I tried to count using following-
include 'db_login';
$sql = "(SELECT * , COUNT(*) FROM `table1`
WHERE `ADVERTISERCATEGORY` LIKE '%something%'
GROUP BY `MANUFACTURER` ORDER BY COUNT DESC )";
$row = mysql_fetch_array($sql);
$total = $row[0];
echo "Total rows: " . $total;
but i got following error message-
Warning: mysql_fetch_array() expects parameter 1 to be resource,
string given in /home/content/43/10130843/html/fashion_test.php on line 169
i am learning php/mysql therefore i need help.
thanks
You haven't called mysql_query(), so you can't fetch the array yet...
$sql = "SELECT * , COUNT(*) FROM `table1`
WHERE `ADVERTISERCATEGORY` LIKE '%something%'
GROUP BY `MANUFACTURER` ORDER BY COUNT(*) DESC ";
$query = mysql_query($sql) or die(mysql_error()); // exit on error
$row = mysql_fetch_array($query);
Note: mysql_query() and the rest of the mysql_* library have been deprecated for some time, you should make the move to paramterized queries with mysqli_* or PDO while you're in the development phase.
Related
i'm trying to use like in mysql from php and i write this code
$query = mysqli_query($connection, "SELECT * FROM items order by create_at desc where content LIKE '" . $content . "%'")
or die(mysqli_error($connection));
but it says there is an error in my syntax it says like this
You have an error in your SQL syntax; check the manual that
corresponds to your MariaDB server version for the right syntax to use
near 'where content LIKE 'c%'' at line 1
Order BY clause always come in the end, use WHERE clause first and then use ORDER BY
Solution would be this :
SELECT * FROM items where content LIKE 'YourVariable%' ORDER BY create_at DESC
Your PHP code should be:
$query = "SELECT * FROM items where content LIKE '" . $content . "%' order by create_at desc";
$result = mysqli_query($connection, $query) or die(mysqli_error($connection));
Query clauses sequence should be :
Select
From
join
where
group by
order by
limit
$query = mysqli_query($connection, "SELECT * FROM items order by create_at desc where content LIKE '%.$content.%'") or die(mysqli_error($connection));
I am new to PHP PDO and trying to use named placeholder at the place of ORDER BY ASC. Sometime in simple query page this run very successfully but unable to run in the following query:
PHP CODE IS:
$price_sort = "ASC";
$keyword = "samsung glaxy";
$limit = 0;
$query = $db->prepare("SELECT *, MATCH(title) against (:keyword) as 'relevence'
FROM view_store_items_grid
WHERE MATCH(title) against(:keyword)
ORDER BY relevence DESC, price :order
LIMIT :limit,25");
$query->bindValue(":keyword",$keyword);
$query->bindValue(":order",$price_sort);
$query->bindValue(":limit", $limit, PDO::PARAM_INT);
$query->execute();
When I remove placeholder :order with ASC this run and gives result but when I use this placeholder, I get empty result.
For Fetching data or to show fetched result I am using
while ($row = $query->fetch(PDO::FETCH_ASSOC)) :
extract($row);
echo "$name";
endwhile;
What I am doing wrong and How I can use many named placeholder in query at different places?
You should not bind ASC/DESC in prepared statement. Parameters are automatically quoted, and ASC/DESC shouldn't be quoted. this is the same reason that table and column names can't be parameters.
Instead you can do like that
$sql_query = "SELECT *, MATCH(title) against (:keyword) as 'relevence'
FROM view_store_items_grid
WHERE MATCH(title) against(:keyword)
ORDER BY relevence DESC, price "
if($price_order == 'ASC'){
$sql_query .= " ASC "
}else{
$sql_query .= " DESC "
}
$sql_query .= " LIMIT :limit,25 "
$query = $db->prepare($sql_query);
Refer How bindValue in LIMIT
Refer pdo binding asc/desc order dynamically
Also do not try to use the same named parameter twice in a single SQL statement, for example
<?php
$sql = 'SELECT * FROM some_table WHERE some_value > :value OR some_value < :value';
$stmt = $dbh->prepare($sql);
$stmt->execute( array( ':value' => 3 ) );
?>
...this will return no rows and no error -- you must use each parameter once and only once. Apparently this is expected behavior (according to this bug report: http://bugs.php.net/bug.php?id=33886) because of portability issues.
This one solved this question by replacing the price_sort variable value with price ASC and removing the price before the placehoder :order
as:
$price_sort = "price ASC";
and the query is as:
$query = $db->prepare("SELECT *, MATCH(title) against (:keyword) as 'relevence'
FROM view_store_items_grid
WHERE MATCH(title) against(:keyword)
ORDER BY relevence DESC, :order
LIMIT :limit,25");
this solved my question with the help of answer of #tamil
Thank you
I have a problem with PHP 5, I do a while for the last results of my table like this :
while($news = mysql_fetch_assoc("SELECT * FROM acts ORDER BY id DESC LIMIT 0,5"))
But I receive the following message
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in
That's because you are using it wrong, you shouldn't pass the query to the mysql_fetch_assoc function but:
$sql = "SELECT * FROM acts ORDER BY id DESC LIMIT 0,5";
$result = mysql_query($sql,$con);
while($news = mysql_fetch_assoc($result))
{
// do something
}
you should pass a resultset to mysql_fetch_assoc(), not a query.
while($news = mysql_fetch_assoc(mysql_query("SELECT * FROM acts ORDER BY id DESC LIMIT 0,5",$con)));
I created a table that contains message, sender, to, time I want group by sender and order by time this is my code
$query= mysql_query("SELECT * FROM `table` ORDER BY `time` GROUP BY `sender`")or die(mysql_error());
while($arr = mysql_fetch_array($query)){
$num = mysql_num_rows($query);
$msg = $arr ['message'];
echo '</br>';
echo $msg;
}
that shows me this error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP BYsender' at line 1
So how to fix that problem?
