passing variable from a href to pop up box through php - php

Question

after i click on this a href, it ll pop out a form and i trying to pass a variable to the pop up form. This is in a while loop.
while($row = mysql_fetch_array($result))
{
$id=$row['file_id'];
echo '<span class=right>[edit]
}
This is the pop up form code
<?php
$con=mysql_connect("localhost","root","");
mysql_select_db("isiti");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if (isset($_GET["id"]))
{
$id =$_GET["id"];
}
$result = mysql_query("SELECT * FROM publication where file_id='$id'");
$row1 = mysql_fetch_array($result);
$title=$row1['title'];
$author=$row1['author'];
$year=$row1['year'];
$abstract=$row1['abstract'];
if(!empty($_SESSION['username']))
{
echo'<div class="popup">';
echo'<form method="POST" action="public_edit.php" enctype="multipart/form-data">';
echo'<div>';
echo'<label for="citation">Title</label>';
echo'<input style="width:100%;" type="text" name="title" id="title" value="'.$title.'">';
echo'</div>';
echo'<div>';
echo'<label for="citation">Author</label>';
echo'<input style="width:100%;" type="text" name="author" id="author" value="'.$author.'">';
echo'</div>';
echo'<div>';
echo'<label for="citation">Year</label>';
echo'<input style="width:100%;" type="year" name="year" id="year" value="'.$year.'">';
echo'</div>';
echo'<div>';
echo'<label for="abstract">Abstract</label>';
echo'<textarea name="abstract" id="abstract" size="5000">'.$abstract.'</textarea>';
echo'</div>';
echo'<p>Rechoose your file here</p>';
echo'<input type="hidden" name="MAX_FILE_SIZE" value="2000000">';
echo'<input name="userfile" type="file" id="userfile"> ';
echo'<br/> ';
echo'<input name="submit" type="submit" value="Upload" style="width: 150px">';
echo'<a class="close" href="#close"></a>';
echo'</form>';
echo'</div>';
}
The problem i faced is that it do not pass the right id. no matter what link i click it show the data from the first id.
Thanks for helping me .

Answer 1

You need to pass the id as get parameter when calling that pop up. Replace with this the echo statement in first code
echo '<span class=right>[edit]';

Answer 2

$_GET works well for data sent by a query string. In this case, you are sending the data as the id of href tag.
so try attaching id to your query string.
echo '<span class=right>[edit]