I was wondering if it is even at all possible to execute an command such as "crontab -l" via webpage? This seems to be an permission issue.
$out = shell_exec('crontab -l');
echo '<pre>'.$out.'</pre>';
When this is executed via PHP, the value of $out is empty.
From PHP.net :
It is not possible to detect execution failures using this function.
exec() should be used when access to the program exit code is
required.
I suggest you use exec so that you can check if the command executed successfully. You should be able to output any data.
Something like:
exec('crontab -l 2>&1', $output, $return_code)
if ($return_code !== 0) {
//Returned Error
echo implode("\n", $output); // display output
} else {
//Returned OK
echo implode("\n", $output); // display output
}
Well this is what I ended up doing...
I added a a cron job to update a txt file with the outout of crontab -l every minute
crontab -l > /var/www/html/logs/cronJobs.txt
Set the permission of cronJobs.txt
Link the cronJobs.txt from the PHP page
Related
Here is a command I successfully execute in terminal:
PHP process_scan.php
I want to execute that code every time a user visits a file, which exists in the same directory as the file mentioned in the command.
Here is the code in the file:
exec('PHP process_scan.php 2>&1', $output, $retval);
Running the file in the browser, $retval = 127 wit $output = "sh: PHP: command not found".
How can I successfully run the command every time a user visits the file?
Instead of referencing PHP, I got this to work by executing PHP bin file:
exec('/usr/bin/php process_scan.php 2>&1', $output, $retval);
I have a a shell script (myscript.sh), which contains many bash commands. I want to run these command from a php file (index.php).
I used exec to execute the commands as following:
$contents = file_get_contents('../folder/myscript.sh');
$output = null;
$return_var = null;
exec($contents, $output, $return_var);
print_r($contents);
print_r($return_var);
print_r($output);
Here is the content of myscript.sh
VAR1=("somePath/allDirs")
ls
cd ..
ls
for DIR in "${VAR1[#]}"; do
echo "Name is $DIR"
done
pwd
....... other 5 lines of commands
All commands before the loop is working i.e: ls and cd .. and I got the output. However, the for loop is not working and it stop executing the rest of the commands after it.
My question is: how to execute this for loop that is inside shell script file from php file?
note: the for loop contains more command here I just put the echo to make the code easy to read and clear.
Are you mutating the contents of the script at all? Why not just execute the script file rather than passing in the contents of the script? Regardless, if you must pass the contents directly to exec, pass it to bash -c and escape the command contents:
$contents = file_get_contents('../folder/myscript.sh');
$output = null;
$return_var = null;
$contents = escapeshellarg($contents);
exec("bash -c $contents", $output, $return_var);
I tried many solutions but nothing it works :
echo '<pre>';
shell_exec("python /home/folder/python/mapfile_compress.py");
shell_exec("sudo -u wwwexec python escapeshellcommand(/home/folder/python/mapfile_compress.py) $uid");
shell_exec("sudo chmod +x /home/folder/python/mapfile_compress.py");
system("bash /home/folder/python/mapfile_compress.py");
passthru("bash /home/folder/python/mapfile_compress.py");
passthru("/home/folder/python/mapfile_compress.py");
exec("bash /home/folder/python/mapfile_compress.py");
echo '</pre>';
I launched indivdually them but in all cases, Firebug returned : '<pre>'
So I tried this code founded on Stack Overflow :
$command = escapeshellcmd('chmod +x /home/folder/python/mapfile_compress_test.py');
echo $command;
$output = shell_exec($command);
echo $output;
But firebug returned nothing.
My python file begin with #!/usr/bin/env python and if I launch it on server that works !
Do you knwo how can I launch my python file from PHP file ?
chmod will return 0 on success and > 0 on error.
Make sure that the file is able to run by just executing it as the web user. When +x is properly set, you can execute it by just calling $ /path/to/your/file.py, the shebang in the first line in your script #!/usr/bin/env python should define the correct python based on your env.
You can test this by running:
$ /usr/bin/env python /path/to/your/file.py
So check your file permissions to check if the file is executable by the user that runs the php script.
Just to test, you can just print a few lines in your python file
#!/usr/bin/env python
print "test line 1"
print "test line 2"
Then if you have verified permissions and the correct use of python, you can do this in your php.
$command = escapeshellcmd('/path/to/your/file.py');
$output = shell_exec($command); // get all output or use passthrough, exec will only return the last line.
echo "<pre>{$output}</pre>;
At first, Do you have enabled shell_exec/system/passthru commands in php.ini?
shell_exec("python /home/folder/python/mapfile_compress.py");
I think, it could be problem with your $PATH. Try something like: (use full path to python)
shell_exec("/usr/bin/python /home/folder/python/mapfile_compress.py");
shell_exec("/usr/local/bin/python /home/folder/python/mapfile_compress.py");
In my case that's work if I write this code :
$command = escapeshellcmd('python /path/to/your/file.py');
exec($command);
I have a shell script in Linux that performs SFTP to get some files. It works fine when I execute it from a terminal.
I am trying to call the script from PHP. It seems to work until the echo, and then it doesn't do anything.
The script and the PHP file are in the same folder.
This is the PHP code:
<?php
$comando = "sh ftpgesdoc.sh";
$result=exec($comando);
echo $result;
?>
And this is shell script. When I execute from the web, I can see the echo "ejecutando sftp", but nothing happens after this point.
#!/bin/sh
echo "ejecutando sftp"
folder="/aaa/bbb"
file="xxx.PDF"
sftp UserXX#nnn.nn.n.nn << EOF
cd $folder
get $file test.pdf
EOF
exec returns only the last line from the command output. If you want to capture entire output, use proc_open. See this answer, for instance.
you have to give the full path to file
and use this 2>&1 and know the error
try something like this
$comando = "sh pathTofile/location/ftpgesdoc.sh";
if(exec("$comando 2>&1", $output, $return_var))
{
print_r($output);
echo "<br>";
print_r($return_var);
}
I'm trying to list running services on a windows server via php. Therefore I'm using shell_exec with winexe.
My script:
$cmd = "winexe --interactive=0 --user='***' --password='***' //192.168.***.** \"net start\"";
$output = shell_exec($cmd);
echo $output;
Unfortunately on execution the page loads forever with no result. The command works on the command-line (Debian).
Anyone an idea?
Thanks in advance.
Save $cmd with correct format into a new bash file. Set cmd value for call this file. Remember set execution perms to this file.
Check if your apache user has perms for exec winexe
===
Try to launch
cat </dev/null | winexe --interactive=0 --ostype=1 --user=...