Thanks
Klaus
Note your precedence. After the results have been grouped , it should be ordered.
"SELECT * FROM `table` GROUP BY `sender` ORDER BY `time`"
try this code
$query= mysql_query("SELECT * FROM `table` GROUP BY `sender` ORDER BY `time` ")or die(mysql_error());
// ^^--will be before order
$num = mysql_num_rows($query); // out of the while loop
while($arr = mysql_fetch_array($query)){
$msg = $arr['message'].'<br />';
// ^^--remove space here
echo $msg;
}
how to use self-joins to get the max/min/something-n rows per group.
In your situation, it can be applied to the effect you want like so:
SELECT * FROM
(SELECT group_id, MAX(`yourdate`) AS yourdate FROM tbl_name GROUP BY group_id)
AS x JOIN tbl_name USING (`group_id`,yourdate);
I'm not sure exactly how to explain what the query does, however the problem isn't entirely with how it's set up, because it does work, in another instance, when I use it as an array, however it's not working when I use it with mysql_fetch_assoc(), so here is what my original query is(not the one im having trouble with):
SELECT * FROM
(SELECT * FROM comments
WHERE postID='$id' AND state='0'
ORDER BY id DESC LIMIT 3
) t ORDER BY id ASC
what this does is selects the last 3 comments on a post, then orders them in another way (so they show up in the correct order, old to new) Now this is the query for echoing out the array of comments directly.
But now what I want to do, is to just get the first id out of the 3 comments.
here's what I have tried to do (and by the way, this query DOES work, when i replace my previous query to echo out the results in an array, but i need to get just the id for use, i don't want an array):
$previousIDq = mysql_fetch_assoc(mysql_query("
SELECT * FROM
(SELECT * FROM comments
WHERE postID='$id' AND state='0'
ORDER BY id DESC LIMIT 3
) t ORDER BY id ASC LIMIT 1"));
$previousID = $previousIDq['id']; //this doesn't return the id as I want it to.
Your problem may be that there are no matching rows.
Also, I think you could also improve your query to this:
SELECT * FROM comments WHERE postID='$id' AND state='0' ORDER BY id DESC LIMIT 2,1
But as others say, use PDO or MySQLi, and with prepared statements. And don't SELECT * ever.
try a var_dump($previousID) to see what you get
It is probably giving you back an object, and you need to get your id from that object
You script is too condensened for error handling, let alone debugging
$mysql = mysql_connect(...
$query = "
SELECT * FROM
(SELECT * FROM comments
WHERE postID='$id' AND state='0'
ORDER BY id DESC LIMIT 3
) t ORDER BY id ASC LIMIT 1
";
$result = mysql_query($query, $mysql);
if ( !$result ) { // query failed
die('<pre>'.htmlspecialchars(mysql_error($mysql)).'</pre><pre>'.htmlspecialchars($query).'</pre>');
}
$previousIDq = mysql_fetch_assoc($result);
if ( !$previousIDq ) {
die('empty result set');
}
else {
$previousID = $previousIDq['id'];
}
You need to separate your code to be able to debug
$query = "SELECT * FROM
(SELECT * FROM comments
WHERE postID='$id' AND state='0'
ORDER BY id DESC LIMIT 3
) t ORDER BY id ASC LIMIT 1";
$result = mysql_query($query);
echo mysql_error(); //what eror comes out here
while($previousIDq = mysql_fetch_assoc($result))
{
print ($previousIDq['id']);
}
NOTE: mysql_* is depreciated, upgrade to mysqli or PDO
Please stop using mysql_ functions to write new code, it is being deprecated. Use mysqli_ or PDO functions (mysqli below).
Bind your parameters to prevent SQL injection
Always use a column list (don't use SELECT *)
If you're returning > 1 row, use a while loop
mysqli_ solution
$link = mysqli_connect("localhost", "user_name", "password", "stock");
if (mysqli_connect_error()) {
die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
}
$stmt = mysqli_prepare($link, "SELECT t.id FROM
(SELECT id FROM comments
WHERE postID = ? AND state = 0
ORDER BY id DESC
LIMIT 3) t
ORDER BY id ASC");
mysqli_bind_param($stmt, 's', $id) or die(mysqli_error($dbh));
$result = mysqli_stmt_execute($stmt) or die(mysqli_error($link));
while($row = mysqli_fetch_assoc($result)) {
echo $row[id];
}
mysqli_close($link);
mysql_ solution
$stmt = "SELECT t.id FROM
(SELECT id FROM comments
WHERE postID = $id AND state = 0
ORDER BY id DESC
LIMIT 3) t
ORDER BY id ASC";
$result = mysql_query($stmt) or die(mysql_error());
$row = mysql_fetch_assoc($result);
while($row = mysql_fetch_assoc($result)) {
echo $row[id];
}