How do I get the result into a variable MYSQL - php

Question

I have the following PHP script. How do I get the correct results. Each query should only return a number. I need to get rank in this case. I was also wondering how to combine those two queries into one statement.
function getRankings($country, $deviceid)
{
$queryWorld = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score ) AS rank FROM
ScoreTable b WHERE DeviceID='$deviceid' ORDER BY rank LIMIT 1";
$queryCountry = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score AND Country='$country') AS rank FROM ScoreTable b WHERE DeviceID='$deviceid' ORDER BY rank LIMIT 1";
$resultWorld = mysql_query($queryWorld) or die(mysql_error());
$rowWorld = mysql_fetch_row($resultWorld);
$resultCountry = mysql_query($queryCountry) or die(mysql_error());
$rowCountry = mysql_fetch_row($resultCountry);
$arr = array();
$arr[] = array("WorldRanking" => $rowWorld[0], "CountryRanking" => $rowCountry[0]);
echo json_encode($arr);
}
If I type the queries individually into MYSQl I get the correct answers. But the echo produces
[{"WorldRanking":null,"CountryRanking":null}]
It should be something like
[{"WorldRanking":"4","CountryRanking":"1"}]
I think I need to get the value of rank but I do not know how.

Answer 1

try your code like this, but I don't know this code correct or not:
function getRankings($country, $deviceid)
{
$queryWorld = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score ) AS rank FROM
ScoreTable b WHERE DeviceID='$deviceid' ORDER BY rank LIMIT 1";
$queryCountry = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score AND Country='$country') AS rank FROM ScoreTable b WHERE DeviceID='$deviceid' ORDER BY rank LIMIT 1";
$resultWorld = mysql_query($queryWorld) or die(mysql_error());
while ($rowWorld = mysql_fetch_row($resultWorld)){
$value1 = $rowWorld['filedname1'];
}
$resultCountry = mysql_query($queryCountry) or die(mysql_error());
while($rowCountry = mysql_fetch_row($resultCountry)){
$value2 = $rowWorld['filedname2'];
}
$arr[] = array("WorldRanking" => $value1, "CountryRanking" => $value2);
print_r($arr);
}

Answer 2

<?php
function getRankings($country, $deviceid)
{
$queryWorld = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score ) AS rank FROM
ScoreTable b WHERE DeviceID=$deviceid ORDER BY rank LIMIT 1";
$queryCountry = "SELECT 1 + (SELECT count( * ) FROM ScoreTable a WHERE a.score > b.score AND Country='$country') AS rank FROM ScoreTable b WHERE DeviceID=$deviceid ORDER BY rank LIMIT 1";
$resultWorld = mysql_query($queryWorld) or die(mysql_error());
$no_of_results_in_resultWorld = mysql_num_rows($resultWorld);
if($no_of_results_in_resultWorld > 0){
$rowWorld = mysql_fetch_row($resultWorld);
}
$resultCountry = mysql_query($queryCountry) or die(mysql_error());
$no_of_results_in_resultCountry = mysql_num_rows($resultCountry);
if($no_of_results_in_resultCountry > 0){
$rowCountry = mysql_fetch_row($resultCountry);
}
$arr = array();
$arr[] = array("WorldRanking" => $rowWorld[0], "CountryRanking" => $rowCountry[0]);
echo json_encode($arr);
}
check whether it is returning results or not.