too like
<?php
session_start();
$inspect = $_SESSION['inspect'];
if(!empty($inspect)) {
echo " </br>Name: </br><a> ". implode("-",$inspect) ."</a></br></br>";
unset ($_SESSION['inspect']);
}
?>

Answer 5

With $inspectit = array(); you are setting $inspectit to an array, then you are trying to set the string (or non-array) $_SESSION['inspect'] to equal that array. You can iterate multiple $_SESSION variables to each iteration of $inspectit as follows:
$n=0;
while($requesting = mysql_fetch_array($day)) {
$_SESSION['inspect'+$n] = $requesting;
$n++;
}
$_SESSION['inpect_count']=$n;
Thus you will know how many variables you setup with the $_SESSION['inpect_count']

Answer 6

I tried all above methods to no avail. I did however get it to work by doing;
<?php
session_start();
include 'connection.php';
$inspectname = array();
$inspectreason = array();
$update1 = $_POST['inspect'];
$query1 = "SELECT title, reason FROM daysoff WHERE DATE(start) = '$update1' AND gighold = 1";
$day = mysql_query($query1);
while($requesting = mysql_fetch_array($day)) {
$inspectname[] = $requesting['title'];
$inspectreason[] = $requesting['reason'];
}
$_SESSION['inspectname'] = $inspectname;
$_SESSION['inspectreason'] = $inspectreason;
header('Location: '. $_SERVER['HTTP_REFERER']) ;
?>
then to call and display the arrays;
<?php
if($inspectname == true) {
$size = sizeof($inspectname) - 1;
for($count = 0; $count <= $size; $count++){
echo " </br>Name: </br><a> ". $inspectname[$count] ."</a>";
echo " </br>Details: </br><a> ". $inspectreason[$count] ."</a></br></br>";
unset ($_SESSION['inspectname']);
unset ($_SESSION['inspectreason']);}
}
?>