Php PDO array in json - php

Question

Her I have this code:
foreach($dates as $date){
$result = $conn->prepare("SELECT naziv, vrednost FROM track_aktivnosti WHERE id_akt = :id_akt AND datum = :datum");
$result->execute(array(':id_akt' => '22', ':datum' => $date['datum']));
foreach($result as $r) {
$m = array();
$m[] = $date['datum'].array('v' => (int) $r['vrednost']);
$rows1[] = array('c' => $m);
}
$table['rows'] = $rows1;
}
And I get: rows":[{"c":["2013-04-01Array"]},{"c":["2013-04-01Array"]},
How to show data instead 'Array' in JSON ?

Answer 1

$m[] = $date['datum'].array('v' => (int) $r['vrednost']);
This line performs a string concatenation, which implicitly transforms the latter array to a string, which results in the Array output.
Probably you mean something more in the line of
$m[] = array( $date['datum'], array('v' => (int) $r['vrednost']) );
or something similar. To be sure you would have to give us an example of the output you actually want to see, but I think the string concatenation at the given point is wrong in any case.
Edit
After your comment, I guess you want this:
$rows1 = array();
foreach($dates as $date){
$result = $conn->prepare("SELECT naziv, vrednost FROM track_aktivnosti WHERE id_akt = :id_akt AND datum = :datum");
$result->execute(array(':id_akt' => '22', ':datum' => $date['datum']));
$m = array( array( 'v' => $date['datum'] ) );
foreach($result as $r) {
$m[] = array('v' => (int) $r['vrednost']);
}
$rows1[] = array('c' => $m);
$table['rows'] = $rows1;
}
If correct, your ordering was completely off. You want to init a new $m for each resultset (== for each date), fill it with the date first, add all data from the database and the push it to your result array.
after your