Here is my Code :
<html>
<head>
<title>Untitled Document</title>
</head>
<body>
<form id="form1" action="../../../wamp/www/abc.php" method="get">
<input type="text" name="text1" id="username" />
<input type="submit" />
</form>
</body>
</html>
The abc.php file is located in C:/wamp/www/abc.php
<html>
<body>
Hello World
<?php
echo "Hello";
echo $_GET["username"];
?>
</body>
</html>
In the form, when I press the Submit button, only "Hello World" is displayed.
The value entered in the textbox is not displayed at all. Even the "Hello" message printed inside the php code is not displayed.
How can i display the Value ?
text1 is the name of your input, so the correct PHP code would be.
<?php
echo "Hello ";
echo $_GET['text1'];
?>
Try the below, get array is created using name attr not id one.
echo $_GET["text1"];
There is two solution for you should use :
First Way :Change your php code:
<?php
echo "hello";
echo $_GET["text1"];
?>
Second Way: Chnage your HTML
<input type="text" name="username" id="username"/>
If second "Hello" from echo is not displayed, there is a problem with your PHP installation.
Related
I really don't know why my code isn't working! Let me clear it by example..
I got a file named 'index.html' example...
<html>
<body>
<form action="test.php" method="post">
Name: <input type="text" name="test">
<input type="submit">
</form>
</body>
</html>
And of course the form action file test.php .. example..
<?php
$something = ($_POST["test"]);
// from here I have some PHP codes and this "something" variable will be process in this codes and will print out something spacial..
?>
Now example If I post "Hello, It's not working" then the output will show a spacial design.
But Instead process, it's just printing out whatever I submit in that form.
But when I manually add the variable to "something" and if I execute the "test.php" . Example..
$something = "Hello, It's not working";
Then it works perfectly..
And yes. Also tried GET method.. It's still same as POST.
This is my first question here..
Thanks for any help and suggestions!
First Convert, index.html to php and follow this code:-
<html>
<body>
<form action="test.php" method="post">
Name: <input type="text" value="" name="test">
<input name="submit" value="submit" type="submit">
</form>
</body>
</html>
<?php
if(isset($_POST['submit'])){
$something = $_POST["test"];
}
?>
That's correct _POST:
<?php
//NO ($_POST["test"])
$something = $_POST["test"];
?>
this is the code for my html page in the site:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>index</title>
</head>
<body>
<html>
<body>
<form action="Untitled-4.php" method="get">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>
</body>
</html>
</body>
</html>
and this is my code for the "Untitled-4.php" file:
<html>
<body>
<?php
if ($_GET["name"] == "tom"){
echo "hello you are special";
}
?>
</body>
</html>
this is the error i am getting:
"undefined index on line 7 of the php file"
I am trying to use the GET method to take whatever the user types in the "name" box to be used in the if statement that echoes "you are special" if the user types in "tom". can anyone tell me what the problem here is.
(the question stack overflow is saying is a possible duplicate is a completely different question)
Check if the variable is set first:
<html>
<body>
<?php
if (isset($_GET["name"])) {
if ($_GET["name"] == "tom"){
echo "hello you are special";}
} else {
echo "you are not special";
}
?>
</body>
</html>
for some reason i just tried it again with no changes to my code and it appears to be working i did not actually have to do anything.
A php 'if statement' example from a tutorial by Kevin Yank doesn't seem to work. Specifically, both branches of the conditional appear when the page loads.
I have also tried changing to the non-shorthand 'if' syntax, to no avail.
Is the problem something other than syntax?
The code is as follows:
<!DOCTYPE html>
<html>
<head>
<title> Sample Page </title>
</head>
<body>
<?php if(isset($name)) : ?>
<p> Your name: <?php echo ($name); ?> </p>
<p> This paragraph contains a link that passes the name variable on to the next document. </p>
<?php else : ?>
<!-- No name has been provided, so prompt the user for one -->
<form action="<php echo($PHP_SELF); ?>" method="get">
Please enter your user name:
<input type="text" name="name">
<input type="submit" value="ok">
</form>
<?php endif; ?>
</body>
</html>
This script left out a very important element >>> $name=$_GET['name']; <<<
The name must first be declared as a variable.
It has been added inside this line: <?php if(isset($name)) : ?>
See my code below: (tested and working)
<HTML>
<HEAD>
<TITLE> Sample Page </TITLE>
</HEAD>
<BODY>
<?php $name=$_GET['name']; if (isset($name)): ?>
<P>Your name: <?php echo($name); ?></P>
<P>This paragraph contains a
<A HREF="newpage.php?name=<?php echo(urlencode
($name)); ?>">link</A> that passes the
name variable on to the next document.</P>
<?php else: ?>
<!-- No name has been provided, so we
prompt the user for one. -->
<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD="GET">
Please enter your name: <INPUT TYPE="TEXT" NAME="name">
<INPUT TYPE="SUBMIT" VALUE="GO">
</FORM>
<?php endif; ?>
</BODY>
</HTML>
Plus as an added bonus (tested and working), you can use the PHP code below, inside your goodone.php file to echo the name after you clicked on the link after you submitted the form. You can do whatever you wish from hereonin, for database use, etc.
<?php
echo($_GET['name']);
// do something else
?>
On one PHP server I have two files. One file (the name is "first.php") contains this code:
<html>
<head>
<title>First Page</title>
</head>
<body>
Please enter your password and age:
<form action="pass.php" method="post">
Name: <input type="text" name="fname" />
Age: <input type="text" name="age" />
<input type="submit" />
</form>
</body>
</html>
The other file ("pass.php") contains this code:
<html>
<head>
<title>Secon Page</title>
</head>
<body>
<?php
if ($fname=="Jack")
echo "You are Jack!";
else
echo "You are not Jack!";
?>
</body>
</html>
As far as I understand, if a user enters "Jack" in the first page, than the second page should be displayed with "You are Jack!" line, but it doesn't happen. Why is it so?
On your second page, instead of checking for $fname, check for $_POST['fname'] instead. I think that is all you are missing.
You probably don't have register_globals set. This is depreciated and will be removed in 6.x. So for good programming you should instead of $fname try $_POST['fname'] on your second page.
pass.php needs to look like this
<html>
<head>
<title>Secon Page</title>
</head>
<body>
<?php
if ($_POST['fname'] =="Jack")
echo "You are Jack!";
else
echo "You are not Jack!";
?>
</body>
</html>
It might help to set the post values as variables and work with that. Something like this:
foreach($_POST as $key => $value)
{
$$key = $value;
}
Then whatever is posted will be available rather than using $_POST['xxxxx'] in your logic.
I have a file test.php with the following code:
<html>
<head>
<title>Listing 10.2 </title>
</head>
<body>
<div>
<form method="post" action="test.php" >
<p> <input type="text" name="guess"/> </p>
</form>
<?php
if(!empty($_POST['guess'] )) {
print "Last guess $_POST['guess']";
}
?>
</div>
</body>
</html>
I have a problem with the form not showing up. However, if I remove the PHP portion of the code, it is visible. What is my problem?
You can't embed the $_POST variable into the string like that, trying changing the php section to:
<?php
if(!empty($_POST['guess'] )) {
print "Last guess {$_POST['guess']}";
}
?>
Use . for combine values and strings
if(!empty($_POST['guess'] ))
{
echo "Last guess".$_POST['guess'];
}