I have developed API's with Zf2 and DynamoDB, I am able to get values from GET params in my local machine but unable to get values from GET params when I uploaded the API's in production
.
FYI: POST method is working properly in production.
Below is the controller get function.
public function get($id)
{
$abcModel = new ABCModel();
error_log("tournamentId:".$this->params()->fromQuery('tournamentId') );
$query = $this->getRequest()->getQuery();
error_log("tournamentId1:".$query['tournamentId']);
error_log("tournamentId2:".$this->getEvent()->getRouteMatch()->getParam('tournamentId'));
error_log("tournamentId3:".$this->params('tournamentId'));
error_log("tournamentId4:".$this->params()->fromRoute('tournamentId'));
}
I have tried all the answers of this question ZF2: Get url parameters in controller.
Can any one know what could be the reason for this?
Any light on the path would be helpful.
To use query string in the production environment, you have to use some alternate approach.
You can add parameter along with route to hold the query string value. But the query string needs to be passed using "/" mark between the route and query string instead of using "?" mark.
/route-name/key=value&key=value1
and the routing configuration need to be
'router' => array(
'routes' => array(
'<route-name>' => array(
'type' => 'segment',
'options' => array(
'route' => '<route-name>[/:action][/:queryPara][/]',
'constraints' => array(
'action' => '[a-zA-Z][a-zA-Z0-9_-]*',
'queryPara' => '[a-zA-Z][a-zA-Z0-9_-&=]*',
),
'defaults' => array(
'controller' => 'Application\Controller\Index',
'action' => 'index',
)
),
),
)),
You can create a function that will extract the query string and returns the array containing key=>value pairs of query string.
And in controller you have to call the function by passing the query string which will be stored in "/queryPara" part after the route name using the following statement you will get the string
$this->params('queryPara')
Hope it helps
Thanks
Related
I'm having trouble finding how to get the Urls from named routes inside a Phalcon PhP controller. This is my route:
$router->add(
'/admin/application/{formUrl:[A-Za-z0-9\-]+}/{id:[A-Za-z0-9\-]+}/detail',
[
'controller' => 'AdminApplication',
'action' => 'detail'
]
)->setName("application-details");
I want to get just the Url, example: domain.com/admin/application/form-test/10/detail . With the code below I can get the html to create a link, the same result of the link_to.
$url = $this->tag->linkTo(
array(
array(
'for' => 'application-details',
'formUrl' => $form->url,
'id' => $id
),
'Show'
)
);
The result I want is just the Url. I'm inside a controller action. I know it must be really simple, I just can't find an example. Can you help me?
Thanks for any help!
You should use the URL helper. Example:
$url = $this->url->get(
[
'for' => 'application-details',
'formUrl' => $form->url,
'id' => $id,
],
[
'q' => 'test1',
'qq' => 'test2',
]
);
You can pass second array for query string params if needed.
According to your route definition, the above should output something like:
/admin/application/form-url/25/detail?q=test1&qq=test2
More info of Generating URIs in the docs.
I'm struggling on this for 2 hours now. I've managed to create a route with parameter (named url) like /login/url:
'login' => array(
'type' => 'segment',
'options' => array(
'route' => '/login[/:url]',
'defaults' => array(
'controller' => 'my_controller',
'action' => 'login',
),
),
),
However I'd like to have an URL which looks like /login?url=foo. I've tried something like:
'route' => '/login[?url=:url]',
But it does not work. Any idea how to achieve this on Zend Framework 2 ?
Thanks a lot!
EDIT:
Trying something else like:
// onBootstrap method --> redirect to login page with request url as param
$url = $router->assemble(
array('url', $e->getRequest()->getRequestUri()),
array('name' => 'login')
);
In controller (login action):
$request = $this->getRequest();
var_dump($request); exit;
I don't see the requested URL anywhere... any suggestion?
I don't think you should put your query string segment in your route. It would seem reasonable to have your route to be just /login and then manage your query string parameter in the controller.
Otherwise, but I don't recommend it since it is deprecated, you could try to use the Query router.
Is it possible to pass multiple parameters to an action in the controller by using the method postLink of the FormHelper?
I didn't manage to do it by using the options array. It is not very well specified in the docs what values this array admits.
