How To Upload Multiple Images With Links To Them In mysql - php

Question

Currently I have a code which is working perfectly for one image upload. But i want to upload multiple images at a time with same Image Title, Image Description for image group being uploaded as these images will be used in photo slideshow(See Images below please)
My Current Code is as follows -
PHP Code -
$bsq->connect_db();
$fileName = $_FILES["image"]["name"];
$fileNameNew = preg_replace('/\s+/', '_', $fileName);
$fileTmpLoc = $_FILES["image"]["tmp_name"];
// Path and file name
$pathAndName = "uploads_admin/".$fileNameNew;
// Run the move_uploaded_file() function here
$moveResult = move_uploaded_file($fileTmpLoc, $pathAndName);
// Evaluate the value returned from the function if needed
if($_POST['action']=="add"){
$all_columns[]="image_subject";
$all_columns[]="image_name";
$all_columns[]="clinic";
$all_columns[]="image_link";
//Get All values to insert in to table
$all_values[]=addslashes($_POST["image_subject"]);
$all_values[]=addslashes($_POST["image_name"]);
$all_values[]=addslashes($_POST["clinic"]);
$all_values[]=addslashes($pathAndName );
//=====================
$qry=$bsq->webdreaminsert("sa_galleryuploads_by_admin",$all_columns,$all_values,'');
echo mysql_error();
header("location:upload_file_for_downloading_list.php");
///////////////////////////////////////////////////
}
And HTML Form For upload Image Is As follows -
<form action="" method="post" enctype="multipart/form-data" name="addtwebinar1" id="addtwebinar1" onsubmit="javascript:return validateimage1();" >
<input type="hidden" value="add" name="action" />
<table width="90%" align="center" border="0" cellpadding="0" cellspacing="0" class="ListTable1">
<tr class="HeadBr">
<td colspan="4"><div align="center"><strong>Add Images For Photo Gallery</strong></div></td>
</tr>
<tr >
<td>Image Title*</td>
<td><input name="image_name" id="image_name" type="text" size="40" value="" /></td>
</tr>
<tr>
<td>Image Description In Short*</td>
<td><input name="image_subject" id="image_subject" type="text" size="40" value="" /></td>
</tr>
<tr >
<td>Clinic Name*</td>
<td>
<select name="clinic" id="message" >
<option value="">Select Clinic</option>
<option value="arogya">1. Arogyawardhini Ayurved Clinic</option>
<option value="smruti">2. Smruti Ayurved Clinic</option>
<option value="tarpan">3. Tarpan Ayurved Clinic</option>
<option value="vishwa">4. Vishwawardhini Ayurved Clinic</option>
</select>
</td>
</tr>
<tr >
<td>Your Image For Upload* </td>
<td><label for="image">File To Upload: </label><br>
<input type="file" size="40" name="image" id="image" /><br />
</td>
</tr>
<tr>
<td></td>
<td><button >Upload</button></td>
</tr>
</table>
</form>
Current Look of My Active Image upload Form -
And I Want Like Below (Created Graphically)

Answer 1

You can use a for loop.
For the form, do something like this:
for($i = 1; $i <= 4; $i++) {
echo "<input type=\"file\" size=\"40\" name=\"image{$i}\" id=\"image{$i}\" /><br />";
}
And for the processing, just put all of that in a for loop as well.
for($i = 1; $i <= 4; $i++) {
$fileName = $_FILES["image".$i]["name"];
$fileNameNew = preg_replace('/\s+/', '_', $fileName);
$fileTmpLoc = $_FILES["image".$i]["tmp_name"];
// Path and file name
$pathAndName = "uploads_admin/".$fileNameNew;
// Run the move_uploaded_file() function here
$moveResult = move_uploaded_file($fileTmpLoc, $pathAndName);
// Evaluate the value returned from the function if needed
if($_POST['action']=="add"){
$image_name = mysql_real_escape_string($_POST['image_name']);
$image_subject = mysql_real_escape_string($_POST['image_subject']);
$clinic = mysql_real_escape_string($_POST['clinic']);
$image_link = "http://".$_SERVER['HTTP_HOST'].rtrim(dirname($_SERVER['REQUEST_URI']), "\\/")."/".$pathAndName;
//=====================
mysql_query("INSERT INTO `sa_galleryuploads_by_admin` VALUES ('', '{$image_name}', '{$image_subject}', '{$clinic}', '{$image_link}' )") or die(mysql_error());
if(!mysql_error()) {
echo "success";
}
}
You can edit the number that the loop goes up to, to match the number of fields/images you want to show. Good luck!
edit: You also need to sanitize validate your inputs. At the very least, use mysql_real_escape_string().
Also, mysql_* functions are deprecated. You should switch to using either mysqli or pdo. I'd suggest mysqli to start off, because it also offers a procedural approach, whereas pdo is completely object oriented.