This is what I tryed:
$this->Form->postLink($staffUser['User']['_name'], array(
'action' => 'subscribe',
array('ticketId' => $ticket['Ticket']['id'], 'userId' => $staffUser['User']['id'])
));
My subscribe action looks like this:
public function subscribe($ticketId, $userId = null){
if ($this->request->is('post')) {
//...
}
}
Update
I've just noticed the provided solution creates another problem to me. Now the class stop getting added ulike before when I was using only one parameter:
$this->Form->postLink($staffUser['User']['_name'], array(
'action' => 'subscribe',
$ticket['Ticket']['id'],
$staffUser['User']['id'],
array('class' => 'demo') //not beind added
));
postLink takes its URL entry in the same form as the create method. Parameters don't need a key, put them in order after the action key/value.
Other options need to go in the third argument - you have the options array as an additional entry to the url array.
$this->Form->postLink($staffUser['User']['_name'], array(
'action' => 'subscribe',
$ticket['Ticket']['id'],
$staffUser['User']['id']
),
array(
'class' => 'demo'
)
);
See options for FormHelper::create here:
http://book.cakephp.org/2.0/en/core-libraries/helpers/form.html
I can't figure out to generate Url from everywhere i want to, in zend 2
I get action and controller so i try this:
$this->url('myControllerName', array('action' => 'myActionName'));
But this return an object, i just want the full URL string of this route
Somebody can help me to find the proper way?
EDIT : according to Stoyan, maybe i made a mistake on my route. here is the part of my module.config
'router' => array (
'routes' => array (
'indexqvm' => array (
'type' => 'segment',
'options' => array (
'route' => '/Indexqvm[/:action][/:id_event]',
'constraints' => array (
'action' => '[a-zA-Z][a-zA-Z0-9_-]+',
'id_event' => '[0-9]+'
),
'defaults' => array (
'controller' => 'Qvm\Controller\Indexqvm',
'action' => 'index'
)
)
),
And my call :
echo $this->url('indexqvm', array('action' => 'list-index'));
the error :
Catchable fatal error: Object of class Zend\Mvc\Controller\Plugin\Url could not be converted to string
Use the echo before calling $this->url(...) (see bellow) and this will display the whole URL.
<?php echo $this->url('route-name', $urlParams, $urlOptions); ?>
Note that the first paramter of url() is the name of the route as specified in your [module]/config/module.config.php file.
See this for more information about ZF2's URL view helper.
EDIT in response to the question edit:
The above section is related to using the URL view helper.
If you want a URL in the controller then you need the URL controller plugin.
<?php $url = $this->url()->fromRoute('route-name', $params, $options); ?>
This is the reference to the ZF2 manual for this controller plugin.
Hope this helps :)
Stoyan
You can use this in the .phtml file
echo $this->url('HelloWorld/default', array('controller'=>'Index', 'action'=>'registration'));
Where HelloWorld/default is the routing and the remaining is the controller and its action and also you can send the others parameter adding just in array as key and value pair.
I'm using Zend Framework 1.12 and have this route:
$router->addRoute('item_start',
new Zend_Controller_Router_Route_Regex(
'(foo|bar|baz)',
array(
'module' => 'default',
'controller' => 'item',
'action' => 'start'
),
array(
1 => 'area'
),
'%s'
)
);
Problem is, when I call '/foo' and use the Url Helper in the View, it doesn't give me any parameters:
$this->url(array("page"=>1));
// returns '/foo' (expected '/foo/page/1')
$this->url(array("page"=>1), "item_start", true);
// also returns '/foo'
Any idea how to get the page-parameter into the URL? I can't use the wildcard like in the standard route, can't I?
In addition to David's suggestions, you could change this route to use the standard route class, and then keep the wildcard option:
$router->addRoute('item_start',
new Zend_Controller_Router_Route(
':area/*',
array(
'module' => 'default',
'controller' => 'item',
'action' => 'start'
),
array(
'area' => '(foo|bar|baz)'
)
)
);
// in your view:
echo $this->url(array('area' => 'foo', 'page' => 1), 'item_start');
Your Regex route doesn't have a page parameter, so when the url view-helper ends up calling Route::assemble() with the parameters you feed it, it ignores your page value.
The two choices that come to mind are:
Modify your regex to include a (probably optional with default value) page parameter
Manage the page parameter outside of your route in the query string.